“Offsetting” an equation
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I use Autocad a lot, and a function I commonly use is offset, which takes a line and offsets it whatever distance you specify. An example would be that if you take a circle with a radius of $5$ ft and offset it $3$ ft, it gives you a new radius of $2$ ft. It also works with curves that are not circles -- it just takes every point on the line and shifts it a perpendicular distance of whatever you specify.
I was starting to wonder if it was possible to offset equations of a line in a similar way? Like an equation that was the exact same as $y = x^2$, but every point on it was a perpendicular distance of $5$ units, for example. I figured it would have to take on the form $y = ax^2 + 5$ (or $- 5$), but no idea how you would get that if it were even possible.
graphing-functions
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
$endgroup$
add a comment |
$begingroup$
I use Autocad a lot, and a function I commonly use is offset, which takes a line and offsets it whatever distance you specify. An example would be that if you take a circle with a radius of $5$ ft and offset it $3$ ft, it gives you a new radius of $2$ ft. It also works with curves that are not circles -- it just takes every point on the line and shifts it a perpendicular distance of whatever you specify.
I was starting to wonder if it was possible to offset equations of a line in a similar way? Like an equation that was the exact same as $y = x^2$, but every point on it was a perpendicular distance of $5$ units, for example. I figured it would have to take on the form $y = ax^2 + 5$ (or $- 5$), but no idea how you would get that if it were even possible.
graphing-functions
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
$endgroup$
$begingroup$
parallel curve?
$endgroup$
– achille hui
Apr 8 '18 at 3:26
$begingroup$
exactly. lol guess I didn't know what I was asking for, thanks
$endgroup$
– quesadyllan
Apr 8 '18 at 16:00
add a comment |
$begingroup$
I use Autocad a lot, and a function I commonly use is offset, which takes a line and offsets it whatever distance you specify. An example would be that if you take a circle with a radius of $5$ ft and offset it $3$ ft, it gives you a new radius of $2$ ft. It also works with curves that are not circles -- it just takes every point on the line and shifts it a perpendicular distance of whatever you specify.
I was starting to wonder if it was possible to offset equations of a line in a similar way? Like an equation that was the exact same as $y = x^2$, but every point on it was a perpendicular distance of $5$ units, for example. I figured it would have to take on the form $y = ax^2 + 5$ (or $- 5$), but no idea how you would get that if it were even possible.
graphing-functions
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
$endgroup$
I use Autocad a lot, and a function I commonly use is offset, which takes a line and offsets it whatever distance you specify. An example would be that if you take a circle with a radius of $5$ ft and offset it $3$ ft, it gives you a new radius of $2$ ft. It also works with curves that are not circles -- it just takes every point on the line and shifts it a perpendicular distance of whatever you specify.
I was starting to wonder if it was possible to offset equations of a line in a similar way? Like an equation that was the exact same as $y = x^2$, but every point on it was a perpendicular distance of $5$ units, for example. I figured it would have to take on the form $y = ax^2 + 5$ (or $- 5$), but no idea how you would get that if it were even possible.
graphing-functions
graphing-functions
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
edited Dec 7 '18 at 16:16
Robert Howard
1,9161822
1,9161822
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
asked Apr 8 '18 at 3:14
quesadyllanquesadyllan
6
6
$begingroup$
parallel curve?
$endgroup$
– achille hui
Apr 8 '18 at 3:26
$begingroup$
exactly. lol guess I didn't know what I was asking for, thanks
$endgroup$
– quesadyllan
Apr 8 '18 at 16:00
add a comment |
$begingroup$
parallel curve?
$endgroup$
– achille hui
Apr 8 '18 at 3:26
$begingroup$
exactly. lol guess I didn't know what I was asking for, thanks
$endgroup$
– quesadyllan
Apr 8 '18 at 16:00
$begingroup$
parallel curve?
$endgroup$
– achille hui
Apr 8 '18 at 3:26
$begingroup$
parallel curve?
$endgroup$
– achille hui
Apr 8 '18 at 3:26
$begingroup$
exactly. lol guess I didn't know what I was asking for, thanks
$endgroup$
– quesadyllan
Apr 8 '18 at 16:00
$begingroup$
exactly. lol guess I didn't know what I was asking for, thanks
$endgroup$
– quesadyllan
Apr 8 '18 at 16:00
add a comment |
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$begingroup$
parallel curve?
$endgroup$
– achille hui
Apr 8 '18 at 3:26
$begingroup$
exactly. lol guess I didn't know what I was asking for, thanks
$endgroup$
– quesadyllan
Apr 8 '18 at 16:00