Simple reshape of numpy array: error: 'total size of new array must be unchanged'
Here is a very straightforward version of the problem i am having reshaping a 40*1 array into a 20*2 array. What is going wrong here?
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
#reshape to 2*20
print(np.reshape(x,2,20))
#returns error: 'total size of new array must be unchanged'
python numpy reshape numpy-ndarray
add a comment |
Here is a very straightforward version of the problem i am having reshaping a 40*1 array into a 20*2 array. What is going wrong here?
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
#reshape to 2*20
print(np.reshape(x,2,20))
#returns error: 'total size of new array must be unchanged'
python numpy reshape numpy-ndarray
let me know if my answer helps
– seralouk
Nov 22 '18 at 22:58
You haven't read the docs closely enough
– Nils Werner
Nov 22 '18 at 22:58
@seralouk yes, it answers my question exactly. thanks!
– HMReliable
Nov 22 '18 at 23:00
add a comment |
Here is a very straightforward version of the problem i am having reshaping a 40*1 array into a 20*2 array. What is going wrong here?
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
#reshape to 2*20
print(np.reshape(x,2,20))
#returns error: 'total size of new array must be unchanged'
python numpy reshape numpy-ndarray
Here is a very straightforward version of the problem i am having reshaping a 40*1 array into a 20*2 array. What is going wrong here?
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
#reshape to 2*20
print(np.reshape(x,2,20))
#returns error: 'total size of new array must be unchanged'
python numpy reshape numpy-ndarray
python numpy reshape numpy-ndarray
edited Nov 22 '18 at 23:18
seralouk
5,66522338
5,66522338
asked Nov 22 '18 at 22:55
HMReliable
185
185
let me know if my answer helps
– seralouk
Nov 22 '18 at 22:58
You haven't read the docs closely enough
– Nils Werner
Nov 22 '18 at 22:58
@seralouk yes, it answers my question exactly. thanks!
– HMReliable
Nov 22 '18 at 23:00
add a comment |
let me know if my answer helps
– seralouk
Nov 22 '18 at 22:58
You haven't read the docs closely enough
– Nils Werner
Nov 22 '18 at 22:58
@seralouk yes, it answers my question exactly. thanks!
– HMReliable
Nov 22 '18 at 23:00
let me know if my answer helps
– seralouk
Nov 22 '18 at 22:58
let me know if my answer helps
– seralouk
Nov 22 '18 at 22:58
You haven't read the docs closely enough
– Nils Werner
Nov 22 '18 at 22:58
You haven't read the docs closely enough
– Nils Werner
Nov 22 '18 at 22:58
@seralouk yes, it answers my question exactly. thanks!
– HMReliable
Nov 22 '18 at 23:00
@seralouk yes, it answers my question exactly. thanks!
– HMReliable
Nov 22 '18 at 23:00
add a comment |
1 Answer
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votes
You do not use the function as you should use it.
Simply use this:
np.reshape(x,(2,20))
Documentation here
Full code:
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
print(np.reshape(x,(2,20)))
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You do not use the function as you should use it.
Simply use this:
np.reshape(x,(2,20))
Documentation here
Full code:
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
print(np.reshape(x,(2,20)))
add a comment |
You do not use the function as you should use it.
Simply use this:
np.reshape(x,(2,20))
Documentation here
Full code:
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
print(np.reshape(x,(2,20)))
add a comment |
You do not use the function as you should use it.
Simply use this:
np.reshape(x,(2,20))
Documentation here
Full code:
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
print(np.reshape(x,(2,20)))
You do not use the function as you should use it.
Simply use this:
np.reshape(x,(2,20))
Documentation here
Full code:
import numpy as np
x=np.linspace(1,20,40)
#confirm length is 40
print(np.shape(x))
print(np.reshape(x,(2,20)))
answered Nov 22 '18 at 22:57
seralouk
5,66522338
5,66522338
add a comment |
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let me know if my answer helps
– seralouk
Nov 22 '18 at 22:58
You haven't read the docs closely enough
– Nils Werner
Nov 22 '18 at 22:58
@seralouk yes, it answers my question exactly. thanks!
– HMReliable
Nov 22 '18 at 23:00