Understanding ODE and phase portraits on Manifolds











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I'm studying on my own Dynamicals Systems and having difficulties to undersrtand ODE defined on a manifold $M$.



Firstly, let $X: Omega subset mathbb{R}^{n} rightarrow mathbb{R}^{n} $ a vector field and consider the equation



$dfrac{d varphi(t)}{dt}= X(varphi(t))$,



a solution for this ODE is a path $varphi(t): I subset mathbb{R} rightarrow Omega$, such that $frac{d varphi(t)}{dt}= X(varphi(t))$, for all $t in I$.



Then, I have the following doubts



1- If $M$ is a $m$-dimensional manifold $(mneq n)$, then, is the vector field defined by $X: M rightarrow TM$, which associes each $p in M$ to the vector $X(p) in T_{p}M$? This make sense for me, once that, the space $T_{p}M$ has more algebraic and topologic properties. However, take $M= S^{1}$ for example, for each $p in S^{1}$ the tangent space $T_{p}M$ is equal to the orthogonal complement of $p$, that is, $T_{p}M = [p]^{perp}$. How to construct a vector field with this property? How to construct vector fields for more general manifolds?



2- Has the solution $varphi(t)$ lie in the manifold $M$, for all $t$? If yes, then is every solution on $S^{1}$ "like" $(sin (pi t), cos(pi t))$?



3- How to draw phase portraits on manifolds? I would like to see examples of two vector fields $X,Y:S^{1}rightarrow TS^{1}*(?)*$, when $X$ and $Y$ are conjugated topologically and when they are not.



I would like to apologize if something pointed out here is too obvious or standart. Any help will be aprecciated.










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  • 1- is answered by studying the definition of $TM$. There is an intrinsic definition that works for abstract manifolds, and then you can compare it with the extrinsic tangent in the case of an embedded manifold, as in your $S^1$ example
    – Federico
    Nov 27 at 17:54










  • 2- the solution lies on $M$ by definition in the abstract setting. In the case of an embedded manifold and $X$ defined on the ambient space, the solution again lies on $M$ by the definition of $TM$: take for instance the implicit approach $M={f=0}$ and try differentiating $f(varphi(t))$
    – Federico
    Nov 27 at 17:59















up vote
0
down vote

favorite












I'm studying on my own Dynamicals Systems and having difficulties to undersrtand ODE defined on a manifold $M$.



Firstly, let $X: Omega subset mathbb{R}^{n} rightarrow mathbb{R}^{n} $ a vector field and consider the equation



$dfrac{d varphi(t)}{dt}= X(varphi(t))$,



a solution for this ODE is a path $varphi(t): I subset mathbb{R} rightarrow Omega$, such that $frac{d varphi(t)}{dt}= X(varphi(t))$, for all $t in I$.



Then, I have the following doubts



1- If $M$ is a $m$-dimensional manifold $(mneq n)$, then, is the vector field defined by $X: M rightarrow TM$, which associes each $p in M$ to the vector $X(p) in T_{p}M$? This make sense for me, once that, the space $T_{p}M$ has more algebraic and topologic properties. However, take $M= S^{1}$ for example, for each $p in S^{1}$ the tangent space $T_{p}M$ is equal to the orthogonal complement of $p$, that is, $T_{p}M = [p]^{perp}$. How to construct a vector field with this property? How to construct vector fields for more general manifolds?



2- Has the solution $varphi(t)$ lie in the manifold $M$, for all $t$? If yes, then is every solution on $S^{1}$ "like" $(sin (pi t), cos(pi t))$?



3- How to draw phase portraits on manifolds? I would like to see examples of two vector fields $X,Y:S^{1}rightarrow TS^{1}*(?)*$, when $X$ and $Y$ are conjugated topologically and when they are not.



I would like to apologize if something pointed out here is too obvious or standart. Any help will be aprecciated.










share|cite|improve this question
























  • 1- is answered by studying the definition of $TM$. There is an intrinsic definition that works for abstract manifolds, and then you can compare it with the extrinsic tangent in the case of an embedded manifold, as in your $S^1$ example
    – Federico
    Nov 27 at 17:54










  • 2- the solution lies on $M$ by definition in the abstract setting. In the case of an embedded manifold and $X$ defined on the ambient space, the solution again lies on $M$ by the definition of $TM$: take for instance the implicit approach $M={f=0}$ and try differentiating $f(varphi(t))$
    – Federico
    Nov 27 at 17:59













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm studying on my own Dynamicals Systems and having difficulties to undersrtand ODE defined on a manifold $M$.



Firstly, let $X: Omega subset mathbb{R}^{n} rightarrow mathbb{R}^{n} $ a vector field and consider the equation



$dfrac{d varphi(t)}{dt}= X(varphi(t))$,



a solution for this ODE is a path $varphi(t): I subset mathbb{R} rightarrow Omega$, such that $frac{d varphi(t)}{dt}= X(varphi(t))$, for all $t in I$.



