Using function inside of function, input occurs twice and once is desired
I'm trying to get input from the user once and then open those links. I tried fitting the first function inside of the second function, and it all works--but it asks me for the search item TWICE. I want this to happen once. How do I correct the logic?
import urllib.request
from bs4 import BeautifulSoup
import re
from collections import Counter
import string
from string import punctuation
from collections import OrderedDict
from bs4.element import Comment
import pandas as pd
import requests
import re
import numpy as np
def user_input():
brand = input("search item?")
link1 = 'https://google.com/search?q='+brand+'&u=&'
link2 = 'http://yahoo.com/?site=thedrive&q='+brand
link3 = 'https://www.bloomberg.com/'+brand+'/news/'
link4 = 'https://www.cnet.com/roadshow/make/'+brand+'/'
list1 = [link1,link2,link3,link4]
return list1
def request():
html_list =
list1 = user_input()
for item in list1:
with urllib.request.urlopen(item) as response:
html = response.read()
html_list.append(html)
return len(html_list)
user_input()
request()
python urllib
asked Nov 24 '18 at 0:02
SRG132SRG132
1
add a comment |
I'm trying to get input from the user once and then open those links. I tried fitting the first function inside of the second function, and it all works--but it asks me for the search item TWICE. I want this to happen once. How do I correct the logic?
import urllib.request
from bs4 import BeautifulSoup
import re
from collections import Counter
import string
from string import punctuation
from collections import OrderedDict
from bs4.element import Comment
import pandas as pd
import requests
import re
import numpy as np
def user_input():
brand = input("search item?")
link1 = 'https://google.com/search?q='+brand+'&u=&'
link2 = 'http://yahoo.com/?site=thedrive&q='+brand
link3 = 'https://www.bloomberg.com/'+brand+'/news/'
link4 = 'https://www.cnet.com/roadshow/make/'+brand+'/'
list1 = [link1,link2,link3,link4]
return list1
def request():
html_list =
list1 = user_input()
for item in list1:
with urllib.request.urlopen(item) as response:
html = response.read()
html_list.append(html)
return len(html_list)
user_input()
request()
python urllib
asked Nov 24 '18 at 0:02
SRG132SRG132
1
Mark as correct?
– John H
Nov 24 '18 at 4:09
add a comment |
I'm trying to get input from the user once and then open those links. I tried fitting the first function inside of the second function, and it all works--but it asks me for the search item TWICE. I want this to happen once. How do I correct the logic?
import urllib.request
from bs4 import BeautifulSoup
import re
from collections import Counter
import string
from string import punctuation
from collections import OrderedDict
from bs4.element import Comment
import pandas as pd
import requests
import re
import numpy as np
def user_input():
brand = input("search item?")
link1 = 'https://google.com/search?q='+brand+'&u=&'
link2 = 'http://yahoo.com/?site=thedrive&q='+brand
link3 = 'https://www.bloomberg.com/'+brand+'/news/'
link4 = 'https://www.cnet.com/roadshow/make/'+brand+'/'
list1 = [link1,link2,link3,link4]
return list1
def request():
html_list =
list1 = user_input()
for item in list1:
with urllib.request.urlopen(item) as response:
html = response.read()
html_list.append(html)
return len(html_list)
user_input()
request()
python urllib
asked Nov 24 '18 at 0:02
SRG132SRG132
1
I'm trying to get input from the user once and then open those links. I tried fitting the first function inside of the second function, and it all works--but it asks me for the search item TWICE. I want this to happen once. How do I correct the logic?
import urllib.request
from bs4 import BeautifulSoup
import re
from collections import Counter
import string
from string import punctuation
from collections import OrderedDict
from bs4.element import Comment
import pandas as pd
import requests
import re
import numpy as np
def user_input():
brand = input("search item?")
link1 = 'https://google.com/search?q='+brand+'&u=&'
link2 = 'http://yahoo.com/?site=thedrive&q='+brand
link3 = 'https://www.bloomberg.com/'+brand+'/news/'
link4 = 'https://www.cnet.com/roadshow/make/'+brand+'/'
list1 = [link1,link2,link3,link4]
return list1
def request():
html_list =
list1 = user_input()
for item in list1:
with urllib.request.urlopen(item) as response:
html = response.read()
html_list.append(html)
return len(html_list)
user_input()
request()
python urllib
python urllib
asked Nov 24 '18 at 0:02
SRG132SRG132
1
asked Nov 24 '18 at 0:02
SRG132SRG132
1
asked Nov 24 '18 at 0:02
SRG132SRG132
1
asked Nov 24 '18 at 0:02
SRG132SRG132
1
asked Nov 24 '18 at 0:02
SRG132SRG132
1
1
Mark as correct?
– John H
Nov 24 '18 at 4:09
add a comment |
Mark as correct?
– John H
Nov 24 '18 at 4:09
Mark as correct?
– John H
Nov 24 '18 at 4:09
Mark as correct?
– John H
Nov 24 '18 at 4:09
add a comment |
1 Answer
1
active
oldest
votes
You are calling user_input() twice. Remove the call in your second to last line of code and you should be good.
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
You are calling user_input() twice. Remove the call in your second to last line of code and you should be good.
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
add a comment |
You are calling user_input() twice. Remove the call in your second to last line of code and you should be good.
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
add a comment |
You are calling user_input() twice. Remove the call in your second to last line of code and you should be good.
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
You are calling user_input() twice. Remove the call in your second to last line of code and you should be good.
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
answered Nov 24 '18 at 0:07
John HJohn H
1,234415
1,234415
add a comment |
add a comment |
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Mark as correct?
– John H
Nov 24 '18 at 4:09