Solving $sin x = 0$, I get $x=ktimes 360^circ$ and $x=ktimes 360^circ+180^circ$, but the answer is $x=ktimes...












1














How to prove that $sin x = 0$ when $x = ktimes180^circ$?



I tried doing it, but I got these results:
$$x=ktimes 360^circ qquad x=ktimes 360^circ+180^circ$$










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  • Those two answers can be “compressed” into one: $x = pi n$.
    – KM101
    Oct 30 '18 at 17:11










  • For one way to "see" what @KM101 said, try writing out all values that $k times 180$ represent in one list, and all values that $k times 360 + 180$ represent in another list, and then make a combined list of everything that shows up in at least one of the first two lists. Make sure you include negative integer values of $k$ when you do this. (Ah ... I see that KM101 was in the middle of doing eactly this when I was writing my comment!)
    – Dave L. Renfro
    Oct 30 '18 at 17:19












  • @KM101 how exactly?
    – Lyds
    Oct 30 '18 at 17:20










  • Yeah, I’ve added a rather brief explanation with the list. The idea can be applied in both degrees and radians.
    – KM101
    Oct 30 '18 at 17:20










  • Check my answer.
    – KM101
    Oct 30 '18 at 17:20
















1














How to prove that $sin x = 0$ when $x = ktimes180^circ$?



I tried doing it, but I got these results:
$$x=ktimes 360^circ qquad x=ktimes 360^circ+180^circ$$










share|cite|improve this question
























  • Those two answers can be “compressed” into one: $x = pi n$.
    – KM101
    Oct 30 '18 at 17:11










  • For one way to "see" what @KM101 said, try writing out all values that $k times 180$ represent in one list, and all values that $k times 360 + 180$ represent in another list, and then make a combined list of everything that shows up in at least one of the first two lists. Make sure you include negative integer values of $k$ when you do this. (Ah ... I see that KM101 was in the middle of doing eactly this when I was writing my comment!)
    – Dave L. Renfro
    Oct 30 '18 at 17:19












  • @KM101 how exactly?
    – Lyds
    Oct 30 '18 at 17:20










  • Yeah, I’ve added a rather brief explanation with the list. The idea can be applied in both degrees and radians.
    – KM101
    Oct 30 '18 at 17:20










  • Check my answer.
    – KM101
    Oct 30 '18 at 17:20














1












1








1







How to prove that $sin x = 0$ when $x = ktimes180^circ$?



I tried doing it, but I got these results:
$$x=ktimes 360^circ qquad x=ktimes 360^circ+180^circ$$










share|cite|improve this question















How to prove that $sin x = 0$ when $x = ktimes180^circ$?



I tried doing it, but I got these results:
$$x=ktimes 360^circ qquad x=ktimes 360^circ+180^circ$$







trigonometry






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Oct 30 '18 at 17:28









Blue

47.7k870151




47.7k870151










asked Oct 30 '18 at 17:06









LydsLyds

163




163












  • Those two answers can be “compressed” into one: $x = pi n$.
    – KM101
    Oct 30 '18 at 17:11










  • For one way to "see" what @KM101 said, try writing out all values that $k times 180$ represent in one list, and all values that $k times 360 + 180$ represent in another list, and then make a combined list of everything that shows up in at least one of the first two lists. Make sure you include negative integer values of $k$ when you do this. (Ah ... I see that KM101 was in the middle of doing eactly this when I was writing my comment!)
    – Dave L. Renfro
    Oct 30 '18 at 17:19












  • @KM101 how exactly?
    – Lyds
    Oct 30 '18 at 17:20










  • Yeah, I’ve added a rather brief explanation with the list. The idea can be applied in both degrees and radians.
    – KM101
    Oct 30 '18 at 17:20










  • Check my answer.
    – KM101
    Oct 30 '18 at 17:20


















  • Those two answers can be “compressed” into one: $x = pi n$.
    – KM101
    Oct 30 '18 at 17:11










  • For one way to "see" what @KM101 said, try writing out all values that $k times 180$ represent in one list, and all values that $k times 360 + 180$ represent in another list, and then make a combined list of everything that shows up in at least one of the first two lists. Make sure you include negative integer values of $k$ when you do this. (Ah ... I see that KM101 was in the middle of doing eactly this when I was writing my comment!)
    – Dave L. Renfro
    Oct 30 '18 at 17:19












  • @KM101 how exactly?
    – Lyds
    Oct 30 '18 at 17:20










  • Yeah, I’ve added a rather brief explanation with the list. The idea can be applied in both degrees and radians.
    – KM101
    Oct 30 '18 at 17:20










  • Check my answer.
    – KM101
    Oct 30 '18 at 17:20
















Those two answers can be “compressed” into one: $x = pi n$.
– KM101
Oct 30 '18 at 17:11




Those two answers can be “compressed” into one: $x = pi n$.
– KM101
Oct 30 '18 at 17:11












