C# - Play videos from resources in wmp component

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0
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I have a wmp component in a C# Windows Forms and i want it to play a video (.avi) from the solution's resources. I need to know the code for the wmp component to find the video. Suggestions?

asked Jul 1 '13 at 17:24

Lucas Dias

1013

Here come the downvotes...
– Brian
Jul 1 '13 at 17:29

What did you so far? Post some Code.
– Smartis
Jul 1 '13 at 17:29

1

@Brian always the same -.-
– Smartis
Jul 1 '13 at 17:29

add a comment |

up vote
0
down vote

favorite

I have a wmp component in a C# Windows Forms and i want it to play a video (.avi) from the solution's resources. I need to know the code for the wmp component to find the video. Suggestions?

asked Jul 1 '13 at 17:24

Lucas Dias

1013

Here come the downvotes...
– Brian
Jul 1 '13 at 17:29

What did you so far? Post some Code.
– Smartis
Jul 1 '13 at 17:29

1

@Brian always the same -.-
– Smartis
Jul 1 '13 at 17:29

add a comment |

up vote
0
down vote

favorite

I have a wmp component in a C# Windows Forms and i want it to play a video (.avi) from the solution's resources. I need to know the code for the wmp component to find the video. Suggestions?

asked Jul 1 '13 at 17:24

Lucas Dias

1013

I have a wmp component in a C# Windows Forms and i want it to play a video (.avi) from the solution's resources. I need to know the code for the wmp component to find the video. Suggestions?

c# video resources wmp

asked Jul 1 '13 at 17:24

Lucas Dias

1013

asked Jul 1 '13 at 17:24

Lucas Dias

1013

asked Jul 1 '13 at 17:24

Lucas Dias

1013

asked Jul 1 '13 at 17:24

Lucas Dias

1013

asked Jul 1 '13 at 17:24

Lucas Dias

1013

Here come the downvotes...
– Brian
Jul 1 '13 at 17:29

What did you so far? Post some Code.
– Smartis
Jul 1 '13 at 17:29

1

@Brian always the same -.-
– Smartis
Jul 1 '13 at 17:29

add a comment |

Here come the downvotes...
– Brian
Jul 1 '13 at 17:29

What did you so far? Post some Code.
– Smartis
Jul 1 '13 at 17:29

1

@Brian always the same -.-
– Smartis
Jul 1 '13 at 17:29

Here come the downvotes...
– Brian
Jul 1 '13 at 17:29

What did you so far? Post some Code.
– Smartis
Jul 1 '13 at 17:29

@Brian always the same -.-
– Smartis
Jul 1 '13 at 17:29

add a comment |

1 Answer
1

active

oldest

votes

up vote
4
down vote

accepted

Currently there is a way over streaming the file.

First of all, we need a place where it should be always possible

        string streamPath = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + @"";

Next Step an Instance of the MediaPlayer

    WindowsMediaPlayer wmp = new WindowsMediaPlayer();

Then we need to stream the Assembly Resource

    Stream stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("Smartis.Resources.Natur.wmv");



    using (Stream output = new FileStream (streamPath + "mediafile.avi", FileMode.Create))

    {

        byte buffer = new byte[32*1024];

        int read;



        while ( (read= stream.Read(buffer, 0, buffer.Length)) > 0)

        {

            output.Write(buffer, 0, read);

        }

    }

Finally we should be able to load the file.

    wmp.URL = streamPath + "mediafile.avi";

    wmp.controls.play();

After playing don't forget to clear the folder:

    File.Delete(streamPath + "mediafile.avi");

edited Jul 1 '13 at 18:35

answered Jul 1 '13 at 17:43

Smartis

4,14832440

This won't work because the video is not located in an URL, it's in the resources of the program
– Lucas Dias
Jul 1 '13 at 17:53

1

Gentlemen, you had my curiosity. But now you have my attention. Upvote
– Smartis
Jul 1 '13 at 18:00

@LucasDias: Try this...
– Smartis
Jul 1 '13 at 18:38

thank you good sir ^^
– Lucas Dias
Jul 1 '13 at 18:58

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
4
down vote

accepted

Currently there is a way over streaming the file.

First of all, we need a place where it should be always possible

        string streamPath = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + @"";

Next Step an Instance of the MediaPlayer

    WindowsMediaPlayer wmp = new WindowsMediaPlayer();

Then we need to stream the Assembly Resource

    Stream stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("Smartis.Resources.Natur.wmv");



    using (Stream output = new FileStream (streamPath + "mediafile.avi", FileMode.Create))

    {

        byte buffer = new byte[32*1024];

        int read;



        while ( (read= stream.Read(buffer, 0, buffer.Length)) > 0)

        {

            output.Write(buffer, 0, read);

        }

    }

Finally we should be able to load the file.

    wmp.URL = streamPath + "mediafile.avi";

    wmp.controls.play();

After playing don't forget to clear the folder:

    File.Delete(streamPath + "mediafile.avi");

edited Jul 1 '13 at 18:35

answered Jul 1 '13 at 17:43

Smartis

4,14832440

This won't work because the video is not located in an URL, it's in the resources of the program
– Lucas Dias
Jul 1 '13 at 17:53

1

Gentlemen, you had my curiosity. But now you have my attention. Upvote
– Smartis
Jul 1 '13 at 18:00

@LucasDias: Try this...
– Smartis
Jul 1 '13 at 18:38

thank you good sir ^^
– Lucas Dias
Jul 1 '13 at 18:58

add a comment |

up vote
4
down vote

accepted

Currently there is a way over streaming the file.