Then, I have the following doubts



1- If $M$ is a $m$-dimensional manifold $(mneq n)$, then, is the vector field defined by $X: M rightarrow TM$, which associes each $p in M$ to the vector $X(p) in T_{p}M$? This make sense for me, once that, the space $T_{p}M$ has more algebraic and topologic properties. However, take $M= S^{1}$ for example, for each $p in S^{1}$ the tangent space $T_{p}M$ is equal to the orthogonal complement of $p$, that is, $T_{p}M = [p]^{perp}$. How to construct a vector field with this property? How to construct vector fields for more general manifolds?



2- Has the solution $varphi(t)$ lie in the manifold $M$, for all $t$? If yes, then is every solution on $S^{1}$ "like" $(sin (pi t), cos(pi t))$?



3- How to draw phase portraits on manifolds? I would like to see examples of two vector fields $X,Y:S^{1}rightarrow TS^{1}*(?)*$, when $X$ and $Y$ are conjugated topologically and when they are not.



I would like to apologize if something pointed out here is too obvious or standart. Any help will be aprecciated.










share|cite|improve this question















I'm studying on my own Dynamicals Systems and having difficulties to undersrtand ODE defined on a manifold $M$.



Firstly, let $X: Omega subset mathbb{R}^{n} rightarrow mathbb{R}^{n} $ a vector field and consider the equation



$dfrac{d varphi(t)}{dt}= X(varphi(t))$,



a solution for this ODE is a path $varphi(t): I subset mathbb{R} rightarrow Omega$, such that $frac{d varphi(t)}{dt}= X(varphi(t))$, for all $t in I$.



Then, I have the following doubts



1- If $M$ is a $m$-dimensional manifold $(mneq n)$, then, is the vector field defined by $X: M rightarrow TM$, which associes each $p in M$ to the vector $X(p) in T_{p}M$? This make sense for me, once that, the space $T_{p}M$ has more algebraic and topologic properties. However, take $M= S^{1}$ for example, for each $p in S^{1}$ the tangent space $T_{p}M$ is equal to the orthogonal complement of $p$, that is, $T_{p}M = [p]^{perp}$. How to construct a vector field with this property? How to construct vector fields for more general manifolds?



2- Has the solution $varphi(t)$ lie in the manifold $M$, for all $t$? If yes, then is every solution on $S^{1}$ "like" $(sin (pi t), cos(pi t))$?



3- How to draw phase portraits on manifolds? I would like to see examples of two vector fields $X,Y:S^{1}rightarrow TS^{1}*(?)*$, when $X$ and $Y$ are conjugated topologically and when they are not.



I would like to apologize if something pointed out here is too obvious or standart. Any help will be aprecciated.







differential-equations dynamical-systems vector-fields






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share|cite|improve this question













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edited Nov 27 at 17:52









Federico

4,193512




4,193512










asked Nov 27 at 17:46









BBVM

17112




17112












  • 1- is answered by studying the definition of $TM$. There is an intrinsic definition that works for abstract manifolds, and then you can compare it with the extrinsic tangent in the case of an embedded manifold, as in your $S^1$ example
    – Federico
    Nov 27 at 17:54










  • 2- the solution lies on $M$ by definition in the abstract setting. In the case of an embedded manifold and $X$ defined on the ambient space, the solution again lies on $M$ by the definition of $TM$: take for instance the implicit approach $M={f=0}$ and try differentiating $f(varphi(t))$
    – Federico
    Nov 27 at 17:59


















  • 1- is answered by studying the definition of $TM$. There is an intrinsic definition that works for abstract manifolds, and then you can compare it with the extrinsic tangent in the case of an embedded manifold, as in your $S^1$ example
    – Federico
    Nov 27 at 17:54










  • 2- the solution lies on $M$ by definition in the abstract setting. In the case of an embedded manifold and $X$ defined on the ambient space, the solution again lies on $M$ by the definition of $TM$: take for instance the implicit approach $M={f=0}$ and try differentiating $f(varphi(t))$
    – Federico
    Nov 27 at 17:59
















1- is answered by studying the definition of $TM$. There is an intrinsic definition that works for abstract manifolds, and then you can compare it with the extrinsic tangent in the case of an embedded manifold, as in your $S^1$ example
– Federico
Nov 27 at 17:54




1- is answered by studying the definition of $TM$. There is an intrinsic definition that works for abstract manifolds, and then you can compare it with the extrinsic tangent in the case of an embedded manifold, as in your $S^1$ example
– Federico
Nov 27 at 17:54












2- the solution lies on $M$ by definition in the abstract setting. In the case of an embedded manifold and $X$ defined on the ambient space, the solution again lies on $M$ by the definition of $TM$: take for instance the implicit approach $M={f=0}$ and try differentiating $f(varphi(t))$
– Federico
Nov 27 at 17:59




2- the solution lies on $M$ by definition in the abstract setting. In the case of an embedded manifold and $X$ defined on the ambient space, the solution again lies on $M$ by the definition of $TM$: take for instance the implicit approach $M={f=0}$ and try differentiating $f(varphi(t))$
– Federico
Nov 27 at 17:59















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