Simplifying $dfrac{cot(34^circ)sin(44^circ)}{sin(22^circ)sin(56^circ)} $
$$dfrac{cot(34^circ)sin(44^circ)}{sin(22^circ)sin(56^circ)} $$
Simplify given expression.
We know that $cot alpha = dfrac{sin alpha }{cos alpha }$ and $sin(44^circ) = 2sin(22^circ)cos(22^circ)$
$$dfrac{cot(34^circ) 2sin(22^circ)cos(22^circ)}{sin(22^circ)sin(56^circ)}$$
Cancelling similar terms out
$$dfrac{cot(34^circ)2cos (22^circ)}{sin(56^circ)} = dfrac{dfrac{cos(34^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)} $$
Using the identity $cos (90^circ-alpha ) = sin (alpha)$
$$dfrac{dfrac{sin(56^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)}=dfrac {2sin(56^circ)cos(22^circ)}{sin(34^circ)sin(56^circ)} = dfrac{2cos (22^circ)}{sin(34^circ)} $$
Since the degrees aren't the same, I could not proceed further.
trigonometry
edited Dec 1 at 17:01
J.G.
22.3k22034
asked Dec 1 at 16:55
Hamilton
1848
add a comment |
$$dfrac{cot(34^circ)sin(44^circ)}{sin(22^circ)sin(56^circ)} $$
Simplify given expression.
We know that $cot alpha = dfrac{sin alpha }{cos alpha }$ and $sin(44^circ) = 2sin(22^circ)cos(22^circ)$
$$dfrac{cot(34^circ) 2sin(22^circ)cos(22^circ)}{sin(22^circ)sin(56^circ)}$$
Cancelling similar terms out
$$dfrac{cot(34^circ)2cos (22^circ)}{sin(56^circ)} = dfrac{dfrac{cos(34^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)} $$
Using the identity $cos (90^circ-alpha ) = sin (alpha)$
$$dfrac{dfrac{sin(56^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)}=dfrac {2sin(56^circ)cos(22^circ)}{sin(34^circ)sin(56^circ)} = dfrac{2cos (22^circ)}{sin(34^circ)} $$
Since the degrees aren't the same, I could not proceed further.
trigonometry
edited Dec 1 at 17:01
J.G.
22.3k22034
asked Dec 1 at 16:55
Hamilton
1848
add a comment |
$$dfrac{cot(34^circ)sin(44^circ)}{sin(22^circ)sin(56^circ)} $$
Simplify given expression.
We know that $cot alpha = dfrac{sin alpha }{cos alpha }$ and $sin(44^circ) = 2sin(22^circ)cos(22^circ)$
$$dfrac{cot(34^circ) 2sin(22^circ)cos(22^circ)}{sin(22^circ)sin(56^circ)}$$
Cancelling similar terms out
$$dfrac{cot(34^circ)2cos (22^circ)}{sin(56^circ)} = dfrac{dfrac{cos(34^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)} $$
Using the identity $cos (90^circ-alpha ) = sin (alpha)$
$$dfrac{dfrac{sin(56^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)}=dfrac {2sin(56^circ)cos(22^circ)}{sin(34^circ)sin(56^circ)} = dfrac{2cos (22^circ)}{sin(34^circ)} $$
Since the degrees aren't the same, I could not proceed further.
trigonometry
edited Dec 1 at 17:01
J.G.
22.3k22034
asked Dec 1 at 16:55
Hamilton
1848
$$dfrac{cot(34^circ)sin(44^circ)}{sin(22^circ)sin(56^circ)} $$
Simplify given expression.
We know that $cot alpha = dfrac{sin alpha }{cos alpha }$ and $sin(44^circ) = 2sin(22^circ)cos(22^circ)$
$$dfrac{cot(34^circ) 2sin(22^circ)cos(22^circ)}{sin(22^circ)sin(56^circ)}$$
Cancelling similar terms out
$$dfrac{cot(34^circ)2cos (22^circ)}{sin(56^circ)} = dfrac{dfrac{cos(34^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)} $$
Using the identity $cos (90^circ-alpha ) = sin (alpha)$
$$dfrac{dfrac{sin(56^circ)}{sin(34^circ)}2cos (22^circ)}{sin(56^circ)}=dfrac {2sin(56^circ)cos(22^circ)}{sin(34^circ)sin(56^circ)} = dfrac{2cos (22^circ)}{sin(34^circ)} $$
Since the degrees aren't the same, I could not proceed further.
trigonometry
trigonometry
edited Dec 1 at 17:01
J.G.
22.3k22034
asked Dec 1 at 16:55
Hamilton
1848
edited Dec 1 at 17:01
J.G.
22.3k22034
asked Dec 1 at 16:55
Hamilton
1848
edited Dec 1 at 17:01
J.G.
22.3k22034
edited Dec 1 at 17:01
J.G.
22.3k22034
edited Dec 1 at 17:01
J.G.
22.3k22034
22.3k22034
asked Dec 1 at 16:55
Hamilton
1848
asked Dec 1 at 16:55
Hamilton
1848
asked Dec 1 at 16:55
Hamilton
1848
1848
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$$frac{2sin 68^circ}{sin 34^circ}=4cos 34^circ$$
answered Dec 1 at 16:59
J.G.
22.3k22034
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3021561%2fsimplifying-dfrac-cot34-circ-sin44-circ-sin22-circ-sin56-circ%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$$frac{2sin 68^circ}{sin 34^circ}=4cos 34^circ$$
answered Dec 1 at 16:59
J.G.
22.3k22034
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
add a comment |
$$frac{2sin 68^circ}{sin 34^circ}=4cos 34^circ$$
answered Dec 1 at 16:59
J.G.
22.3k22034
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
add a comment |
$$frac{2sin 68^circ}{sin 34^circ}=4cos 34^circ$$
answered Dec 1 at 16:59
J.G.
22.3k22034
$$frac{2sin 68^circ}{sin 34^circ}=4cos 34^circ$$
answered Dec 1 at 16:59
J.G.
22.3k22034
answered Dec 1 at 16:59
J.G.
22.3k22034
answered Dec 1 at 16:59
J.G.
22.3k22034
answered Dec 1 at 16:59
J.G.
22.3k22034
22.3k22034
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
add a comment |
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
It was unbelieveable mistake. Thanks for reminding!
– Hamilton
Dec 1 at 17:02
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3021561%2fsimplifying-dfrac-cot34-circ-sin44-circ-sin22-circ-sin56-circ%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
