returning a tuple from a dictionary, I need the key but am getting the value instead
I have a dictionary myDict
{'1': 5, '2': 15, '3', 50}
I have a targetNumber of 12
I'm using this code to find the number closest to 12 in myDict
answer = key, value = min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))
answer returns ('2', 15)
That's the key/value that I want, but what I really need now is the 2.
When I print myDict[key], it returns 15
How can I return what I believe was the key, but now that it is in that tuple, i'm not sure exactly what i'm dealing with.
I'd like to end up with:
2
python dictionary python-2.x
asked Nov 23 '18 at 21:50
yodishyodish
329312
|
show 2 more comments
I have a dictionary myDict
{'1': 5, '2': 15, '3', 50}
I have a targetNumber of 12
I'm using this code to find the number closest to 12 in myDict
answer = key, value = min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))
answer returns ('2', 15)
That's the key/value that I want, but what I really need now is the 2.
When I print myDict[key], it returns 15
How can I return what I believe was the key, but now that it is in that tuple, i'm not sure exactly what i'm dealing with.
I'd like to end up with:
2
python dictionary python-2.x
asked Nov 23 '18 at 21:50
yodishyodish
329312
3
I don't understand... you've got it in answer... it'sanswer[0]...
– Silmathoron
Nov 23 '18 at 21:51
you're right, thank you!
– yodish
Nov 23 '18 at 21:53
it'smyDict[answer[0]]
– Silmathoron
Nov 23 '18 at 21:53
2
answer, forget_this_value =min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))- its called decomposition - you decompose the tuple-result into 2 variables - you do not need key and value ... for that - you can directly useanswer- the 15 is stored infoget_this_value
– Patrick Artner
Nov 23 '18 at 21:57
1
@yodish andforget_this_value(in Patrick Artner's answer) is traditionally sent to_in python, which you already saw in thelambdafunction, for instance
– Silmathoron
Nov 23 '18 at 22:03
|
show 2 more comments
I have a dictionary myDict
{'1': 5, '2': 15, '3', 50}
I have a targetNumber of 12
I'm using this code to find the number closest to 12 in myDict
answer = key, value = min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))
answer returns ('2', 15)
That's the key/value that I want, but what I really need now is the 2.
When I print myDict[key], it returns 15
How can I return what I believe was the key, but now that it is in that tuple, i'm not sure exactly what i'm dealing with.
I'd like to end up with:
2
python dictionary python-2.x
asked Nov 23 '18 at 21:50
yodishyodish
329312
I have a dictionary myDict
{'1': 5, '2': 15, '3', 50}
I have a targetNumber of 12
I'm using this code to find the number closest to 12 in myDict
answer = key, value = min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))
answer returns ('2', 15)
That's the key/value that I want, but what I really need now is the 2.
When I print myDict[key], it returns 15
How can I return what I believe was the key, but now that it is in that tuple, i'm not sure exactly what i'm dealing with.
I'd like to end up with:
2
python dictionary python-2.x
python dictionary python-2.x
asked Nov 23 '18 at 21:50
yodishyodish
329312
asked Nov 23 '18 at 21:50
yodishyodish
329312
asked Nov 23 '18 at 21:50
yodishyodish
329312
asked Nov 23 '18 at 21:50
yodishyodish
329312
asked Nov 23 '18 at 21:50
yodishyodish
329312
329312
3
I don't understand... you've got it in answer... it'sanswer[0]...
– Silmathoron
Nov 23 '18 at 21:51
you're right, thank you!
– yodish
Nov 23 '18 at 21:53
it'smyDict[answer[0]]
– Silmathoron
Nov 23 '18 at 21:53
2
answer, forget_this_value =min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))- its called decomposition - you decompose the tuple-result into 2 variables - you do not need key and value ... for that - you can directly useanswer- the 15 is stored infoget_this_value
– Patrick Artner
Nov 23 '18 at 21:57
1
@yodish andforget_this_value(in Patrick Artner's answer) is traditionally sent to_in python, which you already saw in thelambdafunction, for instance
– Silmathoron
Nov 23 '18 at 22:03
|
show 2 more comments
3
I don't understand... you've got it in answer... it'sanswer[0]...
