How to get all the text separately from the bracket using javascript regular expression
I have a sentence stored in a variable.That sentence I need to extract into 4 parts depends on sentence which I have put into variables in my code,I can able to extract here and get into console but I am not getting the whole text of inside the bracket,only I am getting first words.Here is the code below.Can anyone please help me.
HTML
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="messages">
SCRIPT
$(document).ready(function() {
regex = /.+(|d. w+/g;
maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
matches = maintext.match(regex);
text_split0 = matches[0].slice(0, -1);
text_split1 = matches[1];
text_split2 = matches[2];
text_split3 = matches[3];
text_split4 = matches[4];
console.log(text_split0);
console.log(text_split1);
console.log(text_split2);
console.log(text_split3);
console.log(text_split4);
$(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');
// $("li:contains('undefined')").remove()
});
javascript jquery html
add a comment |
I have a sentence stored in a variable.That sentence I need to extract into 4 parts depends on sentence which I have put into variables in my code,I can able to extract here and get into console but I am not getting the whole text of inside the bracket,only I am getting first words.Here is the code below.Can anyone please help me.
HTML
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="messages">
SCRIPT
$(document).ready(function() {
regex = /.+(|d. w+/g;
maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
matches = maintext.match(regex);
text_split0 = matches[0].slice(0, -1);
text_split1 = matches[1];
text_split2 = matches[2];
text_split3 = matches[3];
text_split4 = matches[4];
console.log(text_split0);
console.log(text_split1);
console.log(text_split2);
console.log(text_split3);
console.log(text_split4);
$(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');
// $("li:contains('undefined')").remove()
});
javascript jquery html
add a comment |
I have a sentence stored in a variable.That sentence I need to extract into 4 parts depends on sentence which I have put into variables in my code,I can able to extract here and get into console but I am not getting the whole text of inside the bracket,only I am getting first words.Here is the code below.Can anyone please help me.
HTML
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="messages">
SCRIPT
$(document).ready(function() {
regex = /.+(|d. w+/g;
maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
matches = maintext.match(regex);
text_split0 = matches[0].slice(0, -1);
text_split1 = matches[1];
text_split2 = matches[2];
text_split3 = matches[3];
text_split4 = matches[4];
console.log(text_split0);
console.log(text_split1);
console.log(text_split2);
console.log(text_split3);
console.log(text_split4);
$(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');
// $("li:contains('undefined')").remove()
});
javascript jquery html
I have a sentence stored in a variable.That sentence I need to extract into 4 parts depends on sentence which I have put into variables in my code,I can able to extract here and get into console but I am not getting the whole text of inside the bracket,only I am getting first words.Here is the code below.Can anyone please help me.
HTML
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="messages">
SCRIPT
$(document).ready(function() {
regex = /.+(|d. w+/g;
maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
matches = maintext.match(regex);
text_split0 = matches[0].slice(0, -1);
text_split1 = matches[1];
text_split2 = matches[2];
text_split3 = matches[3];
text_split4 = matches[4];
console.log(text_split0);
console.log(text_split1);
console.log(text_split2);
console.log(text_split3);
console.log(text_split4);
$(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');
// $("li:contains('undefined')").remove()
});
javascript jquery html
javascript jquery html
edited Nov 21 '18 at 19:58
asked Nov 21 '18 at 19:30
carreankush
947
947
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
function buildMessages(text) {
let messages = text.split(/d.s/);
messages.shift();
messages.forEach((v)=>{
let msg = v.replace(/,/,'').replace(/sors/,'').trim();
$('.messages').append(`<li>${msg}</li>`);
// console.log(`<li>${msg}</li>`);
});
}
let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
buildMessages(sentenceToParse);
- Use the
split
function on the String, keying on the digits (e.g.1.
), you will get the preface and each of the steps into an array. - Use the
shift
function on the Array removes the unneeded preface. - Use
forEach
to iterate over the values in the array, clean up the text. - Using
replace
to first remove commas, then removeor
with spaces on either side. - Use
trim
to remove leading and training whitespace.
At this point, your array will have sanitized copy for use in your <li>
elements.
