Python match tuples in string
I have a string with the format:
s = "[(1,2,'foe'), (3,5,'bar'), ...]"
I need to extract each tuple using regular expressions.
I tried stripping '[' and ']' and then apply
re.findall(r'((d+),(d+),(.+))', s[1:-1])
and other variants but cannot make it work.
python regex string tuples
edited Nov 22 at 20:16
timgeb
49.2k116390
asked Nov 22 at 19:34
Fernando Ruscitti
83
add a comment |
I have a string with the format:
s = "[(1,2,'foe'), (3,5,'bar'), ...]"
I need to extract each tuple using regular expressions.
I tried stripping '[' and ']' and then apply
re.findall(r'((d+),(d+),(.+))', s[1:-1])
and other variants but cannot make it work.
python regex string tuples
edited Nov 22 at 20:16
timgeb
49.2k116390
asked Nov 22 at 19:34
Fernando Ruscitti
83
N.B: This pattern is not recursive, it's repeating. A recursive one would be like:[(1, [(2, [(3, [...])])])]
– handras
Nov 22 at 20:00
add a comment |
I have a string with the format:
s = "[(1,2,'foe'), (3,5,'bar'), ...]"
I need to extract each tuple using regular expressions.
I tried stripping '[' and ']' and then apply
re.findall(r'((d+),(d+),(.+))', s[1:-1])
and other variants but cannot make it work.
python regex string tuples
edited Nov 22 at 20:16
timgeb
49.2k116390
asked Nov 22 at 19:34
Fernando Ruscitti
83
I have a string with the format:
s = "[(1,2,'foe'), (3,5,'bar'), ...]"
I need to extract each tuple using regular expressions.
I tried stripping '[' and ']' and then apply
re.findall(r'((d+),(d+),(.+))', s[1:-1])
and other variants but cannot make it work.
python regex string tuples
python regex string tuples
edited Nov 22 at 20:16
timgeb
49.2k116390
asked Nov 22 at 19:34
Fernando Ruscitti
83
edited Nov 22 at 20:16
timgeb
49.2k116390
asked Nov 22 at 19:34
Fernando Ruscitti
83
edited Nov 22 at 20:16
timgeb
49.2k116390
edited Nov 22 at 20:16
timgeb
49.2k116390
edited Nov 22 at 20:16
timgeb
49.2k116390
49.2k116390
asked Nov 22 at 19:34
Fernando Ruscitti
83
asked Nov 22 at 19:34
Fernando Ruscitti
83
asked Nov 22 at 19:34
Fernando Ruscitti
83
83
N.B: This pattern is not recursive, it's repeating. A recursive one would be like:[(1, [(2, [(3, [...])])])]
– handras
Nov 22 at 20:00
add a comment |
N.B: This pattern is not recursive, it's repeating. A recursive one would be like:[(1, [(2, [(3, [...])])])]
– handras
Nov 22 at 20:00
N.B: This pattern is not recursive, it's repeating. A recursive one would be like:
[(1, [(2, [(3, [...])])])]– handras
Nov 22 at 20:00
N.B: This pattern is not recursive, it's repeating. A recursive one would be like:
[(1, [(2, [(3, [...])])])]– handras
Nov 22 at 20:00
add a comment |
1 Answer
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votes
It looks like you have a list-literal. You don't evaluate those with regex, you throw ast.literal_eval on it and are done.
>>> from ast import literal_eval
>>> literal_eval("[(1,2,'foe'), (3,5,'bar')]")
[(1, 2, 'foe'), (3, 5, 'bar')]
answered Nov 22 at 19:39
timgeb
49.2k116390
1
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It looks like you have a list-literal. You don't evaluate those with regex, you throw ast.literal_eval on it and are done.
>>> from ast import literal_eval
>>> literal_eval("[(1,2,'foe'), (3,5,'bar')]")
[(1, 2, 'foe'), (3, 5, 'bar')]
answered Nov 22 at 19:39
timgeb
49.2k116390
1
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
add a comment |
It looks like you have a list-literal. You don't evaluate those with regex, you throw ast.literal_eval on it and are done.
>>> from ast import literal_eval
>>> literal_eval("[(1,2,'foe'), (3,5,'bar')]")
[(1, 2, 'foe'), (3, 5, 'bar')]
answered Nov 22 at 19:39
timgeb
49.2k116390
1
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
add a comment |
It looks like you have a list-literal. You don't evaluate those with regex, you throw ast.literal_eval on it and are done.
>>> from ast import literal_eval
>>> literal_eval("[(1,2,'foe'), (3,5,'bar')]")
[(1, 2, 'foe'), (3, 5, 'bar')]
answered Nov 22 at 19:39
timgeb
49.2k116390
It looks like you have a list-literal. You don't evaluate those with regex, you throw ast.literal_eval on it and are done.
>>> from ast import literal_eval
>>> literal_eval("[(1,2,'foe'), (3,5,'bar')]")
[(1, 2, 'foe'), (3, 5, 'bar')]
answered Nov 22 at 19:39
timgeb
49.2k116390
answered Nov 22 at 19:39
timgeb
49.2k116390
answered Nov 22 at 19:39
timgeb
49.2k116390
answered Nov 22 at 19:39
timgeb
49.2k116390
49.2k116390
1
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
add a comment |
1
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
1
1
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
thats exactly what I needed!! Thanks very much. Sorry I didn't know about ast module.
– Fernando Ruscitti
Nov 22 at 19:46
add a comment |
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N.B: This pattern is not recursive, it's repeating. A recursive one would be like:
[(1, [(2, [(3, [...])])])]– handras
Nov 22 at 20:00