select row having one kind of value only while missing other from a pair











up vote
0
down vote

favorite












I have to select row which has one kind of value in one row but not the other row, both row having a key entity common



Sample model :



+------+---------+---------------+
| key | status | arrival_p |
+------+---------+---------------+
| k1 | failure | came |
| k1 | success | gone |
| k2 | failure | came |
| k3 | success | came |
| k3 | failure | gone |
| k4 | success | came |
| k5 | success | came |
| k2 | success | gone |
| k6 | success | gone |
+------+---------+---------------+


so in this case, except for k4 and k5, all have come and gone. how can i find folks who have come but not gone??
k6 has just gone, so its an outlier, good to catch it but not immediate priority.



i tried below query but it doesn't work (i know of exact value in actual table which matches my description but below query returns no value at all) :



select ap1.`key`
from `arrival_pattern` ap1
left join `arrival_pattern` ap2
on ap1.`key` = ap2.`key`
where ap2.`key` is NULL
and ap1.`arrival_p` = 'came'
and ap2.`arrival_p` = 'gone'
limit 10;


any help or pointers in right direction as to what might be wrong in my join is helpful. i am on mysql.



TIA :)










share|improve this question






















  • Possible values for arrival_p are exclusively came and gone? For each key there's at most 1 record with arrival_p=came and at most 1 record with arrival_p=gone?
    – Robert Kock
    Nov 21 at 8:54










  • yes sir...its an enum from code with only possible values of came / gone, key + arrival_p have unique constraint
    – NoobEditor
    Nov 21 at 8:56

















up vote
0
down vote

favorite












I have to select row which has one kind of value in one row but not the other row, both row having a key entity common



Sample model :



+------+---------+---------------+
| key | status | arrival_p |
+------+---------+---------------+
| k1 | failure | came |
| k1 | success | gone |
| k2 | failure | came |
| k3 | success | came |
| k3 | failure | gone |
| k4 | success | came |
| k5 | success | came |
| k2 | success | gone |
| k6 | success | gone |
+------+---------+---------------+


so in this case, except for k4 and k5, all have come and gone. how can i find folks who have come but not gone??
k6 has just gone, so its an outlier, good to catch it but not immediate priority.



i tried below query but it doesn't work (i know of exact value in actual table which matches my description but below query returns no value at all) :



select ap1.`key`
from `arrival_pattern` ap1
left join `arrival_pattern` ap2
on ap1.`key` = ap2.`key`
where ap2.`key` is NULL
and ap1.`arrival_p` = 'came'
and ap2.`arrival_p` = 'gone'
limit 10;


any help or pointers in right direction as to what might be wrong in my join is helpful. i am on mysql.



TIA :)










share|improve this question






















  • Possible values for arrival_p are exclusively came and gone? For each key there's at most 1 record with arrival_p=came and at most 1 record with arrival_p=gone?
    – Robert Kock
    Nov 21 at 8:54










  • yes sir...its an enum from code with only possible values of came / gone, key + arrival_p have unique constraint
    – NoobEditor
    Nov 21 at 8:56















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have to select row which has one kind of value in one row but not the other row, both row having a key entity common



Sample model :



+------+---------+---------------+
| key | status | arrival_p |
+------+---------+---------------+
| k1 | failure | came |
| k1 | success | gone |
| k2 | failure | came |
| k3 | success | came |
| k3 | failure | gone |
| k4 | success | came |
| k5 | success | came |
| k2 | success | gone |
| k6 | success | gone |
+------+---------+---------------+


so in this case, except for k4 and k5, all have come and gone. how can i find folks who have come but not gone??
k6 has just gone, so its an outlier, good to catch it but not immediate priority.



i tried below query but it doesn't work (i know of exact value in actual table which matches my description but below query returns no value at all) :



select ap1.`key`
from `arrival_pattern` ap1
left join `arrival_pattern` ap2
on ap1.`key` = ap2.`key`
where ap2.`key` is NULL
and ap1.`arrival_p` = 'came'
and ap2.`arrival_p` = 'gone'
limit 10;


any help or pointers in right direction as to what might be wrong in my join is helpful. i am on mysql.