– Silmathoron
Nov 23 '18 at 21:51
you're right, thank you!
– yodish
Nov 23 '18 at 21:53
it'smyDict[answer[0]]
– Silmathoron
Nov 23 '18 at 21:53
2
answer, forget_this_value =min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))- its called decomposition - you decompose the tuple-result into 2 variables - you do not need key and value ... for that - you can directly useanswer- the 15 is stored infoget_this_value
– Patrick Artner
Nov 23 '18 at 21:57
1
@yodish andforget_this_value(in Patrick Artner's answer) is traditionally sent to_in python, which you already saw in thelambdafunction, for instance
– Silmathoron
Nov 23 '18 at 22:03
3
3
I don't understand... you've got it in answer... it's
answer[0]...– Silmathoron
Nov 23 '18 at 21:51
I don't understand... you've got it in answer... it's
answer[0]...– Silmathoron
Nov 23 '18 at 21:51
you're right, thank you!
– yodish
Nov 23 '18 at 21:53
you're right, thank you!
– yodish
Nov 23 '18 at 21:53
it's
myDict[answer[0]]– Silmathoron
Nov 23 '18 at 21:53
it's
myDict[answer[0]]– Silmathoron
Nov 23 '18 at 21:53
2
2
answer, forget_this_value =min(myDict.items(), key=lambda (_, v): abs(v - targetNumber)) - its called decomposition - you decompose the tuple-result into 2 variables - you do not need key and value ... for that - you can directly use answer - the 15 is stored in foget_this_value– Patrick Artner
Nov 23 '18 at 21:57
answer, forget_this_value =min(myDict.items(), key=lambda (_, v): abs(v - targetNumber)) - its called decomposition - you decompose the tuple-result into 2 variables - you do not need key and value ... for that - you can directly use answer - the 15 is stored in foget_this_value– Patrick Artner
Nov 23 '18 at 21:57
1
1
@yodish and
forget_this_value (in Patrick Artner's answer) is traditionally sent to _ in python, which you already saw in the lambda function, for instance– Silmathoron
Nov 23 '18 at 22:03
@yodish and
forget_this_value (in Patrick Artner's answer) is traditionally sent to _ in python, which you already saw in the lambda function, for instance– Silmathoron
Nov 23 '18 at 22:03
|
show 2 more comments
1 Answer
1
active
oldest
votes
Unpack "answer":
Key, Value = answer
or use
Key = Answer[ 0 ]
Value = Answer{ 1 ]
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Unpack "answer":
Key, Value = answer
or use
Key = Answer[ 0 ]
Value = Answer{ 1 ]
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
add a comment |
Unpack "answer":
Key, Value = answer
or use
Key = Answer[ 0 ]
Value = Answer{ 1 ]
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
add a comment |
Unpack "answer":
Key, Value = answer
or use
Key = Answer[ 0 ]
Value = Answer{ 1 ]
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
Unpack "answer":
Key, Value = answer
or use
Key = Answer[ 0 ]
Value = Answer{ 1 ]
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
answered Nov 23 '18 at 22:12
user1459519user1459519
400313
400313
add a comment |
add a comment |
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3
I don't understand... you've got it in answer... it's
answer[0]...– Silmathoron
Nov 23 '18 at 21:51
you're right, thank you!
– yodish
Nov 23 '18 at 21:53
it's
myDict[answer[0]]– Silmathoron
Nov 23 '18 at 21:53
2
answer, forget_this_value =min(myDict.items(), key=lambda (_, v): abs(v - targetNumber))- its called decomposition - you decompose the tuple-result into 2 variables - you do not need key and value ... for that - you can directly useanswer- the 15 is stored infoget_this_value– Patrick Artner
Nov 23 '18 at 21:57
1
@yodish and
forget_this_value(in Patrick Artner's answer) is traditionally sent to_in python, which you already saw in thelambdafunction, for instance– Silmathoron
Nov 23 '18 at 22:03