how to set selected value from database into dropdown list
0
I am using dropdown list in my form. If the value already in the database, I want that value doesn't display in the dropdown list.
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row1["bank_name"];?>" <?php if(!empty($_POST['bank_name']) && $_POST['bank_name']==$row_subject['bankname']){echo 'selected="selected"';}?>>
<?php echo $row_subject['bankname'];?>
</option>
<?php } ?>
</select>
How to display the stored value from database into dropdown list?
php html
edited Nov 24 '18 at 7:06
kit
1,1063816
asked Nov 24 '18 at 6:46
antonyantony
16
add a comment |
0
I am using dropdown list in my form. If the value already in the database, I want that value doesn't display in the dropdown list.
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row1["bank_name"];?>" <?php if(!empty($_POST['bank_name']) && $_POST['bank_name']==$row_subject['bankname']){echo 'selected="selected"';}?>>
<?php echo $row_subject['bankname'];?>
</option>
<?php } ?>
</select>
How to display the stored value from database into dropdown list?
php html
edited Nov 24 '18 at 7:06
kit
1,1063816
asked Nov 24 '18 at 6:46
antonyantony
16
add a comment |
0
0
0
I am using dropdown list in my form. If the value already in the database, I want that value doesn't display in the dropdown list.
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row1["bank_name"];?>" <?php if(!empty($_POST['bank_name']) && $_POST['bank_name']==$row_subject['bankname']){echo 'selected="selected"';}?>>
<?php echo $row_subject['bankname'];?>
</option>
<?php } ?>
</select>
How to display the stored value from database into dropdown list?
php html
edited Nov 24 '18 at 7:06
kit
1,1063816
asked Nov 24 '18 at 6:46
antonyantony
16
I am using dropdown list in my form. If the value already in the database, I want that value doesn't display in the dropdown list.
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row1["bank_name"];?>" <?php if(!empty($_POST['bank_name']) && $_POST['bank_name']==$row_subject['bankname']){echo 'selected="selected"';}?>>
<?php echo $row_subject['bankname'];?>
</option>
<?php } ?>
</select>
How to display the stored value from database into dropdown list?
php html
php html
edited Nov 24 '18 at 7:06
kit
1,1063816
asked Nov 24 '18 at 6:46
antonyantony
16
edited Nov 24 '18 at 7:06
kit
1,1063816
asked Nov 24 '18 at 6:46
antonyantony
16
edited Nov 24 '18 at 7:06
kit
1,1063816
edited Nov 24 '18 at 7:06
kit
1,1063816
edited Nov 24 '18 at 7:06
kit
1,1063816
1,1063816
asked Nov 24 '18 at 6:46
antonyantony
16
asked Nov 24 '18 at 6:46
antonyantony
16
asked Nov 24 '18 at 6:46
antonyantony
16
16
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
-1
Try this below . In select box option value you have defined the wrong value ($row1["bank_name"]) and query also not defined the orderby
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname asc ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row_subject["bank_name"];?>" <?php if(!empty($_POST["bank_name"]) && $_POST["bank_name"]==$row_subject["bankname"]){echo 'selected="selected"';}?>>
<?php echo $row_subject["bankname"];?>
</option>
<?php } ?>
</select>
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
-1
Try this below . In select box option value you have defined the wrong value ($row1["bank_name"]) and query also not defined the orderby
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname asc ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row_subject["bank_name"];?>" <?php if(!empty($_POST["bank_name"]) && $_POST["bank_name"]==$row_subject["bankname"]){echo 'selected="selected"';}?>>
<?php echo $row_subject["bankname"];?>
</option>
<?php } ?>
</select>
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
add a comment |
-1
Try this below . In select box option value you have defined the wrong value ($row1["bank_name"]) and query also not defined the orderby
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname asc ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row_subject["bank_name"];?>" <?php if(!empty($_POST["bank_name"]) && $_POST["bank_name"]==$row_subject["bankname"]){echo 'selected="selected"';}?>>
<?php echo $row_subject["bankname"];?>
</option>
<?php } ?>
</select>
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
add a comment |
-1
-1
-1
Try this below . In select box option value you have defined the wrong value ($row1["bank_name"]) and query also not defined the orderby
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname asc ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row_subject["bank_name"];?>" <?php if(!empty($_POST["bank_name"]) && $_POST["bank_name"]==$row_subject["bankname"]){echo 'selected="selected"';}?>>
<?php echo $row_subject["bankname"];?>
</option>
<?php } ?>
</select>
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
Try this below . In select box option value you have defined the wrong value ($row1["bank_name"]) and query also not defined the orderby
<select name="bank_name" id="bank_name" required>
<option value="">Select Bank</option>
<?php
$query_val = mysql_query("SELECT * from bank order by bankname asc ");
while($row_subject = mysql_fetch_array($query_val)) {
?>
<option value="<?php echo $row_subject["bank_name"];?>" <?php if(!empty($_POST["bank_name"]) && $_POST["bank_name"]==$row_subject["bankname"]){echo 'selected="selected"';}?>>
<?php echo $row_subject["bankname"];?>
</option>
<?php } ?>
</select>
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
answered Nov 24 '18 at 6:52
VinothRajaVinothRaja
1,041416
1,041416
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
add a comment |
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
The OP needs to avoid using the mysql_* series of functions which were REMOVED from PHP as of version 7.0 and instead use either the mysqli (MySQL Improved) functions or PDO
– SpacePhoenix
Nov 24 '18 at 7:19
add a comment |
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