Is this correct? $N(langle a, b rangle) = gcd(N(a), N(b))$
  
 
     
     
             
                 
 
 
         
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 Given a ring $R$ , not necessarily a principal ideal domain, and numbers $a, b in R$ , is the norm of the ideal $langle a, b rangle$  the greatest common divisor of the norms of the numbers $a$  and $b$ ?   For example, given that $N(3) = 9$  and $N(1 + sqrt{-5}) = 6$ , is $N(langle 3, 1 + sqrt{-5} rangle) = 3$ ? Or how about $N(3) = 9$  and $N(1 + sqrt{10}) = -9$ , so $N(langle 3, 1 + sqrt{10} rangle) = 3$  also?    Related question: Norm of an ideal      
 
         
             
                 algebraic-number-theory ideals 
             
         
 
     
         
             
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         asked Dec 4 '18 at 22:00 
     
     
         
     
     
         Bob Happ Bob Happ 
         
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