Quadratic simultaneous equations with three variables











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I am looking for an analytical solution of the following quadratic simultaneous equations.
$$(1) x^2-a_0(b_0-x-z)(c_0-y-x)=0$$
$$(2) y^2-a_1(b_1-y-x)(c_1-z-y)=0$$
$$(3) z^2-a_2(b_2-z-y)(c_2-x-z)=0$$
where $x$, $y$, and $z$ are variables; $a_i$, $b_i$, and $c_i$ ($i=0,1,2$) are constants.



I tried with Maple, but i couldn't get the solution...










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  • Welcome to math.SE, can you explain more? like where you faced problem in using Maple?
    – tarit goswami
    Nov 22 at 9:16

















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0
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I am looking for an analytical solution of the following quadratic simultaneous equations.
$$(1) x^2-a_0(b_0-x-z)(c_0-y-x)=0$$
$$(2) y^2-a_1(b_1-y-x)(c_1-z-y)=0$$
$$(3) z^2-a_2(b_2-z-y)(c_2-x-z)=0$$
where $x$, $y$, and $z$ are variables; $a_i$, $b_i$, and $c_i$ ($i=0,1,2$) are constants.



I tried with Maple, but i couldn't get the solution...










share|cite|improve this question







New contributor




Sun Yong Kwon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Welcome to math.SE, can you explain more? like where you faced problem in using Maple?
    – tarit goswami
    Nov 22 at 9:16















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am looking for an analytical solution of the following quadratic simultaneous equations.
$$(1) x^2-a_0(b_0-x-z)(c_0-y-x)=0$$
$$(2) y^2-a_1(b_1-y-x)(c_1-z-y)=0$$
$$(3) z^2-a_2(b_2-z-y)(c_2-x-z)=0$$
where $x$, $y$, and $z$ are variables; $a_i$, $b_i$, and $c_i$ ($i=0,1,2$) are constants.



I tried with Maple, but i couldn't get the solution...










share|cite|improve this question







New contributor




Sun Yong Kwon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I am looking for an analytical solution of the following quadratic simultaneous equations.
$$(1) x^2-a_0(b_0-x-z)(c_0-y-x)=0$$
$$(2) y^2-a_1(b_1-y-x)(c_1-z-y)=0$$
$$(3) z^2-a_2(b_2-z-y)(c_2-x-z)=0$$
where $x$, $y$, and $z$ are variables; $a_i$, $b_i$, and $c_i$ ($i=0,1,2$) are constants.



I tried with Maple, but i couldn't get the solution...







systems-of-equations nonlinear-system






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Sun Yong Kwon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked Nov 22 at 9:12









Sun Yong Kwon

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1




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New contributor





Sun Yong Kwon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Sun Yong Kwon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Welcome to math.SE, can you explain more? like where you faced problem in using Maple?
    – tarit goswami
    Nov 22 at 9:16




















  • Welcome to math.SE, can you explain more? like where you faced problem in using Maple?
    – tarit goswami
    Nov 22 at 9:16


















Welcome to math.SE, can you explain more? like where you faced problem in using Maple?
– tarit goswami
Nov 22 at 9:16






Welcome to math.SE, can you explain more? like where you faced problem in using Maple?
– tarit goswami
Nov 22 at 9:16












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I think that you are facing a monster !



You could reduce the problem to two equations $x,y$ eliminating $z$ from equation $(1)$. Replacing in $(2)$ and $(3)$ is just awful. You should end with a polynomial of degree $6$ in $x$ or $y$. Then, this explains that.



For illustration purposes, I used $a_i=i+1$, $b_i=a_i+1$, $c_i=b_i+1$ $(i=0,1,2)$. There are six real solutions ${x_k,y_k,z_k}$ $(k=1,2,cdots,6)$, which express as functions of the roots of polynomial
$$t^6-324 t^4+3312 t^3-12276 t^2+19008 t-10368=0$$






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    1 Answer
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    I think that you are facing a monster !



    You could reduce the problem to two equations $x,y$ eliminating $z$ from equation $(1)$. Replacing in $(2)$ and $(3)$ is just awful. You should end with a polynomial of degree $6$ in $x$ or $y$. Then, this explains that.



    For illustration purposes, I used $a_i=i+1$, $b_i=a_i+1$, $c_i=b_i+1$ $(i=0,1,2)$. There are six real solutions ${x_k,y_k,z_k}$ $(k=1,2,cdots,6)$, which express as functions of the roots of polynomial
    $$t^6-324 t^4+3312 t^3-12276 t^2+19008 t-10368=0$$






    share|cite|improve this answer

























      up vote
      0
      down vote













      I think that you are facing a monster !



      You could reduce the problem to two equations $x,y$ eliminating $z$ from equation $(1)$. Replacing in $(2)$ and $(3)$ is just awful. You should end with a polynomial of degree $6$ in $x$ or $y$. Then, this explains that.



      For illustration purposes, I used $a_i=i+1$, $b_i=a_i+1$, $c_i=b_i+1$ $(i=0,1,2)$. There are six real solutions ${x_k,y_k,z_k}$ $(k=1,2,cdots,6)$, which express as functions of the roots of polynomial
      $$t^6-324 t^4+3312 t^3-12276 t^2+19008 t-10368=0$$






      share|cite|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        I think that you are facing a monster !



        You could reduce the problem to two equations $x,y$ eliminating $z$ from equation $(1)$. Replacing in $(2)$ and $(3)$ is just awful. You should end with a polynomial of degree $6$ in $x$ or $y$. Then, this explains that.



        For illustration purposes, I used $a_i=i+1$, $b_i=a_i+1$, $c_i=b_i+1$ $(i=0,1,2)$. There are six real solutions ${x_k,y_k,z_k}$ $(k=1,2,cdots,6)$, which express as functions of the roots of polynomial
        $$t^6-324 t^4+3312 t^3-12276 t^2+19008 t-10368=0$$






        share|cite|improve this answer












        I think that you are facing a monster !



        You could reduce the problem to two equations $x,y$ eliminating $z$ from equation $(1)$. Replacing in $(2)$ and $(3)$ is just awful. You should end with a polynomial of degree $6$ in $x$ or $y$. Then, this explains that.



        For illustration purposes, I used $a_i=i+1$, $b_i=a_i+1$, $c_i=b_i+1$ $(i=0,1,2)$. There are six real solutions ${x_k,y_k,z_k}$ $(k=1,2,cdots,6)$, which express as functions of the roots of polynomial
        $$t^6-324 t^4+3312 t^3-12276 t^2+19008 t-10368=0$$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 22 at 10:07









        Claude Leibovici

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