solve for y: $xy'=y^2-2y$











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$$xy'=y^2-2y$$ $$y(1) = 1, x >= 0$$



I get $C = 0$ which gives:



$$left| frac{y}{y-2}right|=x^2$$ When solving for $y$ it gives $$frac{2x^2}{1+x^2}$$, however the correct answer should be $$frac{2}{1+x^2}$$.



Is $$left| frac{y}{y-2}right|=x^2$$ correct? And if it is, how to continue from there?










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    up vote
    0
    down vote

    favorite












    $$xy'=y^2-2y$$ $$y(1) = 1, x >= 0$$



    I get $C = 0$ which gives:



    $$left| frac{y}{y-2}right|=x^2$$ When solving for $y$ it gives $$frac{2x^2}{1+x^2}$$, however the correct answer should be $$frac{2}{1+x^2}$$.



    Is $$left| frac{y}{y-2}right|=x^2$$ correct? And if it is, how to continue from there?










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      $$xy'=y^2-2y$$ $$y(1) = 1, x >= 0$$



      I get $C = 0$ which gives:



      $$left| frac{y}{y-2}right|=x^2$$ When solving for $y$ it gives $$frac{2x^2}{1+x^2}$$, however the correct answer should be $$frac{2}{1+x^2}$$.



      Is $$left| frac{y}{y-2}right|=x^2$$ correct? And if it is, how to continue from there?










      share|cite|improve this question













      $$xy'=y^2-2y$$ $$y(1) = 1, x >= 0$$



      I get $C = 0$ which gives:



      $$left| frac{y}{y-2}right|=x^2$$ When solving for $y$ it gives $$frac{2x^2}{1+x^2}$$, however the correct answer should be $$frac{2}{1+x^2}$$.



      Is $$left| frac{y}{y-2}right|=x^2$$ correct? And if it is, how to continue from there?







      differential-equations






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      asked May 19 '14 at 11:18









      iveqy

      721816




      721816






















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          (2018-11-25) "Amusing" revenge downvote, four years later.




          Instead, try $$left| frac{y-2}{y}right|=x^2.$$






          share|cite|improve this answer























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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            -1
            down vote



            accepted











            (2018-11-25) "Amusing" revenge downvote, four years later.




            Instead, try $$left| frac{y-2}{y}right|=x^2.$$






            share|cite|improve this answer



























              up vote
              -1
              down vote



              accepted











              (2018-11-25) "Amusing" revenge downvote, four years later.




              Instead, try $$left| frac{y-2}{y}right|=x^2.$$






              share|cite|improve this answer

























                up vote
                -1
                down vote



                accepted







                up vote
                -1
                down vote



                accepted







                (2018-11-25) "Amusing" revenge downvote, four years later.




                Instead, try $$left| frac{y-2}{y}right|=x^2.$$






                share|cite|improve this answer















                (2018-11-25) "Amusing" revenge downvote, four years later.




                Instead, try $$left| frac{y-2}{y}right|=x^2.$$







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Nov 25 at 17:55

























                answered May 19 '14 at 11:28









                Did

                245k23217452




                245k23217452






























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