Is this correct? $N(langle a, b rangle) = gcd(N(a), N(b))$
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Given a ring $R$ , not necessarily a principal ideal domain, and numbers $a, b in R$ , is the norm of the ideal $langle a, b rangle$ the greatest common divisor of the norms of the numbers $a$ and $b$ ? For example, given that $N(3) = 9$ and $N(1 + sqrt{-5}) = 6$ , is $N(langle 3, 1 + sqrt{-5} rangle) = 3$ ? Or how about $N(3) = 9$ and $N(1 + sqrt{10}) = -9$ , so $N(langle 3, 1 + sqrt{10} rangle) = 3$ also? Related question: Norm of an ideal
algebraic-number-theory ideals
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asked Dec 4 '18 at 22:00
Bob Happ Bob Happ
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