Solve a linear problem using bounded variables method
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Consider the following $$min 3x_1+4x_2\ s.t. 4x_1+3x_2ge12 \ 3x_1+4x_2le12\ x_1,x_2ge0$$ Substitute the first restriction by $x_1le3$ and solve the LP by bounded variable method. Attempt We first standarize and then set in a table begin{array}{r|rrrrr|r} & x_1 & x_2 & x_3 & x_4 & \ hline z & -3 & -4 & 0 & 0 & & 0 \ hline x_3 & -4 & -3 & 1 & 0 & & -12 \ x_4 & 3 & 4 & 0 & 1 & & 12 end{array} From here we see that $theta_1=min{12/4}=3$ $theta_2=min{frac{-12-?}{-3}}=?$ and $u_2=?$ The bounded variable method requires an upper bound of $x_3$ but does not have. How will I find $theta_2$ ? $u_2?$ Could someone help...