If you're only concerned with working through a regex and not re-factoring, the easiest way may be to use an online regex tool where you provide a few different string samples. Look at https://www.regextester.com/
1
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
add a comment |
Ok, Try another approach, cause regex for this isn't the best way. Try this:
$(document).ready(function() {
// First part of sentence.
var mainText = "Welcome to project, are you a here(";
// Users array.
var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];
var uSize = USERS.length;
// Construct string & user list dynamically.
for(var i = 0; i < uSize; i++) {
var li = $('<li/>').text(USERS[i]);
if(i === uSize - 1)
mainText += (i+1) + ". " + USERS[i] + ")";
else if(i === uSize - 2)
mainText += (i+1) + ". " + USERS[i] + " or ";
else
mainText += (i+1) + ". " + USERS[i] + " , ";
$(".messages").append(li);
}
console.log(mainText); // You will have you complete sentence.
}
Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
function buildMessages(text) {
let messages = text.split(/d.s/);
messages.shift();
messages.forEach((v)=>{
let msg = v.replace(/,/,'').replace(/sors/,'').trim();
$('.messages').append(`<li>${msg}</li>`);
// console.log(`<li>${msg}</li>`);
});
}
let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
buildMessages(sentenceToParse);
- Use the
split
function on the String, keying on the digits (e.g.1.
), you will get the preface and each of the steps into an array. - Use the
shift
function on the Array removes the unneeded preface. - Use
forEach
to iterate over the values in the array, clean up the text. - Using
replace
to first remove commas, then removeor
with spaces on either side. - Use
trim
to remove leading and training whitespace.
At this point, your array will have sanitized copy for use in your <li>
elements.
If you're only concerned with working through a regex and not re-factoring, the easiest way may be to use an online regex tool where you provide a few different string samples. Look at https://www.regextester.com/
1
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
add a comment |
function buildMessages(text) {
let messages = text.split(/d.s/);
messages.shift();
messages.forEach((v)=>{
let msg = v.replace(/,/,'').replace(/sors/,'').trim();
$('.messages').append(`<li>${msg}</li>`);
// console.log(`<li>${msg}</li>`);
});
}
let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
buildMessages(sentenceToParse);
- Use the
split
function on the String, keying on the digits (e.g.1.
), you will get the preface and each of the steps into an array. - Use the
shift
function on the Array removes the unneeded preface. - Use
forEach
to iterate over the values in the array, clean up the text. - Using
replace
to first remove commas, then removeor
with spaces on either side. - Use
trim
to remove leading and training whitespace.
At this point, your array will have sanitized copy for use in your <li>
elements.
If you're only concerned with working through a regex and not re-factoring, the easiest way may be to use an online regex tool where you provide a few different string samples. Look at https://www.regextester.com/
1
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
add a comment |
function buildMessages(text) {
let messages = text.split(/d.s/);
messages.shift();
messages.forEach((v)=>{
let msg = v.replace(/,/,'').replace(/sors/,'').trim();
$('.messages').append(`<li>${msg}</li>`);
// console.log(`<li>${msg}</li>`);
});
}
let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
buildMessages(sentenceToParse);
- Use the
split
function on the String, keying on the digits (e.g.1.
), you will get the preface and each of the steps into an array. - Use the
shift
function on the Array removes the unneeded preface. - Use
forEach
to iterate over the values in the array, clean up the text. - Using
replace
to first remove commas, then removeor
with spaces on either side. - Use
trim
to remove leading and training whitespace.
At this point, your array will have sanitized copy for use in your <li>
elements.
If you're only concerned with working through a regex and not re-factoring, the easiest way may be to use an online regex tool where you provide a few different string samples. Look at https://www.regextester.com/
function buildMessages(text) {
let messages = text.split(/d.s/);
messages.shift();
messages.forEach((v)=>{
let msg = v.replace(/,/,'').replace(/sors/,'').trim();
$('.messages').append(`<li>${msg}</li>`);
// console.log(`<li>${msg}</li>`);
});
}
let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";
buildMessages(sentenceToParse);
- Use the
split
function on the String, keying on the digits (e.g.1.
