Probability of the first die
I am working on the following problem.
If you toss two dice, what is the probability that the first dice shows a face of 6, given that the sum of both faces is an 8?
Am I wrong to assume that both rolls are independent? If not, wouldn't the probability just be the following:
$$frac{1}{6} approx 16.67%$$
Thank you!
probability dice
add a comment |
I am working on the following problem.
If you toss two dice, what is the probability that the first dice shows a face of 6, given that the sum of both faces is an 8?
Am I wrong to assume that both rolls are independent? If not, wouldn't the probability just be the following:
$$frac{1}{6} approx 16.67%$$
Thank you!
probability dice
add a comment |
I am working on the following problem.
If you toss two dice, what is the probability that the first dice shows a face of 6, given that the sum of both faces is an 8?
Am I wrong to assume that both rolls are independent? If not, wouldn't the probability just be the following:
$$frac{1}{6} approx 16.67%$$
Thank you!
probability dice
I am working on the following problem.
If you toss two dice, what is the probability that the first dice shows a face of 6, given that the sum of both faces is an 8?
Am I wrong to assume that both rolls are independent? If not, wouldn't the probability just be the following:
$$frac{1}{6} approx 16.67%$$
Thank you!
probability dice
probability dice
asked Dec 4 '18 at 2:56
Lee
1015
1015
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Yes, you are wrong, because the information that the sum is $8$ means the rolls are not independent. In particular, the first roll cannot be $1$ (nor can the second).
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3025068%2fprobability-of-the-first-die%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Yes, you are wrong, because the information that the sum is $8$ means the rolls are not independent. In particular, the first roll cannot be $1$ (nor can the second).
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
add a comment |
Yes, you are wrong, because the information that the sum is $8$ means the rolls are not independent. In particular, the first roll cannot be $1$ (nor can the second).
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
add a comment |
Yes, you are wrong, because the information that the sum is $8$ means the rolls are not independent. In particular, the first roll cannot be $1$ (nor can the second).
Yes, you are wrong, because the information that the sum is $8$ means the rolls are not independent. In particular, the first roll cannot be $1$ (nor can the second).
answered Dec 4 '18 at 3:00
Ross Millikan
292k23197371
292k23197371
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
add a comment |
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
I see what you are saying. Thank you for the information!
– Lee
Dec 4 '18 at 3:02
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3025068%2fprobability-of-the-first-die%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown