How to loop trough elements of an array wihout a for loop in python?
up vote
-1
down vote
favorite
sindrometestearray[len(sindrometestearray)]
gives the [idxOfElementToChange,idxOfBitToChange]
I have these arrays:
sindrometestearray = [[0,0],[2,1]]
c1divided = [[0,0,0,0],[0,0,0,0],[0,0,0,0]]
example: sindrometestearray[0] = [0,0], in c1divided, the first bit of the first element should be the opposite.
like : [1,0,0,1]
for n in sindrometestearray:
c1divided[n[0]][n[1]] = not(c1divided[n[0]][n[1]])
Output:
[[1,0,0,0],[0,0,0,0],[0,1,0,0]]
How could I do it without for loops?
python
|
show 1 more comment
up vote
-1
down vote
favorite
sindrometestearray[len(sindrometestearray)]
gives the [idxOfElementToChange,idxOfBitToChange]
I have these arrays:
sindrometestearray = [[0,0],[2,1]]
c1divided = [[0,0,0,0],[0,0,0,0],[0,0,0,0]]
example: sindrometestearray[0] = [0,0], in c1divided, the first bit of the first element should be the opposite.
like : [1,0,0,1]
for n in sindrometestearray:
c1divided[n[0]][n[1]] = not(c1divided[n[0]][n[1]])
Output:
[[1,0,0,0],[0,0,0,0],[0,1,0,0]]
How could I do it without for loops?
python
Are you (supposed to be) using NumPy?
– user2357112
Nov 21 at 23:42
Yes. Im importing numpy as np
– Yunrin 127
Nov 21 at 23:43
Welcome to SO, it’s great that you’ve included your code and intended result, could you please explain in more detail what exactly it’s supposed to do to get that?
– Jaba
Nov 21 at 23:46
Shouldn't your output be[[True, 1, 0, 1], [0, 1, 1, 0], [0, True, 0, 0]]instead?
– blhsing
Nov 21 at 23:50
@blhsing yes the True should appear as 1, but yes.
– Yunrin 127
Nov 21 at 23:53
|
show 1 more comment
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
sindrometestearray[len(sindrometestearray)]
gives the [idxOfElementToChange,idxOfBitToChange]
I have these arrays:
sindrometestearray = [[0,0],[2,1]]
c1divided = [[0,0,0,0],[0,0,0,0],[0,0,0,0]]
example: sindrometestearray[0] = [0,0], in c1divided, the first bit of the first element should be the opposite.
like : [1,0,0,1]
for n in sindrometestearray:
c1divided[n[0]][n[1]] = not(c1divided[n[0]][n[1]])
Output:
[[1,0,0,0],[0,0,0,0],[0,1,0,0]]
How could I do it without for loops?
python
sindrometestearray[len(sindrometestearray)]
gives the [idxOfElementToChange,idxOfBitToChange]
I have these arrays:
sindrometestearray = [[0,0],[2,1]]
c1divided = [[0,0,0,0],[0,0,0,0],[0,0,0,0]]
example: sindrometestearray[0] = [0,0], in c1divided, the first bit of the first element should be the opposite.
like : [1,0,0,1]
for n in sindrometestearray:
c1divided[n[0]][n[1]] = not(c1divided[n[0]][n[1]])
Output:
[[1,0,0,0],[0,0,0,0],[0,1,0,0]]
How could I do it without for loops?
python
python
edited Nov 22 at 9:50
asked Nov 21 at 23:41
Yunrin 127
41
41
Are you (supposed to be) using NumPy?
– user2357112
Nov 21 at 23:42
Yes. Im importing numpy as np
– Yunrin 127
Nov 21 at 23:43
Welcome to SO, it’s great that you’ve included your code and intended result, could you please explain in more detail what exactly it’s supposed to do to get that?
– Jaba
Nov 21 at 23:46
Shouldn't your output be[[True, 1, 0, 1], [0, 1, 1, 0], [0, True, 0, 0]]instead?
– blhsing
Nov 21 at 23:50
@blhsing yes the True should appear as 1, but yes.
– Yunrin 127
Nov 21 at 23:53
|
show 1 more comment
Are you (supposed to be) using NumPy?
– user2357112
Nov 21 at 23:42
Yes. Im importing numpy as np
– Yunrin 127
Nov 21 at 23:43
Welcome to SO, it’s great that you’ve included your code and intended result, could you please explain in more detail what exactly it’s supposed to do to get that?
– Jaba
Nov 21 at 23:46
Shouldn't your output be[[True, 1, 0, 1], [0, 1, 1, 0], [0, True, 0, 0]]instead?
– blhsing
Nov 21 at 23:50
@blhsing yes the True should appear as 1, but yes.
– Yunrin 127
Nov 21 at 23:53
Are you (supposed to be) using NumPy?
– user2357112
Nov 21 at 23:42
Are you (supposed to be) using NumPy?
– user2357112
Nov 21 at 23:42
Yes. Im importing numpy as np
– Yunrin 127
Nov 21 at 23:43
Yes. Im importing numpy as np
– Yunrin 127
Nov 21 at 23:43
Welcome to SO, it’s great that you’ve included your code and intended result, could you please explain in more detail what exactly it’s supposed to do to get that?
– Jaba
Nov 21 at 23:46
Welcome to SO, it’s great that you’ve included your code and intended result, could you please explain in more detail what exactly it’s supposed to do to get that?
– Jaba
Nov 21 at 23:46
Shouldn't your output be
[[True, 1, 0, 1], [0, 1, 1, 0], [0, True, 0, 0]] instead?– blhsing
Nov 21 at 23:50
Shouldn't your output be
[[True, 1, 0, 1], [0, 1, 1, 0], [0, True, 0, 0]] instead?– blhsing
Nov 21 at 23:50
@blhsing yes the True should appear as 1, but yes.
– Yunrin 127
Nov 21 at 23:53
@blhsing yes the True should appear as 1, but yes.
– Yunrin 127
Nov 21 at 23:53
|
show 1 more comment
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53421981%2fhow-to-loop-trough-elements-of-an-array-wihout-a-for-loop-in-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53421981%2fhow-to-loop-trough-elements-of-an-array-wihout-a-for-loop-in-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Are you (supposed to be) using NumPy?
– user2357112
Nov 21 at 23:42
Yes. Im importing numpy as np
– Yunrin 127
Nov 21 at 23:43
Welcome to SO, it’s great that you’ve included your code and intended result, could you please explain in more detail what exactly it’s supposed to do to get that?
– Jaba
Nov 21 at 23:46
Shouldn't your output be
[[True, 1, 0, 1], [0, 1, 1, 0], [0, True, 0, 0]]instead?– blhsing
Nov 21 at 23:50
@blhsing yes the True should appear as 1, but yes.
– Yunrin 127
Nov 21 at 23:53