Getting wrong data with regex
up vote
1
down vote
favorite
I'm facing an issue here. Python version 3.7.
https://regex101.com/r/WVxEKM/3
As you can see on regex site, my regex is working great, however, when I try to read the strings with python, I only get the first part, meaning, no values after comma.
Here's my code:
part_number = str(row)
partn = re.search(r"([a-zA-Z0-9 ,-]+)", part_number)
print(partn.group(0))
This is what partn.group(0) is printing:
FMC2H-OHC-100018-00
I need to get the string as regex, with comma and value:
FMC2H-OHC-100018-00, 2
Is it my regex wrong?. What is happening with commas and values?
ROW Values
Here are the row values converted to string, the data retrieve from my db also include parentheses and quotes:
('FMC2H-OHC-100018-00', 2)
('FMC2H-OHC-100027-00', 0)
python regex python-3.x parsing
edited Nov 22 at 3:45
martineau
65.3k987176
asked Nov 21 at 23:43
Javier Ramirez
384
add a comment |
up vote
1
down vote
favorite
I'm facing an issue here. Python version 3.7.
https://regex101.com/r/WVxEKM/3
As you can see on regex site, my regex is working great, however, when I try to read the strings with python, I only get the first part, meaning, no values after comma.
Here's my code:
part_number = str(row)
partn = re.search(r"([a-zA-Z0-9 ,-]+)", part_number)
print(partn.group(0))
This is what partn.group(0) is printing:
FMC2H-OHC-100018-00
I need to get the string as regex, with comma and value:
FMC2H-OHC-100018-00, 2
Is it my regex wrong?. What is happening with commas and values?
ROW Values
Here are the row values converted to string, the data retrieve from my db also include parentheses and quotes:
('FMC2H-OHC-100018-00', 2)
('FMC2H-OHC-100027-00', 0)
python regex python-3.x parsing
edited Nov 22 at 3:45
martineau
65.3k987176
asked Nov 21 at 23:43
Javier Ramirez
384
I have read that group(0) returns complete match, so what am I doing wrong?
– Javier Ramirez
Nov 21 at 23:45
Please copy enough of your input into the question to locally reproduce your results.
– usr2564301
Nov 21 at 23:46
(w{5}-w{3}-d{6}-d{2}, d+)?
– Dev
Nov 21 at 23:58
Your character class isn't matching the single quotes, by the way.
– Dev
Nov 21 at 23:58
Edit the question to include the value ofpart_number.
– John Gordon
Nov 22 at 0:01
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I'm facing an issue here. Python version 3.7.
https://regex101.com/r/WVxEKM/3
As you can see on regex site, my regex is working great, however, when I try to read the strings with python, I only get the first part, meaning, no values after comma.
Here's my code:
part_number = str(row)
partn = re.search(r"([a-zA-Z0-9 ,-]+)", part_number)
print(partn.group(0))
This is what partn.group(0) is printing:
FMC2H-OHC-100018-00
I need to get the string as regex, with comma and value:
FMC2H-OHC-100018-00, 2
Is it my regex wrong?. What is happening with commas and values?
ROW Values
Here are the row values converted to string, the data retrieve from my db also include parentheses and quotes:
('FMC2H-OHC-100018-00', 2)
('FMC2H-OHC-100027-00', 0)
python regex python-3.x parsing
edited Nov 22 at 3:45
martineau
65.3k987176
asked Nov 21 at 23:43
Javier Ramirez
384
I'm facing an issue here. Python version 3.7.
https://regex101.com/r/WVxEKM/3
As you can see on regex site, my regex is working great, however, when I try to read the strings with python, I only get the first part, meaning, no values after comma.
Here's my code:
part_number = str(row)
partn = re.search(r"([a-zA-Z0-9 ,-]+)", part_number)
print(partn.group(0))
This is what partn.group(0) is printing:
FMC2H-OHC-100018-00
I need to get the string as regex, with comma and value:
FMC2H-OHC-100018-00, 2
Is it my regex wrong?. What is happening with commas and values?