TIA :)










share|improve this question













I have to select row which has one kind of value in one row but not the other row, both row having a key entity common



Sample model :



+------+---------+---------------+
| key | status | arrival_p |
+------+---------+---------------+
| k1 | failure | came |
| k1 | success | gone |
| k2 | failure | came |
| k3 | success | came |
| k3 | failure | gone |
| k4 | success | came |
| k5 | success | came |
| k2 | success | gone |
| k6 | success | gone |
+------+---------+---------------+


so in this case, except for k4 and k5, all have come and gone. how can i find folks who have come but not gone??
k6 has just gone, so its an outlier, good to catch it but not immediate priority.



i tried below query but it doesn't work (i know of exact value in actual table which matches my description but below query returns no value at all) :



select ap1.`key`
from `arrival_pattern` ap1
left join `arrival_pattern` ap2
on ap1.`key` = ap2.`key`
where ap2.`key` is NULL
and ap1.`arrival_p` = 'came'
and ap2.`arrival_p` = 'gone'
limit 10;


any help or pointers in right direction as to what might be wrong in my join is helpful. i am on mysql.



TIA :)







mysql sql






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 at 8:42









NoobEditor

11.1k84878




11.1k84878












  • Possible values for arrival_p are exclusively came and gone? For each key there's at most 1 record with arrival_p=came and at most 1 record with arrival_p=gone?
    – Robert Kock
    Nov 21 at 8:54










  • yes sir...its an enum from code with only possible values of came / gone, key + arrival_p have unique constraint
    – NoobEditor
    Nov 21 at 8:56




















  • Possible values for arrival_p are exclusively came and gone? For each key there's at most 1 record with arrival_p=came and at most 1 record with arrival_p=gone?
    – Robert Kock
    Nov 21 at 8:54










  • yes sir...its an enum from code with only possible values of came / gone, key + arrival_p have unique constraint
    – NoobEditor
    Nov 21 at 8:56


















Possible values for arrival_p are exclusively came and gone? For each key there's at most 1 record with arrival_p=came and at most 1 record with arrival_p=gone?
– Robert Kock
Nov 21 at 8:54




Possible values for arrival_p are exclusively came and gone? For each key there's at most 1 record with arrival_p=came and at most 1 record with arrival_p=gone?
– Robert Kock
Nov 21 at 8:54












yes sir...its an enum from code with only possible values of came / gone, key + arrival_p have unique constraint
– NoobEditor
Nov 21 at 8:56






yes sir...its an enum from code with only possible values of came / gone, key + arrival_p have unique constraint
– NoobEditor
Nov 21 at 8:56














2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










Since both came and gone can appear only once for a specific key, you might as well select the elements for which a single record exists:



SELECT   `key`,
COUNT(*)
FROM arrival_pattern
GROUP BY `key`
HAVING COUNT(*) = 1;


This solves also the second question ('k6 has just gone').



Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.






share|improve this answer























  • ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
    – NoobEditor
    Nov 21 at 9:04






  • 1




    @NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
    – Madhur Bhaiya
    Nov 21 at 9:04








  • 1




    @MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
    – NoobEditor
    Nov 21 at 9:13










  • @NoobEditor ;) well I am not a telepath :P
    – Madhur Bhaiya
    Nov 21 at 9:14










  • If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
    – Zaynul Abadin Tuhin
    Nov 21 at 14:10




















up vote
1
down vote













use not exists



select t1.* from  arrival_pattern t1
where not exists ( select 1
from arrival_pattern t2
where t2.key=t1.key
and t2.arrival_p='gone')


you can try below self join



select t1.* arrival_pattern t1 
left join
(select key from
arrival_pattern t2 where arrival_p='gone'
) t2
on t1.key=t2.key where t2.key is null





share|improve this answer























  • any way using joins??
    – NoobEditor
    Nov 21 at 8:45










  • @NoobEditor yes you can use self join
    – Zaynul Abadin Tuhin
    Nov 21 at 8:46










  • what exactly is select 1 doing in not exist this case????
    – NoobEditor
    Nov 21 at 8:48








  • 1




    @NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
    – Zaynul Abadin Tuhin
    Nov 21 at 8:50













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










Since both came and gone can appear only once for a specific key, you might as well select the elements for which a single record exists:



SELECT   `key`,
COUNT(*)
FROM arrival_pattern
GROUP BY `key`
HAVING COUNT(*) = 1;


This solves also the second question ('k6 has just gone').



Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.






share|improve this answer























  • ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
    – NoobEditor
    Nov 21 at 9:04






  • 1




    @NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
    – Madhur Bhaiya
    Nov 21 at 9:04








  • 1




    @MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
    – NoobEditor
    Nov 21 at 9:13










  • @NoobEditor ;) well I am not a telepath :P
    – Madhur Bhaiya
    Nov 21 at 9:14










  • If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
    – Zaynul Abadin Tuhin
    Nov 21 at 14:10

















up vote
3
down vote



accepted










Since both came and gone can appear only once for a specific key, you might as well select the elements for which a single record exists:



SELECT   `key`,
COUNT(*)
FROM arrival_pattern
GROUP BY `key`
HAVING COUNT(*) = 1;


This solves also the second question ('k6 has just gone').



Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.






share|improve this answer























  • ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
    – NoobEditor
    Nov 21 at 9:04






  • 1




    @NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
    – Madhur Bhaiya
    Nov 21 at 9:04








  • 1




    @MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
    – NoobEditor
    Nov 21 at 9:13










  • @NoobEditor ;) well I am not a telepath :P
    – Madhur Bhaiya
    Nov 21 at 9:14










  • If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
    – Zaynul Abadin Tuhin
    Nov 21 at 14:10















up vote
3
down vote



accepted







up vote
3
down vote



accepted






Since both came and gone can appear only once for a specific key, you might as well select the elements for which a single record exists:



SELECT   `key`,
COUNT(*)
FROM arrival_pattern
GROUP BY `key`
HAVING COUNT(*) = 1;


This solves also the second question ('k6 has just gone').



Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.






share|improve this answer














Since both came and gone can appear only once for a specific key, you might as well select the elements for which a single record exists:



SELECT   `key`,
COUNT(*)
FROM arrival_pattern
GROUP BY `key`
HAVING COUNT(*) = 1;


This solves also the second question ('k6 has just gone').



Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 at 9:04









Madhur Bhaiya

18.5k62236




18.5k62236










answered Nov 21 at 9:01









Robert Kock

3,7541616




3,7541616












  • ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
    – NoobEditor
    Nov 21 at 9:04






  • 1




    @NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
    – Madhur Bhaiya
    Nov 21 at 9:04








  • 1




    @MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
    – NoobEditor
    Nov 21 at 9:13










  • @NoobEditor ;) well I am not a telepath :P
    – Madhur Bhaiya
    Nov 21 at 9:14










  • If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
    – Zaynul Abadin Tuhin
    Nov 21 at 14:10




















  • ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
    – NoobEditor
    Nov 21 at 9:04






  • 1




    @NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
    – Madhur Bhaiya
    Nov 21 at 9:04








  • 1




    @MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
    – NoobEditor
    Nov 21 at 9:13










  • @NoobEditor ;) well I am not a telepath :P
    – Madhur Bhaiya
    Nov 21 at 9:14










  • If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
    – Zaynul Abadin Tuhin
    Nov 21 at 14:10


















ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
– NoobEditor
Nov 21 at 9:04




ohh maannnn....sometimes overthinking kills the simple solution, this is clean +1!!!
– NoobEditor
Nov 21 at 9:04




1




1




@NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
– Madhur Bhaiya
Nov 21 at 9:04






@NoobEditor Also, note that key is a Reserved Keyword in MySQL. You should seriously consider naming your column to something else.
– Madhur Bhaiya
Nov 21 at 9:04






1




1




@MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
– NoobEditor
Nov 21 at 9:13




@MadhurBhaiya : this is just a reference schema buddy, dont go by my screen name, m not really that noob! :D
– NoobEditor
Nov 21 at 9:13












@NoobEditor ;) well I am not a telepath :P
– Madhur Bhaiya
Nov 21 at 9:14




@NoobEditor ;) well I am not a telepath :P
– Madhur Bhaiya
Nov 21 at 9:14












If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
– Zaynul Abadin Tuhin
Nov 21 at 14:10






