Python match string with dynamic number in string
I have a string and want to match which has words, number, and forward slash.
for eg my string is 'abc/11/xyz'
I tried it but returns nothing,
re.match(r'(a-z)+/(d)+/(w)+', 'abc/11/xyz')
Thank you
python regex pattern-matching
asked Nov 23 '18 at 5:32
aakash singh
437
add a comment |
I have a string and want to match which has words, number, and forward slash.
for eg my string is 'abc/11/xyz'
I tried it but returns nothing,
re.match(r'(a-z)+/(d)+/(w)+', 'abc/11/xyz')
Thank you
python regex pattern-matching
asked Nov 23 '18 at 5:32
aakash singh
437
add a comment |
I have a string and want to match which has words, number, and forward slash.
for eg my string is 'abc/11/xyz'
I tried it but returns nothing,
re.match(r'(a-z)+/(d)+/(w)+', 'abc/11/xyz')
Thank you
python regex pattern-matching
asked Nov 23 '18 at 5:32
aakash singh
437
I have a string and want to match which has words, number, and forward slash.
for eg my string is 'abc/11/xyz'
I tried it but returns nothing,
re.match(r'(a-z)+/(d)+/(w)+', 'abc/11/xyz')
Thank you
python regex pattern-matching
python regex pattern-matching
asked Nov 23 '18 at 5:32
aakash singh
437
asked Nov 23 '18 at 5:32
aakash singh
437
asked Nov 23 '18 at 5:32
aakash singh
437
asked Nov 23 '18 at 5:32
aakash singh
437
asked Nov 23 '18 at 5:32
aakash singh
437
437
add a comment |
add a comment |
1 Answer
1
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re.match(r'([a-z])+/(d)+/(w)+', 'abc/11/xyz')
(a-z)+ matches literally a-z. It seems you want to match any characters between a and z, so you need to use square brackets ([a-z])+ to make a character class.
answered Nov 23 '18 at 5:39
Loocid
2,61011230
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
1
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
re.match(r'([a-z])+/(d)+/(w)+', 'abc/11/xyz')
(a-z)+ matches literally a-z. It seems you want to match any characters between a and z, so you need to use square brackets ([a-z])+ to make a character class.
answered Nov 23 '18 at 5:39
Loocid
2,61011230
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
1
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
add a comment |
re.match(r'([a-z])+/(d)+/(w)+', 'abc/11/xyz')
(a-z)+ matches literally a-z. It seems you want to match any characters between a and z, so you need to use square brackets ([a-z])+ to make a character class.
answered Nov 23 '18 at 5:39
Loocid
2,61011230
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
1
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
add a comment |
re.match(r'([a-z])+/(d)+/(w)+', 'abc/11/xyz')
(a-z)+ matches literally a-z. It seems you want to match any characters between a and z, so you need to use square brackets ([a-z])+ to make a character class.
answered Nov 23 '18 at 5:39
Loocid
2,61011230
re.match(r'([a-z])+/(d)+/(w)+', 'abc/11/xyz')
(a-z)+ matches literally a-z. It seems you want to match any characters between a and z, so you need to use square brackets ([a-z])+ to make a character class.
answered Nov 23 '18 at 5:39
Loocid
2,61011230
answered Nov 23 '18 at 5:39
Loocid
2,61011230
answered Nov 23 '18 at 5:39
Loocid
2,61011230
answered Nov 23 '18 at 5:39
Loocid
2,61011230
2,61011230
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
1
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
add a comment |
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
1
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
If this really be the only problem with the OP, then I might say it is a typo, in which case we should just vote to close.
– Tim Biegeleisen
Nov 23 '18 at 5:43
1
1
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
@TimBiegeleisen it is not a typo, it is lack of regex knowledge.
– FallenAngel
Nov 23 '18 at 5:45
add a comment |
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