A difficulty in understanding a part of a paragraph in P.41 in Guillemin & Pollack (2)
The paragraph is given below:
But I do not understand:
1-In the forth line why we can not have the case $df_{x} =$ constant other than 0, could anyone explain this for me please?
2-In the sixth line how f is simply the first coordinate function, could anyone give me a concrete example for describing this please?
3-In the tenth line I could not understand why the authors said "But if $f(x)$ ia an extreme value, then obviously $f$ can not be a coordinate function near x" , could anyone explain this statement for me please may be by a concrete example?
thank!
general-topology differential-geometry algebraic-topology differential-topology
|
show 5 more comments
The paragraph is given below:
But I do not understand:
1-In the forth line why we can not have the case $df_{x} =$ constant other than 0, could anyone explain this for me please?
2-In the sixth line how f is simply the first coordinate function, could anyone give me a concrete example for describing this please?
3-In the tenth line I could not understand why the authors said "But if $f(x)$ ia an extreme value, then obviously $f$ can not be a coordinate function near x" , could anyone explain this statement for me please may be by a concrete example?
thank!
general-topology differential-geometry algebraic-topology differential-topology
1. $df_x$ is a linear map of vector spaces, so how many such constant maps could it be?
– Randall
Dec 5 '18 at 3:42
you mean $f$ is a linear map of vector spaces or $df$? @Randall
– hopefully
Dec 5 '18 at 3:46
Check the definitions: given $f: X to Y$ a smooth map, $df_x$ is a linear transformation $df_x: T_xM to T_{f(x)}N$.
– Randall
Dec 5 '18 at 3:48
So by this definition since the differential(derivative) of a linear map is the linear map itself .... I do not know the answer for your first question .... I am confused.@Randall
– hopefully
Dec 5 '18 at 3:52
1
You are confusing the concept of linear function from elementary mathematics with the concept of a linear transformation of vector spaces that occurs in linear algebra. There is a connection between the two, but they are not the same thing.
– Justin Young
Dec 5 '18 at 15:01
|
show 5 more comments
The paragraph is given below:
But I do not understand:
1-In the forth line why we can not have the case $df_{x} =$ constant other than 0, could anyone explain this for me please?
2-In the sixth line how f is simply the first coordinate function, could anyone give me a concrete example for describing this please?
3-In the tenth line I could not understand why the authors said "But if $f(x)$ ia an extreme value, then obviously $f$ can not be a coordinate function near x" , could anyone explain this statement for me please may be by a concrete example?
thank!
general-topology differential-geometry algebraic-topology differential-topology
The paragraph is given below:
But I do not understand:
1-In the forth line why we can not have the case $df_{x} =$ constant other than 0, could anyone explain this for me please?
2-In the sixth line how f is simply the first coordinate function, could anyone give me a concrete example for describing this please?
3-In the tenth line I could not understand why the authors said "But if $f(x)$ ia an extreme value, then obviously $f$ can not be a coordinate function near x" , could anyone explain this statement for me please may be by a concrete example?
thank!
general-topology differential-geometry algebraic-topology differential-topology
general-topology differential-geometry algebraic-topology differential-topology
asked Dec 5 '18 at 3:33
hopefullyhopefully
129112
129112
1. $df_x$ is a linear map of vector spaces, so how many such constant maps could it be?
– Randall
Dec 5 '18 at 3:42
you mean $f$ is a linear map of vector spaces or $df$? @Randall
– hopefully
Dec 5 '18 at 3:46
Check the definitions: given $f: X to Y$ a smooth map, $df_x$ is a linear transformation $df_x: T_xM to T_{f(x)}N$.
– Randall
Dec 5 '18 at 3:48
So by this definition since the differential(derivative) of a linear map is the linear map itself .... I do not know the answer for your first question .... I am confused.@Randall
– hopefully
Dec 5 '18 at 3:52
1
You are confusing the concept of linear function from elementary mathematics with the concept of a linear transformation of vector spaces that occurs in linear algebra. There is a connection between the two, but they are not the same thing.
– Justin Young
Dec 5 '18 at 15:01
|
show 5 more comments
1. $df_x$ is a linear map of vector spaces, so how many such constant maps could it be?
– Randall
Dec 5 '18 at 3:42
you mean $f$ is a linear map of vector spaces or $df$? @Randall
– hopefully
Dec 5 '18 at 3:46
Check the definitions: given $f: X to Y$ a smooth map, $df_x$ is a linear transformation $df_x: T_xM to T_{f(x)}N$.