ROW Values
Here are the row values converted to string, the data retrieve from my db also include parentheses and quotes:
('FMC2H-OHC-100018-00', 2)
('FMC2H-OHC-100027-00', 0)
python regex python-3.x parsing
python regex python-3.x parsing
edited Nov 22 at 3:45
martineau
65.3k987176
asked Nov 21 at 23:43
Javier Ramirez
384
edited Nov 22 at 3:45
martineau
65.3k987176
asked Nov 21 at 23:43
Javier Ramirez
384
edited Nov 22 at 3:45
martineau
65.3k987176
edited Nov 22 at 3:45
martineau
65.3k987176
edited Nov 22 at 3:45
martineau
65.3k987176
65.3k987176
asked Nov 21 at 23:43
Javier Ramirez
384
asked Nov 21 at 23:43
Javier Ramirez
384
asked Nov 21 at 23:43
Javier Ramirez
384
384
I have read that group(0) returns complete match, so what am I doing wrong?
– Javier Ramirez
Nov 21 at 23:45
Please copy enough of your input into the question to locally reproduce your results.
– usr2564301
Nov 21 at 23:46
(w{5}-w{3}-d{6}-d{2}, d+)?
– Dev
Nov 21 at 23:58
Your character class isn't matching the single quotes, by the way.
– Dev
Nov 21 at 23:58
Edit the question to include the value ofpart_number.
– John Gordon
Nov 22 at 0:01
add a comment |
I have read that group(0) returns complete match, so what am I doing wrong?
– Javier Ramirez
Nov 21 at 23:45
Please copy enough of your input into the question to locally reproduce your results.
– usr2564301
Nov 21 at 23:46
(w{5}-w{3}-d{6}-d{2}, d+)?
– Dev
Nov 21 at 23:58
Your character class isn't matching the single quotes, by the way.
– Dev
Nov 21 at 23:58
Edit the question to include the value ofpart_number.
– John Gordon
Nov 22 at 0:01
I have read that group(0) returns complete match, so what am I doing wrong?
– Javier Ramirez
Nov 21 at 23:45
I have read that group(0) returns complete match, so what am I doing wrong?
– Javier Ramirez
Nov 21 at 23:45
Please copy enough of your input into the question to locally reproduce your results.
– usr2564301
Nov 21 at 23:46
Please copy enough of your input into the question to locally reproduce your results.
– usr2564301
Nov 21 at 23:46
(w{5}-w{3}-d{6}-d{2}, d+)?– Dev
Nov 21 at 23:58
(w{5}-w{3}-d{6}-d{2}, d+)?– Dev
Nov 21 at 23:58
Your character class isn't matching the single quotes, by the way.
– Dev
Nov 21 at 23:58
Your character class isn't matching the single quotes, by the way.
– Dev
Nov 21 at 23:58
Edit the question to include the value of
part_number.– John Gordon
Nov 22 at 0:01
Edit the question to include the value of
part_number.– John Gordon
Nov 22 at 0:01
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
Your problem is that you didn't include the ' in your character group. So this regex matches for example FMC2H-OHC-100018-00 and , 2, but not both together. Also re.search stops searching after it finds the first match. So if you only want the first match, go with:
re.search(r"([w ',-]+)", part_number)
Where I changed A-Za-z0-9 to w, because it's shorter and more readable. If you want a list that matches all elements, go with:
re.findall(r"([w ',-]+)", part_number)
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
answered Nov 22 at 0:17
user8408080
1,040139
1
Personally, I'd use(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.
– Dev
Nov 22 at 0:20
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the';)
– user8408080
Nov 22 at 0:21
1
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...
– Dev
Nov 22 at 0:28
1
[wd]=w, butwis not equal to[A-Za-z0-9], in Python 3,wmatches any Unicode letter, digit,_and some diacritics.
