How can I prove given language is not regular?












1














My first post here, so glad I found this great place. Hoping I could improve and learn a lot from you and contribute in the future if I can.



I have a problem with the following scenario:




Given $Sigma= {a,b,c,d}$, prove that $L$ is not regular, where $$L = {a^ib^jcd^k mid i geq 0; k > j > 0}$$
using: 1) pumping lemma 2) closure properties.




Regarding 1)



Assuming that $L$ is regular, using the pumping lemma there should exist some integer $n$ (pumping length). Choosing a word $w in L$ (not sure if I chose the right word). If $w=a^ib^jcd^k$ ($|w|>n$), but I cannot find a way to obtain $xy^i z notin L$, would very appreciate an explanation or example of how you found the term so it can be concluded that $L$ is not regular using the pumping lemma.



Regarding 2)



Assuming that $L$ is regular, it means that $a^ib^jcd^k$ is also regular. So it should be closed under intersection, however, the form of ${a^ib^jcd^k mid igeq 0;k>j>0}$ is not regular, and it can be achieved using completion, so contradiction and because of that $L$ is not regular.



Hoping to learn from my mistakes and improve.



Thank you very much for your aid.










share|cite|improve this question





























    1














    My first post here, so glad I found this great place. Hoping I could improve and learn a lot from you and contribute in the future if I can.



    I have a problem with the following scenario:




    Given $Sigma= {a,b,c,d}$, prove that $L$ is not regular, where $$L = {a^ib^jcd^k mid i geq 0; k > j > 0}$$
    using: 1) pumping lemma 2) closure properties.




    Regarding 1)



    Assuming that $L$ is regular, using the pumping lemma there should exist some integer $n$ (pumping length). Choosing a word $w in L$ (not sure if I chose the right word). If $w=a^ib^jcd^k$ ($|w|>n$), but I cannot find a way to obtain $xy^i z notin L$, would very appreciate an explanation or example of how you found the term so it can be concluded that $L$ is not regular using the pumping lemma.



    Regarding 2)



    Assuming that $L$ is regular, it means that $a^ib^jcd^k$ is also regular. So it should be closed under intersection, however, the form of ${a^ib^jcd^k mid igeq 0;k>j>0}$ is not regular, and it can be achieved using completion, so contradiction and because of that $L$ is not regular.



    Hoping to learn from my mistakes and improve.



    Thank you very much for your aid.










    share|cite|improve this question



























      1












      1








      1







      My first post here, so glad I found this great place. Hoping I could improve and learn a lot from you and contribute in the future if I can.



      I have a problem with the following scenario:




      Given $Sigma= {a,b,c,d}$, prove that $L$ is not regular, where $$L = {a^ib^jcd^k mid i geq 0; k > j > 0}$$
      using: 1) pumping lemma 2) closure properties.




      Regarding 1)



      Assuming that $L$ is regular, using the pumping lemma there should exist some integer $n$ (pumping length). Choosing a word $w in L$ (not sure if I chose the right word). If $w=a^ib^jcd^k$ ($|w|>n$), but I cannot find a way to obtain $xy^i z notin L$, would very appreciate an explanation or example of how you found the term so it can be concluded that $L$ is not regular using the pumping lemma.



      Regarding 2)



      Assuming that $L$ is regular, it means that $a^ib^jcd^k$ is also regular. So it should be closed under intersection, however, the form of ${a^ib^jcd^k mid igeq 0;k>j>0}$ is not regular, and it can be achieved using completion, so contradiction and because of that $L$ is not regular.



      Hoping to learn from my mistakes and improve.



      Thank you very much for your aid.










      share|cite|improve this question















      My first post here, so glad I found this great place. Hoping I could improve and learn a lot from you and contribute in the future if I can.



      I have a problem with the following scenario:




      Given $Sigma= {a,b,c,d}$, prove that $L$ is not regular, where $$L = {a^ib^jcd^k mid i geq 0; k > j > 0}$$
      using: 1) pumping lemma 2) closure properties.




      Regarding 1)



      Assuming that $L$ is regular, using the pumping lemma there should exist some integer $n$ (pumping length). Choosing a word $w in L$ (not sure if I chose the right word). If $w=a^ib^jcd^k$ ($|w|>n$), but I cannot find a way to obtain $xy^i z notin L$, would very appreciate an explanation or example of how you found the term so it can be concluded that $L$ is not regular using the pumping lemma.



      Regarding 2)



      Assuming that $L$ is regular, it means that $a^ib^jcd^k$ is also regular. So it should be closed under intersection, however, the form of ${a^ib^jcd^k mid igeq 0;k>j>0}$ is not regular, and it can be achieved using completion, so contradiction and because of that $L$ is not regular.



      Hoping to learn from my mistakes and improve.



      Thank you very much for your aid.







      computer-science automata regular-language






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      edited Dec 4 at 6:20









      J.-E. Pin

      18.3k21754




      18.3k21754










      asked Dec 2 at 11:27









      mathnoobie

      93




      93






















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          For (1): You assume the language satisfies the pumping lemma for some $n$.
          You want to choose a word that would have at least one of its letters related to $n$.
          A good start would be taking one of your letters $lin w$ to be $l^n$, and using that to show that for some $i$, $xy^iznotin L$



          For (2): You want to show that if $L$ is regular, then some other language $L_{not}$ which you know is not regular, is the intersection of another regular language $L_{reg}cap L=L_{not}$.






          share|cite|improve this answer





















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            1 Answer
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            0














            For (1): You assume the language satisfies the pumping lemma for some $n$.
            You want to choose a word that would have at least one of its letters related to $n$.
            A good start would be taking one of your letters $lin w$ to be $l^n$, and using that to show that for some $i$, $xy^iznotin L$



            For (2): You want to show that if $L$ is regular, then some other language $L_{not}$ which you know is not regular, is the intersection of another regular language $L_{reg}cap L=L_{not}$.






            share|cite|improve this answer


























              0














              For (1): You assume the language satisfies the pumping lemma for some $n$.
              You want to choose a word that would have at least one of its letters related to $n$.
              A good start would be taking one of your letters $lin w$ to be $l^n$, and using that to show that for some $i$, $xy^iznotin L$



              For (2): You want to show that if $L$ is regular, then some other language $L_{not}$ which you know is not regular, is the intersection of another regular language $L_{reg}cap L=L_{not}$.






              share|cite|improve this answer
























                0












                0








                0






                For (1): You assume the language satisfies the pumping lemma for some $n$.
                You want to choose a word that would have at least one of its letters related to $n$.
                A good start would be taking one of your letters $lin w$ to be $l^n$, and using that to show that for some $i$, $xy^iznotin L$



                For (2): You want to show that if $L$ is regular, then some other language $L_{not}$ which you know is not regular, is the intersection of another regular language $L_{reg}cap L=L_{not}$.






                share|cite|improve this answer












                For (1): You assume the language satisfies the pumping lemma for some $n$.
                You want to choose a word that would have at least one of its letters related to $n$.
                A good start would be taking one of your letters $lin w$ to be $l^n$, and using that to show that for some $i$, $xy^iznotin L$



                For (2): You want to show that if $L$ is regular, then some other language $L_{not}$ which you know is not regular, is the intersection of another regular language $L_{reg}cap L=L_{not}$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 3 at 4:34









                NL1992

                8311




                8311






























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