Prove that $sim$ is an equivalence relation on the set $A$












0














Let $A$ be a nonempty set and $C$ is a partition of $A$.



A relation $sim$ is defined as:
$$For x, y in A, xsim y if and only if there exists U in C such that x in U and y in U .$$



I have to prove that $sim$ is an equivalence relation on the set $A$. Earlier in this problem, I had to prove that $sim$ was an equivalence relation on $A = { a, b, c, d, e}$ (it was part a of this 4 part problem). In this case, the set $A$ is being generalized. I'm confused on how to prove this without having specific "examples" that I could use like I did in part a of this question.










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  • Your reference to "earlier in this problem" is confusing. Are you sure it's the same $A$ and relation here as there? Your question is straightforward if you omit the last sentence: check the properties you need for an equivalence relation, edit the question to tell us where you are stuck.
    – Ethan Bolker
    Nov 30 at 0:48












  • I meant earlier in the problem that I was assigned for homework, this part that I'm asking a question about is for part c of the 4 part question. The last sentence is referring to what I had to do in part a of the question. The difference between part a and part c is that the set is being generalized in part c.
    – Claire
    Nov 30 at 0:50






  • 2




    You will need to know the definition of a partition. The properties of an equivalence relation should follow almost immediately. For example, $sim$ will be reflexive because for any $xin A$ you will have by definition of partitions some $Uin C$ such that $xin U$. It is clear that given that $xin U$ it follows that simultaneously $color{red}{x}in U$ and $color{blue}{x}in U$ so $color{red}{x}sim color{blue}{x}$. (Color is of course not necessary here, but it feels silly to just repeat $xin U$ four times in a row and have it be clear why I would do so).
    – JMoravitz
    Nov 30 at 0:51


















0














Let $A$ be a nonempty set and $C$ is a partition of $A$.



A relation $sim$ is defined as:
$$For x, y in A, xsim y if and only if there exists U in C such that x in U and y in U .$$



I have to prove that $sim$ is an equivalence relation on the set $A$. Earlier in this problem, I had to prove that $sim$ was an equivalence relation on $A = { a, b, c, d, e}$ (it was part a of this 4 part problem). In this case, the set $A$ is being generalized. I'm confused on how to prove this without having specific "examples" that I could use like I did in part a of this question.










share|cite|improve this question
























  • Your reference to "earlier in this problem" is confusing. Are you sure it's the same $A$ and relation here as there? Your question is straightforward if you omit the last sentence: check the properties you need for an equivalence relation, edit the question to tell us where you are stuck.
    – Ethan Bolker
    Nov 30 at 0:48












  • I meant earlier in the problem that I was assigned for homework, this part that I'm asking a question about is for part c of the 4 part question. The last sentence is referring to what I had to do in part a of the question. The difference between part a and part c is that the set is being generalized in part c.
    – Claire
    Nov 30 at 0:50






  • 2




    You will need to know the definition of a partition. The properties of an equivalence relation should follow almost immediately. For example, $sim$ will be reflexive because for any $xin A$ you will have by definition of partitions some $Uin C$ such that $xin U$. It is clear that given that $xin U$ it follows that simultaneously $color{red}{x}in U$ and $color{blue}{x}in U$ so $color{red}{x}sim color{blue}{x}$. (Color is of course not necessary here, but it feels silly to just repeat $xin U$ four times in a row and have it be clear why I would do so).
    – JMoravitz
    Nov 30 at 0:51
















0












0








0







Let $A$ be a nonempty set and $C$ is a partition of $A$.



A relation $sim$ is defined as:
$$For x, y in A, xsim y if and only if there exists U in C such that x in U and y in U .$$



I have to prove that $sim$ is an equivalence relation on the set $A$. Earlier in this problem, I had to prove that $sim$ was an equivalence relation on $A = { a, b, c, d, e}$ (it was part a of this 4 part problem). In this case, the set $A$ is being generalized. I'm confused on how to prove this without having specific "examples" that I could use like I did in part a of this question.










share|cite|improve this question















Let $A$ be a nonempty set and $C$ is a partition of $A$.



A relation $sim$ is defined as:
$$For x, y in A, xsim y if and only if there exists U in C such that x in U and y in U .$$



I have to prove that $sim$ is an equivalence relation on the set $A$. Earlier in this problem, I had to prove that $sim$ was an equivalence relation on $A = { a, b, c, d, e}$ (it was part a of this 4 part problem). In this case, the set $A$ is being generalized. I'm confused on how to prove this without having specific "examples" that I could use like I did in part a of this question.







equivalence-relations set-partition






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share|cite|improve this question













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share|cite|improve this question








edited Nov 30 at 0:52

























asked Nov 30 at 0:43









Claire

556




556












  • Your reference to "earlier in this problem" is confusing. Are you sure it's the same $A$ and relation here as there? Your question is straightforward if you omit the last sentence: check the properties you need for an equivalence relation, edit the question to tell us where you are stuck.
    – Ethan Bolker
    Nov 30 at 0:48