– Wiktor Stribiżew
Nov 22 at 9:08
add a comment |
up vote
1
down vote
I don't think the you need to convert the row values to string and then try to parse the result with a regex. The clue was when you said in your update that "Here are the row values converted to string" implying that they're in some other format initially—because the result looks they're actually tuples of two values, a string and an integer.
If that's correct, then you can avoid converting them to strings and then trying to parse it with a regex, because you can get the string you want simply by using the relatively simple built-in string formatting capabilities Python has to do it.
Here's what I mean:
# Raw row data retrieved from database.
rows = [('FMC2H-OHC-100018-00', 2),
('FMC2H-OHC-100027-00', 0),
('FMC2H-OHC-100033-00', 0),
('FMC2H-OHC-100032-00', 20),
('FMC2H-OHC-100017-00', 16)]
for row in rows:
result = '{}, {}'.format(*row) # Convert data in row to a formatted string.
print(result)
Output:
FMC2H-OHC-100018-00, 2
FMC2H-OHC-100027-00, 0
FMC2H-OHC-100033-00, 0
FMC2H-OHC-100032-00, 20
FMC2H-OHC-100017-00, 16
answered Nov 22 at 0:42
martineau
65.3k987176
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Your problem is that you didn't include the ' in your character group. So this regex matches for example FMC2H-OHC-100018-00 and , 2, but not both together. Also re.search stops searching after it finds the first match. So if you only want the first match, go with:
re.search(r"([w ',-]+)", part_number)
Where I changed A-Za-z0-9 to w, because it's shorter and more readable. If you want a list that matches all elements, go with:
re.findall(r"([w ',-]+)", part_number)
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
answered Nov 22 at 0:17
user8408080
1,040139
1
Personally, I'd use(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.
– Dev
Nov 22 at 0:20
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the';)
– user8408080
Nov 22 at 0:21
1
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...
– Dev
Nov 22 at 0:28
1
[wd]=w, butwis not equal to[A-Za-z0-9], in Python 3,wmatches any Unicode letter, digit,_and some diacritics.
– Wiktor Stribiżew
Nov 22 at 9:08
add a comment |
up vote
1
down vote
accepted
Your problem is that you didn't include the ' in your character group. So this regex matches for example FMC2H-OHC-100018-00 and , 2, but not both together. Also re.search stops searching after it finds the first match. So if you only want the first match, go with:
re.search(r"([w ',-]+)", part_number)
Where I changed A-Za-z0-9 to w, because it's shorter and more readable. If you want a list that matches all elements, go with:
re.findall(r"([w ',-]+)", part_number)
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
answered Nov 22 at 0:17
user8408080
1,040139
1
Personally, I'd use(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.
– Dev
Nov 22 at 0:20
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the';)
– user8408080
Nov 22 at 0:21
1
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...
– Dev
Nov 22 at 0:28
1
[wd]=w, butwis not equal to[A-Za-z0-9], in Python 3,wmatches any Unicode letter, digit,_and some diacritics.
– Wiktor Stribiżew
Nov 22 at 9:08
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Your problem is that you didn't include the ' in your character group. So this regex matches for example FMC2H-OHC-100018-00 and , 2, but not both together. Also re.search stops searching after it finds the first match. So if you only want the first match, go with:
re.search(r"([w ',-]+)", part_number)
Where I changed A-Za-z0-9 to w, because it's shorter and more readable. If you want a list that matches all elements, go with:
re.findall(r"([w ',-]+)", part_number)
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
answered Nov 22 at 0:17
user8408080
1,040139
Your problem is that you didn't include the ' in your character group. So this regex matches for example FMC2H-OHC-100018-00 and , 2, but not both together. Also re.search stops searching after it finds the first match. So if you only want the first match, go with:
re.search(r"([w ',-]+)", part_number)
Where I changed A-Za-z0-9 to w, because it's shorter and more readable. If you want a list that matches all elements, go with:
re.findall(r"([w ',-]+)", part_number)
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
answered Nov 22 at 0:17
user8408080
1,040139
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
edited Nov 22 at 9:08
Wiktor Stribiżew
305k16124201
305k16124201
answered Nov 22 at 0:17
user8408080
1,040139
answered Nov 22 at 0:17
user8408080
1,040139
answered Nov 22 at 0:17
user8408080
1,040139
1,040139
1
Personally, I'd use(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.
