Htykuut

i am looking for a solution:

$txt = "Welcome to ".$place." City!";

$place = "New York";

echo $txt; // should be "Welcome to New York City!"

The variable "$place" can only be declared after the variable "$txt".
Is that possible?

Thanks

It's unclear what you're trying to accomplish. But this is pretty close to your example and works as expected:

$txt = "Welcome to %s City!";

$place = "New York";

printf($txt, $place); // should be "Welcome to New York City!"

https://3v4l.org/jEQvZ

You can't do that directly. The string is concatenated using the value of $place at the time of assignment so any changes to $place will not be reflected in the string. You can emulate something like this by writing a function that will generate the string once you know the place it should reference.

function welcome($place) {

    return 'Welcome to '.$place.' City!';

}



$place = 'New York';



echo welcome($place);

Yes it's possible.

Just create a placeholder and str_replace it.

Notice I changed " to '.

If you use " it will read $place as a variable. With ' $place is string and can be replaced later in the code.

$txt = 'Welcome to $place City!';

$place = "New York";

echo str_replace('$place', $place, $txt);

https://3v4l.org/DVtQa