), you will get the preface and each of the steps into an array. - Use the
shift
function on the Array removes the unneeded preface. - Use
forEach
to iterate over the values in the array, clean up the text. - Using
replace
to first remove commas, then removeor
with spaces on either side. - Use
trim
to remove leading and training whitespace.
At this point, your array will have sanitized copy for use in your <li>
elements.
If you're only concerned with working through a regex and not re-factoring, the easiest way may be to use an online regex tool where you provide a few different string samples. Look at https://www.regextester.com/
edited Nov 21 '18 at 21:56
answered Nov 21 '18 at 20:02
CodeTheInternet
14
14
1
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
add a comment |
1
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
1
1
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.
– Stephen P
Nov 21 '18 at 20:05
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue
– carreankush
Nov 21 '18 at 20:23
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:34
add a comment |
Ok, Try another approach, cause regex for this isn't the best way. Try this:
$(document).ready(function() {
// First part of sentence.
var mainText = "Welcome to project, are you a here(";
// Users array.
var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];
var uSize = USERS.length;
// Construct string & user list dynamically.
for(var i = 0; i < uSize; i++) {
var li = $('<li/>').text(USERS[i]);
if(i === uSize - 1)
mainText += (i+1) + ". " + USERS[i] + ")";
else if(i === uSize - 2)
mainText += (i+1) + ". " + USERS[i] + " or ";
else
mainText += (i+1) + ". " + USERS[i] + " , ";
$(".messages").append(li);
}
console.log(mainText); // You will have you complete sentence.
}
Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
add a comment |
Ok, Try another approach, cause regex for this isn't the best way. Try this:
$(document).ready(function() {
// First part of sentence.
var mainText = "Welcome to project, are you a here(";
// Users array.
var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];
var uSize = USERS.length;
// Construct string & user list dynamically.
for(var i = 0; i < uSize; i++) {
var li = $('<li/>').text(USERS[i]);
if(i === uSize - 1)
mainText += (i+1) + ". " + USERS[i] + ")";
else if(i === uSize - 2)
mainText += (i+1) + ". " + USERS[i] + " or ";
else
mainText += (i+1) + ". " + USERS[i] + " , ";
$(".messages").append(li);
}
console.log(mainText); // You will have you complete sentence.
}
Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
add a comment |
Ok, Try another approach, cause regex for this isn't the best way. Try this:
$(document).ready(function() {
// First part of sentence.
var mainText = "Welcome to project, are you a here(";
// Users array.
var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];
var uSize = USERS.length;
// Construct string & user list dynamically.
for(var i = 0; i < uSize; i++) {
var li = $('<li/>').text(USERS[i]);
if(i === uSize - 1)
mainText += (i+1) + ". " + USERS[i] + ")";
else if(i === uSize - 2)
mainText += (i+1) + ". " + USERS[i] + " or ";
else
mainText += (i+1) + ". " + USERS[i] + " , ";
$(".messages").append(li);
}
console.log(mainText); // You will have you complete sentence.
}
Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.
Ok, Try another approach, cause regex for this isn't the best way. Try this:
$(document).ready(function() {
// First part of sentence.
var mainText = "Welcome to project, are you a here(";
// Users array.
var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];
var uSize = USERS.length;
// Construct string & user list dynamically.
for(var i = 0; i < uSize; i++) {
var li = $('<li/>').text(USERS[i]);
if(i === uSize - 1)
mainText += (i+1) + ". " + USERS[i] + ")";
else if(i === uSize - 2)
mainText += (i+1) + ". " + USERS[i] + " or ";
else
mainText += (i+1) + ". " + USERS[i] + " , ";
$(".messages").append(li);
}
console.log(mainText); // You will have you complete sentence.
}
Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.
edited Nov 22 '18 at 20:34
answered Nov 21 '18 at 20:10
Hexxefir
38329
38329
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
add a comment |
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major
– carreankush
Nov 21 '18 at 20:19
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;
– carreankush
Nov 21 '18 at 20:21
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident
– carreankush
Nov 21 '18 at 20:35
add a comment |
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