– Dev
Nov 22 at 0:20
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the';)
– user8408080
Nov 22 at 0:21
1
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...
– Dev
Nov 22 at 0:28
1
[wd]=w, butwis not equal to[A-Za-z0-9], in Python 3,wmatches any Unicode letter, digit,_and some diacritics.
– Wiktor Stribiżew
Nov 22 at 9:08
add a comment |
1
Personally, I'd use(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.
– Dev
Nov 22 at 0:20
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the';)
– user8408080
Nov 22 at 0:21
1
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...
– Dev
Nov 22 at 0:28
1
[wd]=w, butwis not equal to[A-Za-z0-9], in Python 3,wmatches any Unicode letter, digit,_and some diacritics.
– Wiktor Stribiżew
Nov 22 at 9:08
1
1
Personally, I'd use
(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.– Dev
Nov 22 at 0:20
Personally, I'd use
(w{5}-w{3}-d{6}-d{2}, d+), which is more specific.– Dev
Nov 22 at 0:20
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the
' ;)– user8408080
Nov 22 at 0:21
This is also what I would do, but I wanted to change OP's regex as little as possible, because he still might have a reason for this. Good addition, though! Also you still missed the
' ;)– user8408080
Nov 22 at 0:21
1
1
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is
'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...– Dev
Nov 22 at 0:28
Oh, sorry, I just copied that from my comment which for some reason didn't update in this tab when I corrected it. The regex I have open in regex101 right now is
'(w{5}-w{3}-d{6}-d{2})', (d+), SO's live update functionality just sucks. Guess I didn't look it over for the 32nd time after copying it over...– Dev
Nov 22 at 0:28
1
1
[wd] = w, but w is not equal to [A-Za-z0-9], in Python 3, w matches any Unicode letter, digit, _ and some diacritics.– Wiktor Stribiżew
Nov 22 at 9:08
[wd] = w, but w is not equal to [A-Za-z0-9], in Python 3, w matches any Unicode letter, digit, _ and some diacritics.– Wiktor Stribiżew
Nov 22 at 9:08
add a comment |
up vote
1
down vote
I don't think the you need to convert the row values to string and then try to parse the result with a regex. The clue was when you said in your update that "Here are the row values converted to string" implying that they're in some other format initially—because the result looks they're actually tuples of two values, a string and an integer.
If that's correct, then you can avoid converting them to strings and then trying to parse it with a regex, because you can get the string you want simply by using the relatively simple built-in string formatting capabilities Python has to do it.
Here's what I mean:
# Raw row data retrieved from database.
rows = [('FMC2H-OHC-100018-00', 2),
('FMC2H-OHC-100027-00', 0),
('FMC2H-OHC-100033-00', 0),
('FMC2H-OHC-100032-00', 20),
('FMC2H-OHC-100017-00', 16)]
for row in rows:
result = '{}, {}'.format(*row) # Convert data in row to a formatted string.
print(result)
Output:
FMC2H-OHC-100018-00, 2
FMC2H-OHC-100027-00, 0
FMC2H-OHC-100033-00, 0
FMC2H-OHC-100032-00, 20
FMC2H-OHC-100017-00, 16
answered Nov 22 at 0:42
martineau
65.3k987176
add a comment |
up vote
1
down vote
I don't think the you need to convert the row values to string and then try to parse the result with a regex. The clue was when you said in your update that "Here are the row values converted to string" implying that they're in some other format initially—because the result looks they're actually tuples of two values, a string and an integer.
