If V and W are linear subspaces of $R^n$, then V transversal W means just $V + W = R^n$











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If V and W are linear subspaces of $R^n$, then V transversal W means just $V + W = R^n$.



Could anyone give me a hint for this exercise please?










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  • 2




    What is your question? I don't think this is the usual definition for transversal.
    – Ethan Bolker
    Nov 21 at 17:05






  • 2




    This sounds more like a definition than something in need of proof.
    – Rocket Man
    Nov 21 at 17:06












  • What's up with all the random tags, but no "linear algebra"?
    – Federico
    Nov 21 at 17:10










  • This is an exercise in Guillemin & Pollack 1.5.1(b) @EthanBolker
    – hopefully
    Nov 21 at 17:14










  • @RocketMan This is an exercise in Guillemin & Pollack 1.5.1(b) - differential topology
    – hopefully
    Nov 21 at 17:16















up vote
0
down vote

favorite












If V and W are linear subspaces of $R^n$, then V transversal W means just $V + W = R^n$.



Could anyone give me a hint for this exercise please?










share|cite|improve this question




















  • 2




    What is your question? I don't think this is the usual definition for transversal.
    – Ethan Bolker
    Nov 21 at 17:05






  • 2




    This sounds more like a definition than something in need of proof.
    – Rocket Man
    Nov 21 at 17:06












  • What's up with all the random tags, but no "linear algebra"?
    – Federico
    Nov 21 at 17:10










  • This is an exercise in Guillemin & Pollack 1.5.1(b) @EthanBolker
    – hopefully
    Nov 21 at 17:14










  • @RocketMan This is an exercise in Guillemin & Pollack 1.5.1(b) - differential topology
    – hopefully
    Nov 21 at 17:16













up vote
0
down vote

favorite









up vote
0
down vote

favorite











If V and W are linear subspaces of $R^n$, then V transversal W means just $V + W = R^n$.



Could anyone give me a hint for this exercise please?










share|cite|improve this question















If V and W are linear subspaces of $R^n$, then V transversal W means just $V + W = R^n$.



Could anyone give me a hint for this exercise please?







linear-algebra definition differential-topology geometric-topology transversality






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share|cite|improve this question













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edited Nov 21 at 17:15

























asked Nov 21 at 17:04









hopefully

8611




8611








  • 2




    What is your question? I don't think this is the usual definition for transversal.
    – Ethan Bolker
    Nov 21 at 17:05






  • 2




    This sounds more like a definition than something in need of proof.
    – Rocket Man
    Nov 21 at 17:06












  • What's up with all the random tags, but no "linear algebra"?
    – Federico
    Nov 21 at 17:10










  • This is an exercise in Guillemin & Pollack 1.5.1(b) @EthanBolker
    – hopefully
    Nov 21 at 17:14










  • @RocketMan This is an exercise in Guillemin & Pollack 1.5.1(b) - differential topology
    – hopefully
    Nov 21 at 17:16














  • 2




    What is your question? I don't think this is the usual definition for transversal.
    – Ethan Bolker
    Nov 21 at 17:05






  • 2




    This sounds more like a definition than something in need of proof.
    – Rocket Man
    Nov 21 at 17:06












  • What's up with all the random tags, but no "linear algebra"?
    – Federico
    Nov 21 at 17:10










  • This is an exercise in Guillemin & Pollack 1.5.1(b) @EthanBolker
    – hopefully
    Nov 21 at 17:14










  • @RocketMan This is an exercise in Guillemin & Pollack 1.5.1(b) - differential topology
    – hopefully
    Nov 21 at 17:16








2




2




What is your question? I don't think this is the usual definition for transversal.
– Ethan Bolker
Nov 21 at 17:05




What is your question? I don't think this is the usual definition for transversal.
– Ethan Bolker
Nov 21 at 17:05




2




2




This sounds more like a definition than something in need of proof.
– Rocket Man
Nov 21 at 17:06






This sounds more like a definition than something in need of proof.
– Rocket Man
Nov 21 at 17:06














What's up with all the random tags, but no "linear algebra"?
– Federico
Nov 21 at 17:10




