Calculate how many business day have passed
I'm trying to calculate how many business days have passed since a given date
CREATE TABLE `TestTable` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`user` varchar(255) DEFAULT NULL,
`date` datetime DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8;
And this is my query, but I got stuck
SELECT
SUM(5 * (DATEDIFF(NOW(), date) DIV 7) + MID('0123444401233334012222340111123400001234000123440',
7 * WEEKDAY(date) + WEEKDAY(date) + 1,
1) + ((TIMESTAMPDIFF(SECOND,
NOW(),
date) / 86400) - (DATEDIFF(NOW(), date)))) AS Business_Days, user, date
FROM
MyDB.TestTable
If someone can help me telling me what I'm doing wrong.
mysql sql
add a comment |
I'm trying to calculate how many business days have passed since a given date
CREATE TABLE `TestTable` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`user` varchar(255) DEFAULT NULL,
`date` datetime DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8;
And this is my query, but I got stuck
SELECT
SUM(5 * (DATEDIFF(NOW(), date) DIV 7) + MID('0123444401233334012222340111123400001234000123440',
7 * WEEKDAY(date) + WEEKDAY(date) + 1,
1) + ((TIMESTAMPDIFF(SECOND,
NOW(),
date) / 86400) - (DATEDIFF(NOW(), date)))) AS Business_Days, user, date
FROM
MyDB.TestTable
If someone can help me telling me what I'm doing wrong.
mysql sql
Because I need to select a lot of users, will be run as a cron job
– Uffo
Nov 22 at 12:29
stackoverflow.com/questions/1828948/…
– jeroen
Nov 22 at 12:31
3
Please think about what constitutes a business day for your business. Are all holidays needed for the calculations? Are different holidays needed for different countries? Usually it's better to have a table of calendars in which you store all holidays (and weekends) and subtract those from the number of days between two dates to arrive at the number of business days.
– Corion
Nov 22 at 12:57
add a comment |
I'm trying to calculate how many business days have passed since a given date
CREATE TABLE `TestTable` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`user` varchar(255) DEFAULT NULL,
`date` datetime DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8;
And this is my query, but I got stuck
SELECT
SUM(5 * (DATEDIFF(NOW(), date) DIV 7) + MID('0123444401233334012222340111123400001234000123440',
7 * WEEKDAY(date) + WEEKDAY(date) + 1,
1) + ((TIMESTAMPDIFF(SECOND,
NOW(),
date) / 86400) - (DATEDIFF(NOW(), date)))) AS Business_Days, user, date
FROM
MyDB.TestTable
If someone can help me telling me what I'm doing wrong.
mysql sql
I'm trying to calculate how many business days have passed since a given date
CREATE TABLE `TestTable` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`user` varchar(255) DEFAULT NULL,
`date` datetime DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8;
And this is my query, but I got stuck
SELECT
SUM(5 * (DATEDIFF(NOW(), date) DIV 7) + MID('0123444401233334012222340111123400001234000123440',
7 * WEEKDAY(date) + WEEKDAY(date) + 1,
1) + ((TIMESTAMPDIFF(SECOND,
NOW(),
date) / 86400) - (DATEDIFF(NOW(), date)))) AS Business_Days, user, date
FROM
MyDB.TestTable
If someone can help me telling me what I'm doing wrong.
mysql sql
mysql sql
edited Nov 22 at 12:50
Absorbing
857
857
asked Nov 22 at 12:24
Uffo
3,4381660129
3,4381660129
Because I need to select a lot of users, will be run as a cron job
– Uffo
Nov 22 at 12:29
stackoverflow.com/questions/1828948/…
– jeroen
Nov 22 at 12:31
3
Please think about what constitutes a business day for your business. Are all holidays needed for the calculations? Are different holidays needed for different countries? Usually it's better to have a table of calendars in which you store all holidays (and weekends) and subtract those from the number of days between two dates to arrive at the number of business days.
– Corion
Nov 22 at 12:57
add a comment |
Because I need to select a lot of users, will be run as a cron job
– Uffo
Nov 22 at 12:29
stackoverflow.com/questions/1828948/…
– jeroen
Nov 22 at 12:31
3
Please think about what constitutes a business day for your business. Are all holidays needed for the calculations? Are different holidays needed for different countries? Usually it's better to have a table of calendars in which you store all holidays (and weekends) and subtract those from the number of days between two dates to arrive at the number of business days.
– Corion
Nov 22 at 12:57
Because I need to select a lot of users, will be run as a cron job
– Uffo
Nov 22 at 12:29
Because I need to select a lot of users, will be run as a cron job
– Uffo
Nov 22 at 12:29
stackoverflow.com/questions/1828948/…
– jeroen
Nov 22 at 12:31
stackoverflow.com/questions/1828948/…
– jeroen
Nov 22 at 12:31
3
3
Please think about what constitutes a business day for your business. Are all holidays needed for the calculations? Are different holidays needed for different countries? Usually it's better to have a table of calendars in which you store all holidays (and weekends) and subtract those from the number of days between two dates to arrive at the number of business days.
– Corion
Nov 22 at 12:57
Please think about what constitutes a business day for your business. Are all holidays needed for the calculations? Are different holidays needed for different countries? Usually it's better to have a table of calendars in which you store all holidays (and weekends) and subtract those from the number of days between two dates to arrive at the number of business days.
– Corion
Nov 22 at 12:57
add a comment |
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Because I need to select a lot of users, will be run as a cron job
– Uffo
Nov 22 at 12:29
stackoverflow.com/questions/1828948/…
– jeroen
Nov 22 at 12:31
3
Please think about what constitutes a business day for your business. Are all holidays needed for the calculations? Are different holidays needed for different countries? Usually it's better to have a table of calendars in which you store all holidays (and weekends) and subtract those from the number of days between two dates to arrive at the number of business days.
– Corion
Nov 22 at 12:57