  • I meant earlier in the problem that I was assigned for homework, this part that I'm asking a question about is for part c of the 4 part question. The last sentence is referring to what I had to do in part a of the question. The difference between part a and part c is that the set is being generalized in part c.
    – Claire
    Nov 30 at 0:50






  • 2




    You will need to know the definition of a partition. The properties of an equivalence relation should follow almost immediately. For example, $sim$ will be reflexive because for any $xin A$ you will have by definition of partitions some $Uin C$ such that $xin U$. It is clear that given that $xin U$ it follows that simultaneously $color{red}{x}in U$ and $color{blue}{x}in U$ so $color{red}{x}sim color{blue}{x}$. (Color is of course not necessary here, but it feels silly to just repeat $xin U$ four times in a row and have it be clear why I would do so).
    – JMoravitz
    Nov 30 at 0:51




















  • Your reference to "earlier in this problem" is confusing. Are you sure it's the same $A$ and relation here as there? Your question is straightforward if you omit the last sentence: check the properties you need for an equivalence relation, edit the question to tell us where you are stuck.
    – Ethan Bolker
    Nov 30 at 0:48












  • I meant earlier in the problem that I was assigned for homework, this part that I'm asking a question about is for part c of the 4 part question. The last sentence is referring to what I had to do in part a of the question. The difference between part a and part c is that the set is being generalized in part c.
    – Claire
    Nov 30 at 0:50






  • 2




    You will need to know the definition of a partition. The properties of an equivalence relation should follow almost immediately. For example, $sim$ will be reflexive because for any $xin A$ you will have by definition of partitions some $Uin C$ such that $xin U$. It is clear that given that $xin U$ it follows that simultaneously $color{red}{x}in U$ and $color{blue}{x}in U$ so $color{red}{x}sim color{blue}{x}$. (Color is of course not necessary here, but it feels silly to just repeat $xin U$ four times in a row and have it be clear why I would do so).
    – JMoravitz
    Nov 30 at 0:51


















Your reference to "earlier in this problem" is confusing. Are you sure it's the same $A$ and relation here as there? Your question is straightforward if you omit the last sentence: check the properties you need for an equivalence relation, edit the question to tell us where you are stuck.
– Ethan Bolker
Nov 30 at 0:48






Your reference to "earlier in this problem" is confusing. Are you sure it's the same $A$ and relation here as there? Your question is straightforward if you omit the last sentence: check the properties you need for an equivalence relation, edit the question to tell us where you are stuck.
– Ethan Bolker
Nov 30 at 0:48














I meant earlier in the problem that I was assigned for homework, this part that I'm asking a question about is for part c of the 4 part question. The last sentence is referring to what I had to do in part a of the question. The difference between part a and part c is that the set is being generalized in part c.
– Claire
Nov 30 at 0:50




I meant earlier in the problem that I was assigned for homework, this part that I'm asking a question about is for part c of the 4 part question. The last sentence is referring to what I had to do in part a of the question. The difference between part a and part c is that the set is being generalized in part c.
– Claire
Nov 30 at 0:50




2




2




You will need to know the definition of a partition. The properties of an equivalence relation should follow almost immediately. For example, $sim$ will be reflexive because for any $xin A$ you will have by definition of partitions some $Uin C$ such that $xin U$. It is clear that given that $xin U$ it follows that simultaneously $color{red}{x}in U$ and $color{blue}{x}in U$ so $color{red}{x}sim color{blue}{x}$. (Color is of course not necessary here, but it feels silly to just repeat $xin U$ four times in a row and have it be clear why I would do so).
– JMoravitz
Nov 30 at 0:51






You will need to know the definition of a partition. The properties of an equivalence relation should follow almost immediately. For example, $sim$ will be reflexive because for any $xin A$ you will have by definition of partitions some $Uin C$ such that $xin U$. It is clear that given that $xin U$ it follows that simultaneously $color{red}{x}in U$ and $color{blue}{x}in U$ so $color{red}{x}sim color{blue}{x}$. (Color is of course not necessary here, but it feels silly to just repeat $xin U$ four times in a row and have it be clear why I would do so).
– JMoravitz
Nov 30 at 0:51












1 Answer
1






active

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3














This follows directly by definition of partition. A partition of a set $A$, $C$ is a class of sets $U_alpha$ so that every element of a $A$ is in some $U_alpha$ and the $U_alpha$ are disjoint.



Reflexive says:



There exists a $U$ so that $ain U$ and $a in U$.



By definition of partition there is some $U$ so that for each $ain A$ there is a $U$ so that $ain U$. (and therefore $a in U$).



Symmetric says:



If there exists a $U$ so that $a,b in U$ then there exists a $U$ so that $b,a in U$.



(Don't need to say anything more.)



Transitive says:



If there exists a $U$ so that $a,b in U$ and and $V$ so that $b,cin V$ then there is a $W$ so that $a,c in W$.