What's up with all the random tags, but no "linear algebra"?
– Federico
Nov 21 at 17:10












This is an exercise in Guillemin & Pollack 1.5.1(b) @EthanBolker
– hopefully
Nov 21 at 17:14




This is an exercise in Guillemin & Pollack 1.5.1(b) @EthanBolker
– hopefully
Nov 21 at 17:14












@RocketMan This is an exercise in Guillemin & Pollack 1.5.1(b) - differential topology
– hopefully
Nov 21 at 17:16




@RocketMan This is an exercise in Guillemin & Pollack 1.5.1(b) - differential topology
– hopefully
Nov 21 at 17:16










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So to answer this question, you have to think of $V$ and $W$ as submanifolds of $mathbb{R}^n$. They intersect transversally if, at every point of their intersection, the sum of their tangent spaces is $mathbb{R}^n$. But remember that since $V$ and $W$ are vector spaces, their tangent spaces at any point are isomorphically just themselves, and we identify them as such. The same goes for the tangent space to $mathbb{R}^n$ at any point. Since all these identifications commute in a sense that can be made precise, there is no conflict if we make all these identifications simultaneously and then think about just the subspaces themselves. Thinking about what this means in the context of transversality, we realize that this is just the condition that $V+W = mathbb{R}^n$.






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    So to answer this question, you have to think of $V$ and $W$ as submanifolds of $mathbb{R}^n$. They intersect transversally if, at every point of their intersection, the sum of their tangent spaces is $mathbb{R}^n$. But remember that since $V$ and $W$ are vector spaces, their tangent spaces at any point are isomorphically just themselves, and we identify them as such. The same goes for the tangent space to $mathbb{R}^n$ at any point. Since all these identifications commute in a sense that can be made precise, there is no conflict if we make all these identifications simultaneously and then think about just the subspaces themselves. Thinking about what this means in the context of transversality, we realize that this is just the condition that $V+W = mathbb{R}^n$.






    share|cite|improve this answer

























      up vote
      1
      down vote



      accepted










      So to answer this question, you have to think of $V$ and $W$ as submanifolds of $mathbb{R}^n$. They intersect transversally if, at every point of their intersection, the sum of their tangent spaces is $mathbb{R}^n$. But remember that since $V$ and $W$ are vector spaces, their tangent spaces at any point are isomorphically just themselves, and we identify them as such. The same goes for the tangent space to $mathbb{R}^n$ at any point. Since all these identifications commute in a sense that can be made precise, there is no conflict if we make all these identifications simultaneously and then think about just the subspaces themselves. Thinking about what this means in the context of transversality, we realize that this is just the condition that $V+W = mathbb{R}^n$.






      share|cite|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        So to answer this question, you have to think of $V$ and $W$ as submanifolds of $mathbb{R}^n$. They intersect transversally if, at every point of their intersection, the sum of their tangent spaces is $mathbb{R}^n$. But remember that since $V$ and $W$ are vector spaces, their tangent spaces at any point are isomorphically just themselves, and we identify them as such. The same goes for the tangent space to $mathbb{R}^n$ at any point. Since all these identifications commute in a sense that can be made precise, there is no conflict if we make all these identifications simultaneously and then think about just the subspaces themselves. Thinking about what this means in the context of transversality, we realize that this is just the condition that $V+W = mathbb{R}^n$.






        share|cite|improve this answer












        So to answer this question, you have to think of $V$ and $W$ as submanifolds of $mathbb{R}^n$. They intersect transversally if, at every point of their intersection, the sum of their tangent spaces is $mathbb{R}^n$. But remember that since $V$ and $W$ are vector spaces, their tangent spaces at any point are isomorphically just themselves, and we identify them as such. The same goes for the tangent space to $mathbb{R}^n$ at any point. Since all these identifications commute in a sense that can be made precise, there is no conflict if we make all these identifications simultaneously and then think about just the subspaces themselves. Thinking about what this means in the context of transversality, we realize that this is just the condition that $V+W = mathbb{R}^n$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 21 at 17:32









        Monstrous Moonshiner

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