For one way to "see" what @KM101 said, try writing out all values that $k times 180$ represent in one list, and all values that $k times 360 + 180$ represent in another list, and then make a combined list of everything that shows up in at least one of the first two lists. Make sure you include negative integer values of $k$ when you do this. (Ah ... I see that KM101 was in the middle of doing eactly this when I was writing my comment!)
– Dave L. Renfro
Oct 30 '18 at 17:19






For one way to "see" what @KM101 said, try writing out all values that $k times 180$ represent in one list, and all values that $k times 360 + 180$ represent in another list, and then make a combined list of everything that shows up in at least one of the first two lists. Make sure you include negative integer values of $k$ when you do this. (Ah ... I see that KM101 was in the middle of doing eactly this when I was writing my comment!)
– Dave L. Renfro
Oct 30 '18 at 17:19














@KM101 how exactly?
– Lyds
Oct 30 '18 at 17:20




@KM101 how exactly?
– Lyds
Oct 30 '18 at 17:20












Yeah, I’ve added a rather brief explanation with the list. The idea can be applied in both degrees and radians.
– KM101
Oct 30 '18 at 17:20




Yeah, I’ve added a rather brief explanation with the list. The idea can be applied in both degrees and radians.
– KM101
Oct 30 '18 at 17:20












Check my answer.
– KM101
Oct 30 '18 at 17:20




Check my answer.
– KM101
Oct 30 '18 at 17:20










1 Answer
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$$sin x = 0$$



For $n in mathbb{Z}$, $x = pi + 2pi n$ OR $x = 2pi n$.



$$x = pi + 2pi n implies x = …, -5pi, -3pi, -pi,pi, 3pi, 5pi, …$$



$$x = 2pi n implies x = …, -6pi, -4pi, -2pi, 0, 2pi, 4pi, 6pi, …$$



If you noticed, combining them would give all integer multiples of $pi$, so you just combine them.
$$x = pi n$$



You could demonstrate the same idea in degrees: $x = 180+360n$ and $x = 360n$ can be combined to give $x = 180n$.






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    1 Answer
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    $$sin x = 0$$



    For $n in mathbb{Z}$, $x = pi + 2pi n$ OR $x = 2pi n$.



    $$x = pi + 2pi n implies x = …, -5pi, -3pi, -pi,pi, 3pi, 5pi, …$$



    $$x = 2pi n implies x = …, -6pi, -4pi, -2pi, 0, 2pi, 4pi, 6pi, …$$



    If you noticed, combining them would give all integer multiples of $pi$, so you just combine them.
    $$x = pi n$$



    You could demonstrate the same idea in degrees: $x = 180+360n$ and $x = 360n$ can be combined to give $x = 180n$.






    share|cite|improve this answer




























      1














      $$sin x = 0$$



      For $n in mathbb{Z}$, $x = pi + 2pi n$ OR $x = 2pi n$.



      $$x = pi + 2pi n implies x = …, -5pi, -3pi, -pi,pi, 3pi, 5pi, …$$



      $$x = 2pi n implies x = …, -6pi, -4pi, -2pi, 0, 2pi, 4pi, 6pi, …$$



      If you noticed, combining them would give all integer multiples of $pi$, so you just combine them.
      $$x = pi n$$



      You could demonstrate the same idea in degrees: $x = 180+360n$ and $x = 360n$ can be combined to give $x = 180n$.






      share|cite|improve this answer


























        1












        1








        1






        $$sin x = 0$$



        For $n in mathbb{Z}$, $x = pi + 2pi n$ OR $x = 2pi n$.



        $$x = pi + 2pi n implies x = …, -5pi, -3pi, -pi,pi, 3pi, 5pi, …$$



        $$x = 2pi n implies x = …, -6pi, -4pi, -2pi, 0, 2pi, 4pi, 6pi, …$$



        If you noticed, combining them would give all integer multiples of $pi$, so you just combine them.
        $$x = pi n$$



        You could demonstrate the same idea in degrees: $x = 180+360n$ and $x = 360n$ can be combined to give $x = 180n$.






        share|cite|improve this answer














        $$sin x = 0$$



        For $n in mathbb{Z}$, $x = pi + 2pi n$ OR $x = 2pi n$.



        $$x = pi + 2pi n implies x = …, -5pi, -3pi, -pi,pi, 3pi, 5pi, …$$



        $$x = 2pi n implies x = …, -6pi, -4pi, -2pi, 0, 2pi, 4pi, 6pi, …$$



        If you noticed, combining them would give all integer multiples of $pi$, so you just combine them.
        $$x = pi n$$



        You could demonstrate the same idea in degrees: $x = 180+360n$ and $x = 360n$ can be combined to give $x = 180n$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Dec 5 '18 at 4:12

























        answered Oct 30 '18 at 17:19









        KM101KM101

        5,5911423




        5,5911423






























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