Helicoid is developable surface
Please help me to prove that helicoid whose parametric equation is given by
$$x=ucos v, y= usin v, z=pu$$
is developable, where $p$ is a constant and $u,v$ are the curvelinear coordinates of the surface.
Thank you.
differential-geometry surfaces
asked Dec 4 '18 at 17:05
chandan mondal
1758
add a comment |
Please help me to prove that helicoid whose parametric equation is given by
$$x=ucos v, y= usin v, z=pu$$
is developable, where $p$ is a constant and $u,v$ are the curvelinear coordinates of the surface.
Thank you.
differential-geometry surfaces
asked Dec 4 '18 at 17:05
chandan mondal
1758
add a comment |
Please help me to prove that helicoid whose parametric equation is given by
$$x=ucos v, y= usin v, z=pu$$
is developable, where $p$ is a constant and $u,v$ are the curvelinear coordinates of the surface.
Thank you.
differential-geometry surfaces
asked Dec 4 '18 at 17:05
chandan mondal
1758
Please help me to prove that helicoid whose parametric equation is given by
$$x=ucos v, y= usin v, z=pu$$
is developable, where $p$ is a constant and $u,v$ are the curvelinear coordinates of the surface.
Thank you.
differential-geometry surfaces
differential-geometry surfaces
asked Dec 4 '18 at 17:05
chandan mondal
1758
asked Dec 4 '18 at 17:05
chandan mondal
1758
asked Dec 4 '18 at 17:05
chandan mondal
1758
asked Dec 4 '18 at 17:05
chandan mondal
1758
asked Dec 4 '18 at 17:05
chandan mondal
1758
1758
add a comment |
add a comment |
1 Answer
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I'm afraid I cannot do that, as it is false.
According to this, the helicoid is ruled, but non-developable.
Here you can find a formula for the non-zero Gaussian curvature.
answered Dec 4 '18 at 17:16
Federico
4,799514
add a comment |
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1 Answer
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I'm afraid I cannot do that, as it is false.
According to this, the helicoid is ruled, but non-developable.
Here you can find a formula for the non-zero Gaussian curvature.
answered Dec 4 '18 at 17:16
Federico
4,799514
add a comment |
I'm afraid I cannot do that, as it is false.
According to this, the helicoid is ruled, but non-developable.
Here you can find a formula for the non-zero Gaussian curvature.
answered Dec 4 '18 at 17:16
Federico
4,799514
add a comment |
I'm afraid I cannot do that, as it is false.
According to this, the helicoid is ruled, but non-developable.
Here you can find a formula for the non-zero Gaussian curvature.
answered Dec 4 '18 at 17:16
Federico
4,799514
I'm afraid I cannot do that, as it is false.
According to this, the helicoid is ruled, but non-developable.
Here you can find a formula for the non-zero Gaussian curvature.
answered Dec 4 '18 at 17:16
Federico
4,799514
answered Dec 4 '18 at 17:16
Federico
4,799514
answered Dec 4 '18 at 17:16
Federico
4,799514
answered Dec 4 '18 at 17:16
Federico
4,799514
4,799514
add a comment |
add a comment |
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