– Randall
Dec 5 '18 at 3:48
So by this definition since the differential(derivative) of a linear map is the linear map itself .... I do not know the answer for your first question .... I am confused.@Randall
– hopefully
Dec 5 '18 at 3:52
1
You are confusing the concept of linear function from elementary mathematics with the concept of a linear transformation of vector spaces that occurs in linear algebra. There is a connection between the two, but they are not the same thing.
– Justin Young
Dec 5 '18 at 15:01
1. $df_x$ is a linear map of vector spaces, so how many such constant maps could it be?
– Randall
Dec 5 '18 at 3:42
1. $df_x$ is a linear map of vector spaces, so how many such constant maps could it be?
– Randall
Dec 5 '18 at 3:42
you mean $f$ is a linear map of vector spaces or $df$? @Randall
– hopefully
Dec 5 '18 at 3:46
you mean $f$ is a linear map of vector spaces or $df$? @Randall
– hopefully
Dec 5 '18 at 3:46
Check the definitions: given $f: X to Y$ a smooth map, $df_x$ is a linear transformation $df_x: T_xM to T_{f(x)}N$.
– Randall
Dec 5 '18 at 3:48
Check the definitions: given $f: X to Y$ a smooth map, $df_x$ is a linear transformation $df_x: T_xM to T_{f(x)}N$.
– Randall
Dec 5 '18 at 3:48
So by this definition since the differential(derivative) of a linear map is the linear map itself .... I do not know the answer for your first question .... I am confused.@Randall
– hopefully
Dec 5 '18 at 3:52
So by this definition since the differential(derivative) of a linear map is the linear map itself .... I do not know the answer for your first question .... I am confused.@Randall
– hopefully
Dec 5 '18 at 3:52
1
1
You are confusing the concept of linear function from elementary mathematics with the concept of a linear transformation of vector spaces that occurs in linear algebra. There is a connection between the two, but they are not the same thing.
– Justin Young
Dec 5 '18 at 15:01
You are confusing the concept of linear function from elementary mathematics with the concept of a linear transformation of vector spaces that occurs in linear algebra. There is a connection between the two, but they are not the same thing.
– Justin Young
Dec 5 '18 at 15:01
|
show 5 more comments
1 Answer
1
active
oldest
votes
(1) The only constant linear map is the zero map. (2) The claim in the sixth line is essentially the implicit function theorem. (3) Consider $f(x)=x^2$. No change of coordinates will turn this into $x$ near $0$.
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
(1) The only constant linear map is the zero map. (2) The claim in the sixth line is essentially the implicit function theorem. (3) Consider $f(x)=x^2$. No change of coordinates will turn this into $x$ near $0$.
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
add a comment |
(1) The only constant linear map is the zero map. (2) The claim in the sixth line is essentially the implicit function theorem. (3) Consider $f(x)=x^2$. No change of coordinates will turn this into $x$ near $0$.
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
add a comment |
(1) The only constant linear map is the zero map. (2) The claim in the sixth line is essentially the implicit function theorem. (3) Consider $f(x)=x^2$. No change of coordinates will turn this into $x$ near $0$.
(1) The only constant linear map is the zero map. (2) The claim in the sixth line is essentially the implicit function theorem. (3) Consider $f(x)=x^2$. No change of coordinates will turn this into $x$ near $0$.
answered Dec 5 '18 at 5:38
Kevin CarlsonKevin Carlson
32.6k23271
32.6k23271
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
add a comment |
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
why the only constant linear map is the zero map?
– hopefully
Dec 5 '18 at 6:30
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
How it is the implicit function theorem?
– hopefully
Dec 5 '18 at 6:43
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
do not understand the answer of (3)
– hopefully
Dec 5 '18 at 6:51
add a comment |
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1. $df_x$ is a linear map of vector spaces, so how many such constant maps could it be?
– Randall
Dec 5 '18 at 3:42
you mean $f$ is a linear map of vector spaces or $df$? @Randall
– hopefully
Dec 5 '18 at 3:46
Check the definitions: given $f: X to Y$ a smooth map, $df_x$ is a linear transformation $df_x: T_xM to T_{f(x)}N$.
– Randall
Dec 5 '18 at 3:48
So by this definition since the differential(derivative) of a linear map is the linear map itself .... I do not know the answer for your first question .... I am confused.@Randall
– hopefully
Dec 5 '18 at 3:52
1
You are confusing the concept of linear function from elementary mathematics with the concept of a linear transformation of vector spaces that occurs in linear algebra. There is a connection between the two, but they are not the same thing.
– Justin Young
Dec 5 '18 at 15:01