If any key just contain 'gone' that key also return on this query but if your real data is like sample no exception that I thought then it will work fine
– Zaynul Abadin Tuhin
Nov 21 at 14:10














up vote
1
down vote













use not exists



select t1.* from  arrival_pattern t1
where not exists ( select 1
from arrival_pattern t2
where t2.key=t1.key
and t2.arrival_p='gone')


you can try below self join



select t1.* arrival_pattern t1 
left join
(select key from
arrival_pattern t2 where arrival_p='gone'
) t2
on t1.key=t2.key where t2.key is null





share|improve this answer























  • any way using joins??
    – NoobEditor
    Nov 21 at 8:45










  • @NoobEditor yes you can use self join
    – Zaynul Abadin Tuhin
    Nov 21 at 8:46










  • what exactly is select 1 doing in not exist this case????
    – NoobEditor
    Nov 21 at 8:48








  • 1




    @NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
    – Zaynul Abadin Tuhin
    Nov 21 at 8:50

















up vote
1
down vote













use not exists



select t1.* from  arrival_pattern t1
where not exists ( select 1
from arrival_pattern t2
where t2.key=t1.key
and t2.arrival_p='gone')


you can try below self join



select t1.* arrival_pattern t1 
left join
(select key from
arrival_pattern t2 where arrival_p='gone'
) t2
on t1.key=t2.key where t2.key is null





share|improve this answer























  • any way using joins??
    – NoobEditor
    Nov 21 at 8:45










  • @NoobEditor yes you can use self join
    – Zaynul Abadin Tuhin
    Nov 21 at 8:46










  • what exactly is select 1 doing in not exist this case????
    – NoobEditor
    Nov 21 at 8:48








  • 1




    @NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
    – Zaynul Abadin Tuhin
    Nov 21 at 8:50















up vote
1
down vote










up vote
1
down vote









use not exists



select t1.* from  arrival_pattern t1
where not exists ( select 1
from arrival_pattern t2
where t2.key=t1.key
and t2.arrival_p='gone')


you can try below self join



select t1.* arrival_pattern t1 
left join
(select key from
arrival_pattern t2 where arrival_p='gone'
) t2
on t1.key=t2.key where t2.key is null





share|improve this answer














use not exists



select t1.* from  arrival_pattern t1
where not exists ( select 1
from arrival_pattern t2
where t2.key=t1.key
and t2.arrival_p='gone')


you can try below self join



select t1.* arrival_pattern t1 
left join
(select key from
arrival_pattern t2 where arrival_p='gone'
) t2
on t1.key=t2.key where t2.key is null






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 at 8:48

























answered Nov 21 at 8:44









Zaynul Abadin Tuhin

10.8k2731




10.8k2731












  • any way using joins??
    – NoobEditor
    Nov 21 at 8:45










  • @NoobEditor yes you can use self join
    – Zaynul Abadin Tuhin
    Nov 21 at 8:46










  • what exactly is select 1 doing in not exist this case????
    – NoobEditor
    Nov 21 at 8:48








  • 1




    @NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
    – Zaynul Abadin Tuhin
    Nov 21 at 8:50




















  • any way using joins??
    – NoobEditor
    Nov 21 at 8:45










  • @NoobEditor yes you can use self join
    – Zaynul Abadin Tuhin
    Nov 21 at 8:46










  • what exactly is select 1 doing in not exist this case????
    – NoobEditor
    Nov 21 at 8:48








  • 1




    @NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
    – Zaynul Abadin Tuhin
    Nov 21 at 8:50


















any way using joins??
– NoobEditor
Nov 21 at 8:45




any way using joins??
– NoobEditor
Nov 21 at 8:45












@NoobEditor yes you can use self join
– Zaynul Abadin Tuhin
Nov 21 at 8:46




@NoobEditor yes you can use self join
– Zaynul Abadin Tuhin
Nov 21 at 8:46












what exactly is select 1 doing in not exist this case????
– NoobEditor
Nov 21 at 8:48






what exactly is select 1 doing in not exist this case????
– NoobEditor
Nov 21 at 8:48






1




1




@NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
– Zaynul Abadin Tuhin
Nov 21 at 8:50






@NoobEditor actually EXISTS operator returns true if the subquery returns one or more records so i select constant value 1 rather any column selection you can read docs of sql how exists work
– Zaynul Abadin Tuhin
Nov 21 at 8:50




















 

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