Convert web.xml 2.5 project to springboot java config











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I am trying to convert web.xml to java configuration and i am unable to do so as i remove web.xml, i get an error in tomcat as web.xml not found. how do i go with this?



<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>sampleproject</display-name>
<welcome-file-list>
<welcome-file>welcomPage</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring-web</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-
class>
<init-param>
<param-name>contextClass</param-name>
<param-value>

org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>com.example.sampleproject.config</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix1/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix2/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>60</session-timeout>
</session-config>











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  • You didn't give any response
    – Avijit Barua
    Dec 6 at 10:22















up vote
-2
down vote

favorite












I am trying to convert web.xml to java configuration and i am unable to do so as i remove web.xml, i get an error in tomcat as web.xml not found. how do i go with this?



<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>sampleproject</display-name>
<welcome-file-list>
<welcome-file>welcomPage</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring-web</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-
class>
<init-param>
<param-name>contextClass</param-name>
<param-value>

org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>com.example.sampleproject.config</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix1/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix2/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>60</session-timeout>
</session-config>











share|improve this question






















  • You didn't give any response
    – Avijit Barua
    Dec 6 at 10:22













up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











I am trying to convert web.xml to java configuration and i am unable to do so as i remove web.xml, i get an error in tomcat as web.xml not found. how do i go with this?



<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>sampleproject</display-name>
<welcome-file-list>
<welcome-file>welcomPage</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring-web</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-
class>
<init-param>
<param-name>contextClass</param-name>
<param-value>

org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>com.example.sampleproject.config</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix1/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix2/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>60</session-timeout>
</session-config>











share|improve this question













I am trying to convert web.xml to java configuration and i am unable to do so as i remove web.xml, i get an error in tomcat as web.xml not found. how do i go with this?



<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>sampleproject</display-name>
<welcome-file-list>
<welcome-file>welcomPage</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring-web</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-
class>
<init-param>
<param-name>contextClass</param-name>
<param-value>

org.springframework.web.context.support.AnnotationConfigWebApplicationContext
</param-value>
</init-param>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>com.example.sampleproject.config</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix1/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring-web</servlet-name>
<url-pattern>/prefix2/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>60</session-timeout>
</session-config>








spring spring-boot web.xml






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asked Nov 22 at 5:07









Vaibhav Savala

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3112












  • You didn't give any response
    – Avijit Barua
    Dec 6 at 10:22


















  • You didn't give any response
    – Avijit Barua
    Dec 6 at 10:22
















You didn't give any response
– Avijit Barua
Dec 6 at 10:22




You didn't give any response
– Avijit Barua
Dec 6 at 10:22












1 Answer
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In spring MVC you need to do lots of stuff like configuring web.xml, dispatcher-servlet.xml etc... But in spring boot you don't need to configure this. Spring boot automatically handle this. You don't need to configure mapping. Just need to write controller. I think it will be better if you initialize a new spring boot project and do all the stuff according to your requirements. You can follow the link and this link. If you want to work with jsp follow this link.






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    up vote
    0
    down vote













    In spring MVC you need to do lots of stuff like configuring web.xml, dispatcher-servlet.xml etc... But in spring boot you don't need to configure this. Spring boot automatically handle this. You don't need to configure mapping. Just need to write controller. I think it will be better if you initialize a new spring boot project and do all the stuff according to your requirements. You can follow the link and this link. If you want to work with jsp follow this link.






    share|improve this answer

























      up vote
      0
      down vote













      In spring MVC you need to do lots of stuff like configuring web.xml, dispatcher-servlet.xml etc... But in spring boot you don't need to configure this. Spring boot automatically handle this. You don't need to configure mapping. Just need to write controller. I think it will be better if you initialize a new spring boot project and do all the stuff according to your requirements. You can follow the link and this link. If you want to work with jsp follow this link.






      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        In spring MVC you need to do lots of stuff like configuring web.xml, dispatcher-servlet.xml etc... But in spring boot you don't need to configure this. Spring boot automatically handle this. You don't need to configure mapping. Just need to write controller. I think it will be better if you initialize a new spring boot project and do all the stuff according to your requirements. You can follow the link and this link. If you want to work with jsp follow this link.






        share|improve this answer












        In spring MVC you need to do lots of stuff like configuring web.xml, dispatcher-servlet.xml etc... But in spring boot you don't need to configure this. Spring boot automatically handle this. You don't need to configure mapping. Just need to write controller. I think it will be better if you initialize a new spring boot project and do all the stuff according to your requirements. You can follow the link and this link. If you want to work with jsp follow this link.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 22 at 5:44









        Avijit Barua

        1,1791215




        1,1791215






























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