Negate the statement and re-express as an equivalent positive statement.












0














Need help with this homework problem. I need to negate the statement and then re-express it as a positive statement. I've searched online and haven't been able to find an answer. I'm having trouble grasping quantificational logic so thanks in advance to whoever helps.



Original statement:




Everyone is happy sometimes, but no one is happy all the time.




My attempt at symbolizing the statement: let x = be happy sometimes and y = to be happy all the time. ∀(x) ∧ ∃(¬y)



Any help is appreciated.










share|cite|improve this question
























  • Do you need two negations, one for each, otr one single negation of the whole "original statement"?
    – coffeemath
    Dec 4 '18 at 2:41






  • 2




    You must have attempted to symbolize the original statement before negating it ... can you post your attempt?
    – Bram28
    Dec 4 '18 at 2:46






  • 1




    You really need a 2-var statement like $h(x,t)$ for $x$ is happy at time $t$ to symbolize these. Everyone happy sometime then is for all x exists t so h(x,t). no one happy all the time is then (not)[exists x) (for all t) h(x,t)], These can be put together using "and" for the "but" in original statement. [So far this has not been negated]
    – coffeemath
    Dec 4 '18 at 6:25








  • 1




    You cannot nagate variables: $x,y,ldots$. In quantificational logic (aka predicate logic) we have variables (to be quantified) and predicates. With them we form sentences and we have to use logical connective : $lnot, land, ldots$ with sentences.
    – Mauro ALLEGRANZA
    Dec 4 '18 at 7:11
















0














Need help with this homework problem. I need to negate the statement and then re-express it as a positive statement. I've searched online and haven't been able to find an answer. I'm having trouble grasping quantificational logic so thanks in advance to whoever helps.



Original statement:




Everyone is happy sometimes, but no one is happy all the time.




My attempt at symbolizing the statement: let x = be happy sometimes and y = to be happy all the time. ∀(x) ∧ ∃(¬y)



Any help is appreciated.










share|cite|improve this question
























  • Do you need two negations, one for each, otr one single negation of the whole "original statement"?
    – coffeemath
    Dec 4 '18 at 2:41






  • 2




    You must have attempted to symbolize the original statement before negating it ... can you post your attempt?
    – Bram28
    Dec 4 '18 at 2:46






  • 1




    You really need a 2-var statement like $h(x,t)$ for $x$ is happy at time $t$ to symbolize these. Everyone happy sometime then is for all x exists t so h(x,t). no one happy all the time is then (not)[exists x) (for all t) h(x,t)], These can be put together using "and" for the "but" in original statement. [So far this has not been negated]
    – coffeemath
    Dec 4 '18 at 6:25








  • 1




    You cannot nagate variables: $x,y,ldots$. In quantificational logic (aka predicate logic) we have variables (to be quantified) and predicates. With them we form sentences and we have to use logical connective : $lnot, land, ldots$ with sentences.
    – Mauro ALLEGRANZA
    Dec 4 '18 at 7:11














0












0








0


0





Need help with this homework problem. I need to negate the statement and then re-express it as a positive statement. I've searched online and haven't been able to find an answer. I'm having trouble grasping quantificational logic so thanks in advance to whoever helps.



Original statement:




Everyone is happy sometimes, but no one is happy all the time.




My attempt at symbolizing the statement: let x = be happy sometimes and y = to be happy all the time. ∀(x) ∧ ∃(¬y)



Any help is appreciated.










share|cite|improve this question















Need help with this homework problem. I need to negate the statement and then re-express it as a positive statement. I've searched online and haven't been able to find an answer. I'm having trouble grasping quantificational logic so thanks in advance to whoever helps.



Original statement:




Everyone is happy sometimes, but no one is happy all the time.




