How to show Sup over bigger set is bigger and Inf over bigger set is lesser?











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Let $A,B in mathbb{R}^n$ be two subset such that $A subseteq B$. Also, let $f:mathbb{R}^n rightarrow mathbb{R}$ be a real-valued function.



I always use



$$sup_Af(x) leq sup_Bf(x)$$



That perfectly makes sense to me, but is there any proof for the above inequality?



Also for the following



$$inf_Bf(x) leq inf_Af(x)$$










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    up vote
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    down vote

    favorite












    Let $A,B in mathbb{R}^n$ be two subset such that $A subseteq B$. Also, let $f:mathbb{R}^n rightarrow mathbb{R}$ be a real-valued function.



    I always use



    $$sup_Af(x) leq sup_Bf(x)$$



    That perfectly makes sense to me, but is there any proof for the above inequality?



    Also for the following



    $$inf_Bf(x) leq inf_Af(x)$$










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Let $A,B in mathbb{R}^n$ be two subset such that $A subseteq B$. Also, let $f:mathbb{R}^n rightarrow mathbb{R}$ be a real-valued function.



      I always use



      $$sup_Af(x) leq sup_Bf(x)$$



      That perfectly makes sense to me, but is there any proof for the above inequality?



      Also for the following



      $$inf_Bf(x) leq inf_Af(x)$$










      share|cite|improve this question













      Let $A,B in mathbb{R}^n$ be two subset such that $A subseteq B$. Also, let $f:mathbb{R}^n rightarrow mathbb{R}$ be a real-valued function.



      I always use



      $$sup_Af(x) leq sup_Bf(x)$$



      That perfectly makes sense to me, but is there any proof for the above inequality?



      Also for the following



      $$inf_Bf(x) leq inf_Af(x)$$







      real-analysis functions supremum-and-infimum






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      asked Nov 25 at 19:08









      Saeed

      465110




      465110






















          2 Answers
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          Hint: $sup_{xin B}f(x)$ is an upper bound of the set ${f(x),|,xin A}$.






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            Let $xin A$. Then in particular $xin B$ and $f(x)geq inf_{xin B}f(x)$. So $inf_{xin B}f(x)$ is a lower bound for the values of $f(x)$ on $xin A$. In particular $inf_{xin A}f(x)geq inf_{xin B}f(x)$.






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              2 Answers
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              2 Answers
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              active

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              up vote
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              down vote













              Hint: $sup_{xin B}f(x)$ is an upper bound of the set ${f(x),|,xin A}$.






              share|cite|improve this answer

























                up vote
                1
                down vote













                Hint: $sup_{xin B}f(x)$ is an upper bound of the set ${f(x),|,xin A}$.






                share|cite|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  Hint: $sup_{xin B}f(x)$ is an upper bound of the set ${f(x),|,xin A}$.






                  share|cite|improve this answer












                  Hint: $sup_{xin B}f(x)$ is an upper bound of the set ${f(x),|,xin A}$.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 25 at 19:11









                  José Carlos Santos

                  144k20113214




                  144k20113214






















                      up vote
                      1
                      down vote













                      Let $xin A$. Then in particular $xin B$ and $f(x)geq inf_{xin B}f(x)$. So $inf_{xin B}f(x)$ is a lower bound for the values of $f(x)$ on $xin A$. In particular $inf_{xin A}f(x)geq inf_{xin B}f(x)$.






                      share|cite|improve this answer

























                        up vote
                        1
                        down vote













                        Let $xin A$. Then in particular $xin B$ and $f(x)geq inf_{xin B}f(x)$. So $inf_{xin B}f(x)$ is a lower bound for the values of $f(x)$ on $xin A$. In particular $inf_{xin A}f(x)geq inf_{xin B}f(x)$.






                        share|cite|improve this answer























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                          up vote
                          1
                          down vote









                          Let $xin A$. Then in particular $xin B$ and $f(x)geq inf_{xin B}f(x)$. So $inf_{xin B}f(x)$ is a lower bound for the values of $f(x)$ on $xin A$. In particular $inf_{xin A}f(x)geq inf_{xin B}f(x)$.






                          share|cite|improve this answer












                          Let $xin A$. Then in particular $xin B$ and $f(x)geq inf_{xin B}f(x)$. So $inf_{xin B}f(x)$ is a lower bound for the values of $f(x)$ on $xin A$. In particular $inf_{xin A}f(x)geq inf_{xin B}f(x)$.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered Nov 25 at 19:11









                          Foobaz John

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                          20.2k41250






























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