Evaluating this limit without Taylor $lim_{xtoinfty} frac{x^3sin(x)}{x^2+x+1}$
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I need help with this limit, and without using Taylor series
$$lim_{xtoinfty} frac{x^3sin(x)}{x^2+x+1}$$
limits
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up vote
-2
down vote
favorite
I need help with this limit, and without using Taylor series
$$lim_{xtoinfty} frac{x^3sin(x)}{x^2+x+1}$$
limits
Are you looking for that $frac{x^3sin x}{x^2+x+1}$?
– gimusi
Nov 22 at 22:34
If it is $displaystylelim_{xtoinfty}frac{x^3sin x}{x^2+x+1}$, then the limit obviously doesn't exist.
– egreg
Nov 22 at 22:36
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
I need help with this limit, and without using Taylor series
$$lim_{xtoinfty} frac{x^3sin(x)}{x^2+x+1}$$
limits
I need help with this limit, and without using Taylor series
$$lim_{xtoinfty} frac{x^3sin(x)}{x^2+x+1}$$
limits
limits
edited Nov 22 at 22:41
gimusi
88k74393
88k74393
asked Nov 22 at 22:32
Franco Cabrera
64
64
Are you looking for that $frac{x^3sin x}{x^2+x+1}$?
– gimusi
Nov 22 at 22:34
If it is $displaystylelim_{xtoinfty}frac{x^3sin x}{x^2+x+1}$, then the limit obviously doesn't exist.
– egreg
Nov 22 at 22:36
add a comment |
Are you looking for that $frac{x^3sin x}{x^2+x+1}$?
– gimusi
Nov 22 at 22:34
If it is $displaystylelim_{xtoinfty}frac{x^3sin x}{x^2+x+1}$, then the limit obviously doesn't exist.
– egreg
Nov 22 at 22:36
Are you looking for that $frac{x^3sin x}{x^2+x+1}$?
– gimusi
Nov 22 at 22:34
Are you looking for that $frac{x^3sin x}{x^2+x+1}$?
– gimusi
Nov 22 at 22:34
If it is $displaystylelim_{xtoinfty}frac{x^3sin x}{x^2+x+1}$, then the limit obviously doesn't exist.
– egreg
Nov 22 at 22:36
If it is $displaystylelim_{xtoinfty}frac{x^3sin x}{x^2+x+1}$, then the limit obviously doesn't exist.
– egreg
Nov 22 at 22:36
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
HINT
Let consider
for $x_n=2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to,?$
for $x_n=frac{pi}2+2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to ,?$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
HINT
Let consider
for $x_n=2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to,?$
for $x_n=frac{pi}2+2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to ,?$
add a comment |
up vote
2
down vote
HINT
Let consider
for $x_n=2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to,?$
for $x_n=frac{pi}2+2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to ,?$
add a comment |
up vote
2
down vote
up vote
2
down vote
HINT
Let consider
for $x_n=2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to,?$
for $x_n=frac{pi}2+2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to ,?$
HINT
Let consider
for $x_n=2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to,?$
for $x_n=frac{pi}2+2pi nto infty implies frac{x_n^3sin x_n}{x_n^2+x_n+1}to ,?$
answered Nov 22 at 22:37
gimusi
88k74393
88k74393
add a comment |
add a comment |
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Are you looking for that $frac{x^3sin x}{x^2+x+1}$?
– gimusi
Nov 22 at 22:34
If it is $displaystylelim_{xtoinfty}frac{x^3sin x}{x^2+x+1}$, then the limit obviously doesn't exist.
– egreg
Nov 22 at 22:36