My attempt at symbolizing the statement: let x = be happy sometimes and y = to be happy all the time. ∀(x) ∧ ∃(¬y)



Any help is appreciated.







logic quantifiers






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 4 '18 at 7:09









Mauro ALLEGRANZA

64.4k448112




64.4k448112










asked Dec 4 '18 at 2:36









bvallier

11




11












  • Do you need two negations, one for each, otr one single negation of the whole "original statement"?
    – coffeemath
    Dec 4 '18 at 2:41






  • 2




    You must have attempted to symbolize the original statement before negating it ... can you post your attempt?
    – Bram28
    Dec 4 '18 at 2:46






  • 1




    You really need a 2-var statement like $h(x,t)$ for $x$ is happy at time $t$ to symbolize these. Everyone happy sometime then is for all x exists t so h(x,t). no one happy all the time is then (not)[exists x) (for all t) h(x,t)], These can be put together using "and" for the "but" in original statement. [So far this has not been negated]
    – coffeemath
    Dec 4 '18 at 6:25








  • 1




    You cannot nagate variables: $x,y,ldots$. In quantificational logic (aka predicate logic) we have variables (to be quantified) and predicates. With them we form sentences and we have to use logical connective : $lnot, land, ldots$ with sentences.
    – Mauro ALLEGRANZA
    Dec 4 '18 at 7:11


















  • Do you need two negations, one for each, otr one single negation of the whole "original statement"?
    – coffeemath
    Dec 4 '18 at 2:41






  • 2




    You must have attempted to symbolize the original statement before negating it ... can you post your attempt?
    – Bram28
    Dec 4 '18 at 2:46






  • 1




    You really need a 2-var statement like $h(x,t)$ for $x$ is happy at time $t$ to symbolize these. Everyone happy sometime then is for all x exists t so h(x,t). no one happy all the time is then (not)[exists x) (for all t) h(x,t)], These can be put together using "and" for the "but" in original statement. [So far this has not been negated]
    – coffeemath
    Dec 4 '18 at 6:25








  • 1




    You cannot nagate variables: $x,y,ldots$. In quantificational logic (aka predicate logic) we have variables (to be quantified) and predicates. With them we form sentences and we have to use logical connective : $lnot, land, ldots$ with sentences.
    – Mauro ALLEGRANZA
    Dec 4 '18 at 7:11
















Do you need two negations, one for each, otr one single negation of the whole "original statement"?
– coffeemath
Dec 4 '18 at 2:41




Do you need two negations, one for each, otr one single negation of the whole "original statement"?
– coffeemath
Dec 4 '18 at 2:41




2




2




You must have attempted to symbolize the original statement before negating it ... can you post your attempt?
– Bram28
Dec 4 '18 at 2:46




You must have attempted to symbolize the original statement before negating it ... can you post your attempt?
– Bram28
Dec 4 '18 at 2:46




1




1




You really need a 2-var statement like $h(x,t)$ for $x$ is happy at time $t$ to symbolize these. Everyone happy sometime then is for all x exists t so h(x,t). no one happy all the time is then (not)[exists x) (for all t) h(x,t)], These can be put together using "and" for the "but" in original statement. [So far this has not been negated]
– coffeemath
Dec 4 '18 at 6:25






You really need a 2-var statement like $h(x,t)$ for $x$ is happy at time $t$ to symbolize these. Everyone happy sometime then is for all x exists t so h(x,t). no one happy all the time is then (not)[exists x) (for all t) h(x,t)], These can be put together using "and" for the "but" in original statement. [So far this has not been negated]
– coffeemath
Dec 4 '18 at 6:25






1




1




You cannot nagate variables: $x,y,ldots$. In quantificational logic (aka predicate logic) we have variables (to be quantified) and predicates. With them we form sentences and we have to use logical connective : $lnot, land, ldots$ with sentences.
– Mauro ALLEGRANZA
Dec 4 '18 at 7:11




You cannot nagate variables: $x,y,ldots$. In quantificational logic (aka predicate logic) we have variables (to be quantified) and predicates. With them we form sentences and we have to use logical connective : $lnot, land, ldots$ with sentences.
– Mauro ALLEGRANZA
Dec 4 '18 at 7:11










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