C# for loop to print first 20 positive numbers divisible by 7?
This is Code I reached. What I don't understand is how do I put a condition to display the first 20 numbers where I wrote the condition for i to be less than 20. I know that my code is completely wrong.
for(int i=1; i<=20; i++)
{
if(i%7==0)
{
Console.WriteLine(i);
}
}
c#-3.0
edited Nov 23 '18 at 16:11
kvantour
8,45331230
asked Nov 23 '18 at 16:01
harpreetharpreet
11
add a comment |
This is Code I reached. What I don't understand is how do I put a condition to display the first 20 numbers where I wrote the condition for i to be less than 20. I know that my code is completely wrong.
for(int i=1; i<=20; i++)
{
if(i%7==0)
{
Console.WriteLine(i);
}
}
c#-3.0
edited Nov 23 '18 at 16:11
kvantour
8,45331230
asked Nov 23 '18 at 16:01
harpreetharpreet
11
add a comment |
This is Code I reached. What I don't understand is how do I put a condition to display the first 20 numbers where I wrote the condition for i to be less than 20. I know that my code is completely wrong.
for(int i=1; i<=20; i++)
{
if(i%7==0)
{
Console.WriteLine(i);
}
}
c#-3.0
edited Nov 23 '18 at 16:11
kvantour
8,45331230
asked Nov 23 '18 at 16:01
harpreetharpreet
11
This is Code I reached. What I don't understand is how do I put a condition to display the first 20 numbers where I wrote the condition for i to be less than 20. I know that my code is completely wrong.
for(int i=1; i<=20; i++)
{
if(i%7==0)
{
Console.WriteLine(i);
}
}
c#-3.0
c#-3.0
edited Nov 23 '18 at 16:11
kvantour
8,45331230
asked Nov 23 '18 at 16:01
harpreetharpreet
11
edited Nov 23 '18 at 16:11
kvantour
8,45331230
asked Nov 23 '18 at 16:01
harpreetharpreet
11
edited Nov 23 '18 at 16:11
kvantour
8,45331230
edited Nov 23 '18 at 16:11
kvantour
8,45331230
edited Nov 23 '18 at 16:11
kvantour
8,45331230
8,45331230
asked Nov 23 '18 at 16:01
harpreetharpreet
11
asked Nov 23 '18 at 16:01
harpreetharpreet
11
asked Nov 23 '18 at 16:01
harpreetharpreet
11
11
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You're close. use a counter variable:
int counter = 0; // counter variable
for(int i=1; ; i++) // removed condition
{
if (counter > 20) break; // time to stop the iteration
if(i%7==0)
{
counter++;
Console.WriteLine(i);
}
}
This can be improved to:
for(int i = 7, counter = 0; counter <= 20; i += 7)
{
Console.WriteLine(i);
counter++;
}
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
add a comment |
The first 20 integers that are divisible by 7 are easily written as 7,2*7,3*7,4*7,...,20*7. This in your loop you can do:
for(int i = 1; i<=20; i++) {
Console.WriteLine(7*i);
}
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
add a comment |
Can’t you just go up in sevens?
for (int multiple = 7, int count = 0; count < 20; multiple += 7, count++)
{
Console.WriteLine(multiple);
}
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You're close. use a counter variable:
int counter = 0; // counter variable
for(int i=1; ; i++) // removed condition
{
if (counter > 20) break; // time to stop the iteration
if(i%7==0)
{
counter++;
Console.WriteLine(i);
}
}
This can be improved to:
for(int i = 7, counter = 0; counter <= 20; i += 7)
{
Console.WriteLine(i);
counter++;
}
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
add a comment |
You're close. use a counter variable:
int counter = 0; // counter variable
for(int i=1; ; i++) // removed condition
{
if (counter > 20) break; // time to stop the iteration
if(i%7==0)
{
counter++;
Console.WriteLine(i);
}
}
This can be improved to:
for(int i = 7, counter = 0; counter <= 20; i += 7)
{
Console.WriteLine(i);
counter++;
}
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
add a comment |
You're close. use a counter variable:
int counter = 0; // counter variable
for(int i=1; ; i++) // removed condition
{
if (counter > 20) break; // time to stop the iteration
if(i%7==0)
{
counter++;
Console.WriteLine(i);
}
}
This can be improved to:
for(int i = 7, counter = 0; counter <= 20; i += 7)
{
Console.WriteLine(i);
counter++;
}
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
You're close. use a counter variable:
int counter = 0; // counter variable
for(int i=1; ; i++) // removed condition
{
if (counter > 20) break; // time to stop the iteration
if(i%7==0)
{
counter++;
Console.WriteLine(i);
}
}
This can be improved to:
for(int i = 7, counter = 0; counter <= 20; i += 7)
{
Console.WriteLine(i);
counter++;
}
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
edited Nov 23 '18 at 16:28
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
answered Nov 23 '18 at 16:05
AomineAomine
41.8k74071
41.8k74071
add a comment |
add a comment |
The first 20 integers that are divisible by 7 are easily written as 7,2*7,3*7,4*7,...,20*7. This in your loop you can do:
for(int i = 1; i<=20; i++) {
Console.WriteLine(7*i);
}
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
add a comment |
The first 20 integers that are divisible by 7 are easily written as 7,2*7,3*7,4*7,...,20*7. This in your loop you can do:
for(int i = 1; i<=20; i++) {
Console.WriteLine(7*i);
}
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
add a comment |
The first 20 integers that are divisible by 7 are easily written as 7,2*7,3*7,4*7,...,20*7. This in your loop you can do:
for(int i = 1; i<=20; i++) {
Console.WriteLine(7*i);
}
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
The first 20 integers that are divisible by 7 are easily written as 7,2*7,3*7,4*7,...,20*7. This in your loop you can do:
for(int i = 1; i<=20; i++) {
Console.WriteLine(7*i);
}
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
answered Nov 23 '18 at 16:08
kvantourkvantour
8,45331230
8,45331230
add a comment |
add a comment |
Can’t you just go up in sevens?
for (int multiple = 7, int count = 0; count < 20; multiple += 7, count++)
{
Console.WriteLine(multiple);
}
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
add a comment |
Can’t you just go up in sevens?
for (int multiple = 7, int count = 0; count < 20; multiple += 7, count++)
{
Console.WriteLine(multiple);
}
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
add a comment |
Can’t you just go up in sevens?
for (int multiple = 7, int count = 0; count < 20; multiple += 7, count++)
{
Console.WriteLine(multiple);
}
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
Can’t you just go up in sevens?
for (int multiple = 7, int count = 0; count < 20; multiple += 7, count++)
{
Console.WriteLine(multiple);
}
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
answered Nov 23 '18 at 16:12
GrahamSGrahamS
6,23053556
6,23053556
add a comment |
add a comment |
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