Controllable system?
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So I have my equation of motion for an inverted pendulum on a cart: (linearised about the upright position and X denoting the position of the cart):
$$ ddot{theta}-theta = ddot{X} $$
Rather than dealing with a 4x4 system I’d like to set $ddot{X} = a theta +b dot{theta}$ but now I’m struggling to write my system in the form:
$$dot{x} = Ax + Bu$$
as I can’t determine what my control Bu is now that I’m not applying a direct force to the cart?
linear-algebra dynamical-systems control-theory classical-mechanics
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So I have my equation of motion for an inverted pendulum on a cart: (linearised about the upright position and X denoting the position of the cart):
$$ ddot{theta}-theta = ddot{X} $$
Rather than dealing with a 4x4 system I’d like to set $ddot{X} = a theta +b dot{theta}$ but now I’m struggling to write my system in the form:
$$dot{x} = Ax + Bu$$
as I can’t determine what my control Bu is now that I’m not applying a direct force to the cart?
linear-algebra dynamical-systems control-theory classical-mechanics
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
So I have my equation of motion for an inverted pendulum on a cart: (linearised about the upright position and X denoting the position of the cart):
$$ ddot{theta}-theta = ddot{X} $$
Rather than dealing with a 4x4 system I’d like to set $ddot{X} = a theta +b dot{theta}$ but now I’m struggling to write my system in the form:
$$dot{x} = Ax + Bu$$
as I can’t determine what my control Bu is now that I’m not applying a direct force to the cart?
linear-algebra dynamical-systems control-theory classical-mechanics
So I have my equation of motion for an inverted pendulum on a cart: (linearised about the upright position and X denoting the position of the cart):
$$ ddot{theta}-theta = ddot{X} $$
Rather than dealing with a 4x4 system I’d like to set $ddot{X} = a theta +b dot{theta}$ but now I’m struggling to write my system in the form:
$$dot{x} = Ax + Bu$$
as I can’t determine what my control Bu is now that I’m not applying a direct force to the cart?
linear-algebra dynamical-systems control-theory classical-mechanics
linear-algebra dynamical-systems control-theory classical-mechanics
asked 13 hours ago
mailrenegade
174
174
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You are only using one half of the equations of motion. The other half contains an external force, which will be your input $u$.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You are only using one half of the equations of motion. The other half contains an external force, which will be your input $u$.
add a comment |
up vote
0
down vote
You are only using one half of the equations of motion. The other half contains an external force, which will be your input $u$.
add a comment |
up vote
0
down vote
up vote
0
down vote
You are only using one half of the equations of motion. The other half contains an external force, which will be your input $u$.
You are only using one half of the equations of motion. The other half contains an external force, which will be your input $u$.
answered 8 hours ago
Kwin van der Veen
5,0852826
5,0852826
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