Girsanov's theorem and likelihood for random initial conditions












0












$begingroup$


Consider as an example the Stochastic Differential Equation
$$
text{d}Y(t) = -kappa Y(t) text{d}t + sigma text{d} B(t), qquad t geq 0
$$



where $B(t)$ is a standard Brownian motion, $kappa$ and $sigma$ are
positive constants. If $Y(0) = 0$, Girsanov's theorem tells that the
distribution of the process $Y(t)$ is absolutely continuous
w.r.t. that of a standard Brownian. If $sigma$ is known, this theorem
defines a likelihood function for an (ideal) continuously observed
path $t in [0, , T]$ with $T >0$. A maximum
likelihood estimator for $kappa$ can be consequently be derived as
described by Phillips and
Yu.



Now assume that $Y(t)$ is stationary, which implies that $Y(0)$ is
centred normal with variance $sigma^2/(2 kappa)$. Can we still then
use Girsanov's theorem to define a likelihood function? If yes, what
relations exist between this infill or continuous record
likelihood and the simply defined likelihood function arising from
partial observations $Y(t_i)$ when the instants $t_i$ tend to fill the
fixed interval $[0,,T]$?



More generally how can we cope with random initial conditions for a
continuously observed process having a state-space representation? As
a major difference with the example above, the initial state will no
longer be observed.










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$endgroup$

















    0












    $begingroup$


    Consider as an example the Stochastic Differential Equation
    $$
    text{d}Y(t) = -kappa Y(t) text{d}t + sigma text{d} B(t), qquad t geq 0
    $$



    where $B(t)$ is a standard Brownian motion, $kappa$ and $sigma$ are
    positive constants. If $Y(0) = 0$, Girsanov's theorem tells that the
    distribution of the process $Y(t)$ is absolutely continuous
    w.r.t. that of a standard Brownian. If $sigma$ is known, this theorem
    defines a likelihood function for an (ideal) continuously observed
    path $t in [0, , T]$ with $T >0$. A maximum
    likelihood estimator for $kappa$ can be consequently be derived as
    described by Phillips and
    Yu.



    Now assume that $Y(t)$ is stationary, which implies that $Y(0)$ is
    centred normal with variance $sigma^2/(2 kappa)$. Can we still then
    use Girsanov's theorem to define a likelihood function? If yes, what
    relations exist between this infill or continuous record
    likelihood and the simply defined likelihood function arising from
    partial observations $Y(t_i)$ when the instants $t_i$ tend to fill the
    fixed interval $[0,,T]$?



    More generally how can we cope with random initial conditions for a
    continuously observed process having a state-space representation? As
    a major difference with the example above, the initial state will no
    longer be observed.










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Consider as an example the Stochastic Differential Equation
      $$
      text{d}Y(t) = -kappa Y(t) text{d}t + sigma text{d} B(t), qquad t geq 0
      $$



      where $B(t)$ is a standard Brownian motion, $kappa$ and $sigma$ are
      positive constants. If $Y(0) = 0$, Girsanov's theorem tells that the
      distribution of the process $Y(t)$ is absolutely continuous
      w.r.t. that of a standard Brownian. If $sigma$ is known, this theorem
      defines a likelihood function for an (ideal) continuously observed
      path $t in [0, , T]$ with $T >0$. A maximum
      likelihood estimator for $kappa$ can be consequently be derived as
      described by Phillips and
      Yu.



      Now assume that $Y(t)$ is stationary, which implies that $Y(0)$ is
      centred normal with variance $sigma^2/(2 kappa)$. Can we still then
      use Girsanov's theorem to define a likelihood function? If yes, what
      relations exist between this infill or continuous record
      likelihood and the simply defined likelihood function arising from
      partial observations $Y(t_i)$ when the instants $t_i$ tend to fill the
      fixed interval $[0,,T]$?



      More generally how can we cope with random initial conditions for a
      continuously observed process having a state-space representation? As
      a major difference with the example above, the initial state will no
      longer be observed.










      share|cite|improve this question











      $endgroup$




      Consider as an example the Stochastic Differential Equation
      $$
      text{d}Y(t) = -kappa Y(t) text{d}t + sigma text{d} B(t), qquad t geq 0
      $$



      where $B(t)$ is a standard Brownian motion, $kappa$ and $sigma$ are
      positive constants. If $Y(0) = 0$, Girsanov's theorem tells that the
      distribution of the process $Y(t)$ is absolutely continuous
      w.r.t. that of a standard Brownian. If $sigma$ is known, this theorem
      defines a likelihood function for an (ideal) continuously observed
      path $t in [0, , T]$ with $T >0$. A maximum
      likelihood estimator for $kappa$ can be consequently be derived as
      described by Phillips and
      Yu.



      Now assume that $Y(t)$ is stationary, which implies that $Y(0)$ is
      centred normal with variance $sigma^2/(2 kappa)$. Can we still then
      use Girsanov's theorem to define a likelihood function? If yes, what
      relations exist between this infill or continuous record
      likelihood and the simply defined likelihood function arising from
      partial observations $Y(t_i)$ when the instants $t_i$ tend to fill the
      fixed interval $[0,,T]$?



      More generally how can we cope with random initial conditions for a
      continuously observed process having a state-space representation? As
      a major difference with the example above, the initial state will no
      longer be observed.







      probability stochastic-processes stochastic-calculus






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Dec 6 '18 at 18:44







      Yves

















      asked Dec 6 '18 at 10:42









      YvesYves

      596




      596






















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