Linear algebra: Proving matrix multiplication












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I have an issue with the following homework assignment:



Let A be an m×n matrix and B be an n×n matrix where $b_{kl} = 1$ for fixed $1≤k$, $l≤n$ and $b_{ij} = 0$ for $i neq k$ or $j neq l$. What is the result of AB? Prove your claims!



I understand what the linear map $B$ does, but I don't know how to prove it formally. As far as I understand, matrix (AB) has the $k$th column of A in its $l$th column, and zeros elsewhere.



I would appreciate if you could give me some hints on how to prove this problem.



The problem is the following:










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  • 1




    $begingroup$
    HInt: If $B=[b_1|b_1|cdots|b_n]$ where each $b_i$ is a column vector then $AB=[Ab_1|Ab_|cdots|Ab_n]$.
    $endgroup$
    – user9077
    Dec 10 '18 at 13:52


















0












$begingroup$


I have an issue with the following homework assignment:



Let A be an m×n matrix and B be an n×n matrix where $b_{kl} = 1$ for fixed $1≤k$, $l≤n$ and $b_{ij} = 0$ for $i neq k$ or $j neq l$. What is the result of AB? Prove your claims!



I understand what the linear map $B$ does, but I don't know how to prove it formally. As far as I understand, matrix (AB) has the $k$th column of A in its $l$th column, and zeros elsewhere.



I would appreciate if you could give me some hints on how to prove this problem.



The problem is the following:










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    HInt: If $B=[b_1|b_1|cdots|b_n]$ where each $b_i$ is a column vector then $AB=[Ab_1|Ab_|cdots|Ab_n]$.
    $endgroup$
    – user9077
    Dec 10 '18 at 13:52
















0












0








0





$begingroup$


I have an issue with the following homework assignment:



Let A be an m×n matrix and B be an n×n matrix where $b_{kl} = 1$ for fixed $1≤k$, $l≤n$ and $b_{ij} = 0$ for $i neq k$ or $j neq l$. What is the result of AB? Prove your claims!



I understand what the linear map $B$ does, but I don't know how to prove it formally. As far as I understand, matrix (AB) has the $k$th column of A in its $l$th column, and zeros elsewhere.



I would appreciate if you could give me some hints on how to prove this problem.



The problem is the following:










share|cite|improve this question









$endgroup$




I have an issue with the following homework assignment:



Let A be an m×n matrix and B be an n×n matrix where $b_{kl} = 1$ for fixed $1≤k$, $l≤n$ and $b_{ij} = 0$ for $i neq k$ or $j neq l$. What is the result of AB? Prove your claims!



I understand what the linear map $B$ does, but I don't know how to prove it formally. As far as I understand, matrix (AB) has the $k$th column of A in its $l$th column, and zeros elsewhere.



I would appreciate if you could give me some hints on how to prove this problem.



The problem is the following:







linear-algebra






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 10 '18 at 13:46









Ulrich Paul WohakUlrich Paul Wohak

52




52








  • 1




    $begingroup$
    HInt: If $B=[b_1|b_1|cdots|b_n]$ where each $b_i$ is a column vector then $AB=[Ab_1|Ab_|cdots|Ab_n]$.
    $endgroup$
    – user9077
    Dec 10 '18 at 13:52
















  • 1




    $begingroup$
    HInt: If $B=[b_1|b_1|cdots|b_n]$ where each $b_i$ is a column vector then $AB=[Ab_1|Ab_|cdots|Ab_n]$.
    $endgroup$
    – user9077
    Dec 10 '18 at 13:52










1




1




$begingroup$
HInt: If $B=[b_1|b_1|cdots|b_n]$ where each $b_i$ is a column vector then $AB=[Ab_1|Ab_|cdots|Ab_n]$.
$endgroup$
– user9077
Dec 10 '18 at 13:52






$begingroup$
HInt: If $B=[b_1|b_1|cdots|b_n]$ where each $b_i$ is a column vector then $AB=[Ab_1|Ab_|cdots|Ab_n]$.
$endgroup$
– user9077
Dec 10 '18 at 13:52












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