Definition of $C^k( overline{Omega})$











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What is the exact definition of $C^k( overline{Omega})$ with $Omega$ open set in $mathbb{R}^n$? The functions in that space have domanin $Omega$ or have domain $overline{Omega}$? Is there a general definition in manifold?










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  • The Banach space with norm $|f| = int_Omega (|f(x)|+sum_j |partial_j f(x)|)dx$ has a subspace of continuously differentiable functions on $Omega$. When $Omega$ has a complicated shape there is a smaller subspace which is the space of continuously differentiable functions on some open containing $overline{Omega}$.
    – reuns
    Nov 22 at 23:57

















up vote
0
down vote

favorite












What is the exact definition of $C^k( overline{Omega})$ with $Omega$ open set in $mathbb{R}^n$? The functions in that space have domanin $Omega$ or have domain $overline{Omega}$? Is there a general definition in manifold?










share|cite|improve this question






















  • The Banach space with norm $|f| = int_Omega (|f(x)|+sum_j |partial_j f(x)|)dx$ has a subspace of continuously differentiable functions on $Omega$. When $Omega$ has a complicated shape there is a smaller subspace which is the space of continuously differentiable functions on some open containing $overline{Omega}$.
    – reuns
    Nov 22 at 23:57















up vote
0
down vote

favorite









up vote
0
down vote

favorite











What is the exact definition of $C^k( overline{Omega})$ with $Omega$ open set in $mathbb{R}^n$? The functions in that space have domanin $Omega$ or have domain $overline{Omega}$? Is there a general definition in manifold?










share|cite|improve this question













What is the exact definition of $C^k( overline{Omega})$ with $Omega$ open set in $mathbb{R}^n$? The functions in that space have domanin $Omega$ or have domain $overline{Omega}$? Is there a general definition in manifold?







derivatives continuity partial-derivative






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asked Nov 22 at 21:45









asv

2561210




2561210












  • The Banach space with norm $|f| = int_Omega (|f(x)|+sum_j |partial_j f(x)|)dx$ has a subspace of continuously differentiable functions on $Omega$. When $Omega$ has a complicated shape there is a smaller subspace which is the space of continuously differentiable functions on some open containing $overline{Omega}$.
    – reuns
    Nov 22 at 23:57




















  • The Banach space with norm $|f| = int_Omega (|f(x)|+sum_j |partial_j f(x)|)dx$ has a subspace of continuously differentiable functions on $Omega$. When $Omega$ has a complicated shape there is a smaller subspace which is the space of continuously differentiable functions on some open containing $overline{Omega}$.
    – reuns
    Nov 22 at 23:57


















The Banach space with norm $|f| = int_Omega (|f(x)|+sum_j |partial_j f(x)|)dx$ has a subspace of continuously differentiable functions on $Omega$. When $Omega$ has a complicated shape there is a smaller subspace which is the space of continuously differentiable functions on some open containing $overline{Omega}$.
– reuns
Nov 22 at 23:57






The Banach space with norm $|f| = int_Omega (|f(x)|+sum_j |partial_j f(x)|)dx$ has a subspace of continuously differentiable functions on $Omega$. When $Omega$ has a complicated shape there is a smaller subspace which is the space of continuously differentiable functions on some open containing $overline{Omega}$.
– reuns
Nov 22 at 23:57












1 Answer
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1
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The definition I know is



$$
C^k(overline{Omega}) := { vrvert_{overline{Omega}} mid v in C^k(U) quad text{for some open} quad U supset overline{Omega} }.
$$



I don't know about the manifold part.






share|cite|improve this answer





















  • For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
    – reuns
    Nov 23 at 0:24












  • Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
    – asv
    Nov 23 at 11:57













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote













The definition I know is



$$
C^k(overline{Omega}) := { vrvert_{overline{Omega}} mid v in C^k(U) quad text{for some open} quad U supset overline{Omega} }.
$$



I don't know about the manifold part.






share|cite|improve this answer





















  • For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
    – reuns
    Nov 23 at 0:24












  • Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
    – asv
    Nov 23 at 11:57

















up vote
1
down vote













The definition I know is



$$
C^k(overline{Omega}) := { vrvert_{overline{Omega}} mid v in C^k(U) quad text{for some open} quad U supset overline{Omega} }.
$$



I don't know about the manifold part.






share|cite|improve this answer





















  • For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
    – reuns
    Nov 23 at 0:24












  • Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
    – asv
    Nov 23 at 11:57















up vote
1
down vote










up vote
1
down vote









The definition I know is



$$
C^k(overline{Omega}) := { vrvert_{overline{Omega}} mid v in C^k(U) quad text{for some open} quad U supset overline{Omega} }.
$$



I don't know about the manifold part.






share|cite|improve this answer












The definition I know is



$$
C^k(overline{Omega}) := { vrvert_{overline{Omega}} mid v in C^k(U) quad text{for some open} quad U supset overline{Omega} }.
$$



I don't know about the manifold part.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 22 at 23:54









Gonzalo Benavides

632317




632317












  • For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
    – reuns
    Nov 23 at 0:24












  • Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
    – asv
    Nov 23 at 11:57




















  • For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
    – reuns
    Nov 23 at 0:24












  • Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
    – asv
    Nov 23 at 11:57


















For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
– reuns
Nov 23 at 0:24






For (differentiable) manifolds it works the same way : for every point $p in Omega$, add to $Omega$ a small neighborhood of $p$ ? For the norm it would need fixing some charts around each $p$, or a metric in the tangent spaces
– reuns
Nov 23 at 0:24














Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
– asv
Nov 23 at 11:57






Thank you, have you some textbook reference? Hence the functions in that space have doamin $overline{Omega}$.
– asv
Nov 23 at 11:57




















 

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