By definition of partition, the partitioning sets are disjoint. So if $bin U$ and $b in V$ then $U= V$. So if there exists a $U$ so that $a,b in U$ and if there exists a $V$ so that $b,c in V$ then $U=V$ and $a,b,c in V$.






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  • To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
    – DanielWainfleet
    Nov 30 at 1:44











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1 Answer
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active

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














This follows directly by definition of partition. A partition of a set $A$, $C$ is a class of sets $U_alpha$ so that every element of a $A$ is in some $U_alpha$ and the $U_alpha$ are disjoint.



Reflexive says:



There exists a $U$ so that $ain U$ and $a in U$.



By definition of partition there is some $U$ so that for each $ain A$ there is a $U$ so that $ain U$. (and therefore $a in U$).



Symmetric says:



If there exists a $U$ so that $a,b in U$ then there exists a $U$ so that $b,a in U$.



(Don't need to say anything more.)



Transitive says:



If there exists a $U$ so that $a,b in U$ and and $V$ so that $b,cin V$ then there is a $W$ so that $a,c in W$.



By definition of partition, the partitioning sets are disjoint. So if $bin U$ and $b in V$ then $U= V$. So if there exists a $U$ so that $a,b in U$ and if there exists a $V$ so that $b,c in V$ then $U=V$ and $a,b,c in V$.






share|cite|improve this answer





















  • To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
    – DanielWainfleet
    Nov 30 at 1:44
















3














This follows directly by definition of partition. A partition of a set $A$, $C$ is a class of sets $U_alpha$ so that every element of a $A$ is in some $U_alpha$ and the $U_alpha$ are disjoint.



Reflexive says:



There exists a $U$ so that $ain U$ and $a in U$.



By definition of partition there is some $U$ so that for each $ain A$ there is a $U$ so that $ain U$. (and therefore $a in U$).



Symmetric says:



If there exists a $U$ so that $a,b in U$ then there exists a $U$ so that $b,a in U$.



(Don't need to say anything more.)



Transitive says:



If there exists a $U$ so that $a,b in U$ and and $V$ so that $b,cin V$ then there is a $W$ so that $a,c in W$.



By definition of partition, the partitioning sets are disjoint. So if $bin U$ and $b in V$ then $U= V$. So if there exists a $U$ so that $a,b in U$ and if there exists a $V$ so that $b,c in V$ then $U=V$ and $a,b,c in V$.






share|cite|improve this answer





















  • To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
    – DanielWainfleet
    Nov 30 at 1:44














3












3








3






This follows directly by definition of partition. A partition of a set $A$, $C$ is a class of sets $U_alpha$ so that every element of a $A$ is in some $U_alpha$ and the $U_alpha$ are disjoint.



Reflexive says:



There exists a $U$ so that $ain U$ and $a in U$.



By definition of partition there is some $U$ so that for each $ain A$ there is a $U$ so that $ain U$. (and therefore $a in U$).



Symmetric says:



If there exists a $U$ so that $a,b in U$ then there exists a $U$ so that $b,a in U$.



(Don't need to say anything more.)



Transitive says:



If there exists a $U$ so that $a,b in U$ and and $V$ so that $b,cin V$ then there is a $W$ so that $a,c in W$.



By definition of partition, the partitioning sets are disjoint. So if $bin U$ and $b in V$ then $U= V$. So if there exists a $U$ so that $a,b in U$ and if there exists a $V$ so that $b,c in V$ then $U=V$ and $a,b,c in V$.






share|cite|improve this answer












This follows directly by definition of partition. A partition of a set $A$, $C$ is a class of sets $U_alpha$ so that every element of a $A$ is in some $U_alpha$ and the $U_alpha$ are disjoint.



Reflexive says:



There exists a $U$ so that $ain U$ and $a in U$.



By definition of partition there is some $U$ so that for each $ain A$ there is a $U$ so that $ain U$. (and therefore $a in U$).



Symmetric says:



If there exists a $U$ so that $a,b in U$ then there exists a $U$ so that $b,a in U$.



(Don't need to say anything more.)



Transitive says:



If there exists a $U$ so that $a,b in U$ and and $V$ so that $b,cin V$ then there is a $W$ so that $a,c in W$.



By definition of partition, the partitioning sets are disjoint. So if $bin U$ and $b in V$ then $U= V$. So if there exists a $U$ so that $a,b in U$ and if there exists a $V$ so that $b,c in V$ then $U=V$ and $a,b,c in V$.







share|cite|improve this answer












share|cite|improve this answer



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answered Nov 30 at 1:19









fleablood

68.1k22684




68.1k22684












  • To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
    – DanielWainfleet
    Nov 30 at 1:44


















  • To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
    – DanielWainfleet
    Nov 30 at 1:44
















To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
– DanielWainfleet
Nov 30 at 1:44




To the proposer: The definition of a partition C of a set A requires that for all $ain A$ there is EXACTLY ONE $Uin C$ such that $ain U.$
– DanielWainfleet
Nov 30 at 1:44


















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