First of all, we need a place where it should be always possible

        string streamPath = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + @"";

Next Step an Instance of the MediaPlayer

    WindowsMediaPlayer wmp = new WindowsMediaPlayer();

Then we need to stream the Assembly Resource

    Stream stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("Smartis.Resources.Natur.wmv");



    using (Stream output = new FileStream (streamPath + "mediafile.avi", FileMode.Create))

    {

        byte buffer = new byte[32*1024];

        int read;



        while ( (read= stream.Read(buffer, 0, buffer.Length)) > 0)

        {

            output.Write(buffer, 0, read);

        }

    }

Finally we should be able to load the file.

    wmp.URL = streamPath + "mediafile.avi";

    wmp.controls.play();

After playing don't forget to clear the folder:

    File.Delete(streamPath + "mediafile.avi");

edited Jul 1 '13 at 18:35

answered Jul 1 '13 at 17:43

Smartis

4,14832440

This won't work because the video is not located in an URL, it's in the resources of the program
– Lucas Dias
Jul 1 '13 at 17:53

1

Gentlemen, you had my curiosity. But now you have my attention. Upvote
– Smartis
Jul 1 '13 at 18:00

@LucasDias: Try this...
– Smartis
Jul 1 '13 at 18:38

thank you good sir ^^
– Lucas Dias
Jul 1 '13 at 18:58

add a comment |

up vote
4
down vote

accepted

Currently there is a way over streaming the file.

First of all, we need a place where it should be always possible

        string streamPath = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + @"";

Next Step an Instance of the MediaPlayer

    WindowsMediaPlayer wmp = new WindowsMediaPlayer();

Then we need to stream the Assembly Resource

    Stream stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("Smartis.Resources.Natur.wmv");



    using (Stream output = new FileStream (streamPath + "mediafile.avi", FileMode.Create))

    {

        byte buffer = new byte[32*1024];

        int read;



        while ( (read= stream.Read(buffer, 0, buffer.Length)) > 0)

        {

            output.Write(buffer, 0, read);

        }

    }

Finally we should be able to load the file.

    wmp.URL = streamPath + "mediafile.avi";

    wmp.controls.play();

After playing don't forget to clear the folder:

    File.Delete(streamPath + "mediafile.avi");

edited Jul 1 '13 at 18:35

answered Jul 1 '13 at 17:43

Smartis

4,14832440

Currently there is a way over streaming the file.

First of all, we need a place where it should be always possible

        string streamPath = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData) + @"";

Next Step an Instance of the MediaPlayer

    WindowsMediaPlayer wmp = new WindowsMediaPlayer();

Then we need to stream the Assembly Resource

    Stream stream = Assembly.GetExecutingAssembly().GetManifestResourceStream("Smartis.Resources.Natur.wmv");



    using (Stream output = new FileStream (streamPath + "mediafile.avi", FileMode.Create))

    {

        byte buffer = new byte[32*1024];

        int read;



        while ( (read= stream.Read(buffer, 0, buffer.Length)) > 0)

        {

            output.Write(buffer, 0, read);

        }

    }

Finally we should be able to load the file.

    wmp.URL = streamPath + "mediafile.avi";

    wmp.controls.play();

After playing don't forget to clear the folder:

    File.Delete(streamPath + "mediafile.avi");

edited Jul 1 '13 at 18:35

answered Jul 1 '13 at 17:43

Smartis

4,14832440

edited Jul 1 '13 at 18:35

answered Jul 1 '13 at 17:43

Smartis

4,14832440

answered Jul 1 '13 at 17:43

Smartis

4,14832440

answered Jul 1 '13 at 17:43

Smartis

4,14832440

This won't work because the video is not located in an URL, it's in the resources of the program
– Lucas Dias
Jul 1 '13 at 17:53

1

Gentlemen, you had my curiosity. But now you have my attention. Upvote
– Smartis
Jul 1 '13 at 18:00

@LucasDias: Try this...
– Smartis
Jul 1 '13 at 18:38

thank you good sir ^^
– Lucas Dias
Jul 1 '13 at 18:58

add a comment |

This won't work because the video is not located in an URL, it's in the resources of the program
– Lucas Dias
Jul 1 '13 at 17:53

1

Gentlemen, you had my curiosity. But now you have my attention. Upvote
– Smartis
Jul 1 '13 at 18:00

@LucasDias: Try this...
– Smartis
Jul 1 '13 at 18:38

thank you good sir ^^
– Lucas Dias
Jul 1 '13 at 18:58

This won't work because the video is not located in an URL, it's in the resources of the program
– Lucas Dias
Jul 1 '13 at 17:53

Gentlemen, you had my curiosity. But now you have my attention. Upvote
– Smartis
Jul 1 '13 at 18:00

@LucasDias: Try this...
– Smartis
Jul 1 '13 at 18:38

thank you good sir ^^
– Lucas Dias
Jul 1 '13 at 18:58

add a comment |

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