Is the 4th root of $3^3$ $3^3/4$ or $2.2795$?











up vote
1
down vote

favorite












I'm working through a textbook and one question is:




Use a calculator to find the value of the following expression: $$sqrt[large4]{3^3}$$




The textbook answer is given as $2.2795$; however, using https://live.sympy.org/, if I enter root(3**3, 4), I get back 3^3/4.



How do I arrive at $2.2795$?





Here's the original question and the given solution:



enter image description here



enter image description here










share|cite|improve this question
























  • When I put it into simpy it is clearly $3^{(frac 34)}$ as it should be.
    – Ross Millikan
    Nov 15 at 16:48















up vote
1
down vote

favorite












I'm working through a textbook and one question is:




Use a calculator to find the value of the following expression: $$sqrt[large4]{3^3}$$




The textbook answer is given as $2.2795$; however, using https://live.sympy.org/, if I enter root(3**3, 4), I get back 3^3/4.



How do I arrive at $2.2795$?





Here's the original question and the given solution:



enter image description here



enter image description here










share|cite|improve this question
























  • When I put it into simpy it is clearly $3^{(frac 34)}$ as it should be.
    – Ross Millikan
    Nov 15 at 16:48













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm working through a textbook and one question is:




Use a calculator to find the value of the following expression: $$sqrt[large4]{3^3}$$




The textbook answer is given as $2.2795$; however, using https://live.sympy.org/, if I enter root(3**3, 4), I get back 3^3/4.



How do I arrive at $2.2795$?





Here's the original question and the given solution:



enter image description here



enter image description here










share|cite|improve this question















I'm working through a textbook and one question is:




Use a calculator to find the value of the following expression: $$sqrt[large4]{3^3}$$




The textbook answer is given as $2.2795$; however, using https://live.sympy.org/, if I enter root(3**3, 4), I get back 3^3/4.



How do I arrive at $2.2795$?





Here's the original question and the given solution:



enter image description here



enter image description here







exponentiation






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 6 hours ago









Robert Howard

1,573622




1,573622










asked Nov 15 at 16:40









Doug Fir

1696




1696












  • When I put it into simpy it is clearly $3^{(frac 34)}$ as it should be.
    – Ross Millikan
    Nov 15 at 16:48


















  • When I put it into simpy it is clearly $3^{(frac 34)}$ as it should be.
    – Ross Millikan
    Nov 15 at 16:48
















When I put it into simpy it is clearly $3^{(frac 34)}$ as it should be.
– Ross Millikan
Nov 15 at 16:48




When I put it into simpy it is clearly $3^{(frac 34)}$ as it should be.
– Ross Millikan
Nov 15 at 16:48










1 Answer
1






active

oldest

votes

















up vote
3
down vote



accepted










$3^{frac{3}{4}}$ is what you get out. Not $frac{3^3}{4}$. As it happens, $3^frac{3}{4}$ is approximately 2.2795.






share|cite|improve this answer





















  • Ah so it's the same. Thanks, accepting when the limit comes off.
    – Doug Fir
    Nov 15 at 16:44











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2999940%2fis-the-4th-root-of-33-33-4-or-2-2795%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










$3^{frac{3}{4}}$ is what you get out. Not $frac{3^3}{4}$. As it happens, $3^frac{3}{4}$ is approximately 2.2795.






share|cite|improve this answer





















  • Ah so it's the same. Thanks, accepting when the limit comes off.
    – Doug Fir
    Nov 15 at 16:44















up vote
3
down vote



accepted










$3^{frac{3}{4}}$ is what you get out. Not $frac{3^3}{4}$. As it happens, $3^frac{3}{4}$ is approximately 2.2795.






share|cite|improve this answer





















  • Ah so it's the same. Thanks, accepting when the limit comes off.
    – Doug Fir
    Nov 15 at 16:44













up vote
3
down vote



accepted







up vote
3
down vote



accepted






$3^{frac{3}{4}}$ is what you get out. Not $frac{3^3}{4}$. As it happens, $3^frac{3}{4}$ is approximately 2.2795.






share|cite|improve this answer












$3^{frac{3}{4}}$ is what you get out. Not $frac{3^3}{4}$. As it happens, $3^frac{3}{4}$ is approximately 2.2795.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 15 at 16:43









user3482749

971411




971411












  • Ah so it's the same. Thanks, accepting when the limit comes off.
    – Doug Fir
    Nov 15 at 16:44


















  • Ah so it's the same. Thanks, accepting when the limit comes off.
    – Doug Fir
    Nov 15 at 16:44
















Ah so it's the same. Thanks, accepting when the limit comes off.
– Doug Fir
Nov 15 at 16:44




Ah so it's the same. Thanks, accepting when the limit comes off.
– Doug Fir
Nov 15 at 16:44


















 

draft saved


draft discarded



















































 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2999940%2fis-the-4th-root-of-33-33-4-or-2-2795%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Berounka

Sphinx de Gizeh

Different font size/position of beamer's navigation symbols template's content depending on regular/plain...