If that's correct, then you can avoid converting them to strings and then trying to parse it with a regex, because you can get the string you want simply by using the relatively simple built-in string formatting capabilities Python has to do it.
Here's what I mean:
# Raw row data retrieved from database.
rows = [('FMC2H-OHC-100018-00', 2),
('FMC2H-OHC-100027-00', 0),
('FMC2H-OHC-100033-00', 0),
('FMC2H-OHC-100032-00', 20),
('FMC2H-OHC-100017-00', 16)]
for row in rows:
result = '{}, {}'.format(*row) # Convert data in row to a formatted string.
print(result)
Output:
FMC2H-OHC-100018-00, 2
FMC2H-OHC-100027-00, 0
FMC2H-OHC-100033-00, 0
FMC2H-OHC-100032-00, 20
FMC2H-OHC-100017-00, 16
answered Nov 22 at 0:42
martineau
65.3k987176
add a comment |
up vote
1
down vote
up vote
1
down vote
I don't think the you need to convert the row values to string and then try to parse the result with a regex. The clue was when you said in your update that "Here are the row values converted to string" implying that they're in some other format initially—because the result looks they're actually tuples of two values, a string and an integer.
If that's correct, then you can avoid converting them to strings and then trying to parse it with a regex, because you can get the string you want simply by using the relatively simple built-in string formatting capabilities Python has to do it.
Here's what I mean:
# Raw row data retrieved from database.
rows = [('FMC2H-OHC-100018-00', 2),
('FMC2H-OHC-100027-00', 0),
('FMC2H-OHC-100033-00', 0),
('FMC2H-OHC-100032-00', 20),
('FMC2H-OHC-100017-00', 16)]
for row in rows:
result = '{}, {}'.format(*row) # Convert data in row to a formatted string.
print(result)
Output:
FMC2H-OHC-100018-00, 2
FMC2H-OHC-100027-00, 0
FMC2H-OHC-100033-00, 0
FMC2H-OHC-100032-00, 20
FMC2H-OHC-100017-00, 16
answered Nov 22 at 0:42
martineau
65.3k987176
I don't think the you need to convert the row values to string and then try to parse the result with a regex. The clue was when you said in your update that "Here are the row values converted to string" implying that they're in some other format initially—because the result looks they're actually tuples of two values, a string and an integer.
If that's correct, then you can avoid converting them to strings and then trying to parse it with a regex, because you can get the string you want simply by using the relatively simple built-in string formatting capabilities Python has to do it.
Here's what I mean:
# Raw row data retrieved from database.
rows = [('FMC2H-OHC-100018-00', 2),
('FMC2H-OHC-100027-00', 0),
('FMC2H-OHC-100033-00', 0),
('FMC2H-OHC-100032-00', 20),
('FMC2H-OHC-100017-00', 16)]
for row in rows:
result = '{}, {}'.format(*row) # Convert data in row to a formatted string.
print(result)
Output:
FMC2H-OHC-100018-00, 2
FMC2H-OHC-100027-00, 0
FMC2H-OHC-100033-00, 0
FMC2H-OHC-100032-00, 20
FMC2H-OHC-100017-00, 16
answered Nov 22 at 0:42
martineau
65.3k987176
edited Nov 22 at 3:34
answered Nov 22 at 0:42
martineau
65.3k987176
answered Nov 22 at 0:42
martineau
65.3k987176
answered Nov 22 at 0:42
martineau
65.3k987176
65.3k987176
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I have read that group(0) returns complete match, so what am I doing wrong?
– Javier Ramirez
Nov 21 at 23:45
Please copy enough of your input into the question to locally reproduce your results.
– usr2564301
Nov 21 at 23:46
(w{5}-w{3}-d{6}-d{2}, d+)?– Dev
Nov 21 at 23:58
Your character class isn't matching the single quotes, by the way.
– Dev
Nov 21 at 23:58
Edit the question to include the value of
part_number.– John Gordon
Nov 22 at 0:01