asp.net-mvc get a dictionary in post action or how to transform FormCollection into a dictionary
5
anybody knows how to transform the FormCollection into a IDictionary or how to get a IDictionary in the post action ?
asp.net-mvc formcollection
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
add a comment |
5
anybody knows how to transform the FormCollection into a IDictionary or how to get a IDictionary in the post action ?
asp.net-mvc formcollection
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
add a comment |
5
5
5
1
anybody knows how to transform the FormCollection into a IDictionary or how to get a IDictionary in the post action ?
asp.net-mvc formcollection
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
anybody knows how to transform the FormCollection into a IDictionary or how to get a IDictionary in the post action ?
asp.net-mvc formcollection
asp.net-mvc formcollection
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
edited Nov 24 '18 at 1:41
Roman Marusyk
12.1k123668
12.1k123668
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
asked May 4 '10 at 11:29
OmuOmu
32.5k74234378
32.5k74234378
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
13
This is just an equivalent of Omnu's code, but it seems more elegant to me:
Dictionary<string, string> form = formCollection.AllKeys.ToDictionary(k => k, v => formCollection[v]);
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
add a comment |
1
I did it like this:
var form = new Dictionary<string, string>();
foreach (var key in formCollection.AllKeys)
{
var value = formCollection[key];
form.Add(key, value);
}
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
add a comment |
0
public static IDictionary<string, string> GetFormParameters(FormCollection collection)
{
IDictionary<string, string> formParameters = new Dictionary<string, string>();
foreach (var key in collection.AllKeys)
{
if (key == null) continue;
var value = collection.GetValues(key);
// value = CrossSiteAttackUtil.CleanHtml(value);
if (value != null)
{
formParameters.Add(key, value);
}
}
answered Jul 18 '15 at 10:11
user1606925user1606925
1
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
13
This is just an equivalent of Omnu's code, but it seems more elegant to me:
Dictionary<string, string> form = formCollection.AllKeys.ToDictionary(k => k, v => formCollection[v]);
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
add a comment |
13
This is just an equivalent of Omnu's code, but it seems more elegant to me:
Dictionary<string, string> form = formCollection.AllKeys.ToDictionary(k => k, v => formCollection[v]);
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
add a comment |
13
13
13
This is just an equivalent of Omnu's code, but it seems more elegant to me:
Dictionary<string, string> form = formCollection.AllKeys.ToDictionary(k => k, v => formCollection[v]);
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
This is just an equivalent of Omnu's code, but it seems more elegant to me:
Dictionary<string, string> form = formCollection.AllKeys.ToDictionary(k => k, v => formCollection[v]);
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
answered May 4 '10 at 12:44
TrimackTrimack
2,32383666
2,32383666
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
add a comment |
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
I think it's a matter of style, i personally think Omu's code is a little more verbose, but it's easier to see what happens.
– Michel
May 4 '10 at 12:48
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
prefer this solution, much neater
– Nigel Fds
Nov 9 '18 at 0:38
add a comment |
1
I did it like this:
var form = new Dictionary<string, string>();
foreach (var key in formCollection.AllKeys)
{
var value = formCollection[key];
form.Add(key, value);
}
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
add a comment |
1
I did it like this:
var form = new Dictionary<string, string>();
foreach (var key in formCollection.AllKeys)
{
var value = formCollection[key];
form.Add(key, value);
}
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
add a comment |
1
1
1
I did it like this:
var form = new Dictionary<string, string>();
foreach (var key in formCollection.AllKeys)
{
var value = formCollection[key];
form.Add(key, value);
}
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
I did it like this:
var form = new Dictionary<string, string>();
foreach (var key in formCollection.AllKeys)
{
var value = formCollection[key];
form.Add(key, value);
}
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
answered May 4 '10 at 12:37
OmuOmu
32.5k74234378
32.5k74234378
add a comment |
add a comment |
0
public static IDictionary<string, string> GetFormParameters(FormCollection collection)
{
IDictionary<string, string> formParameters = new Dictionary<string, string>();
foreach (var key in collection.AllKeys)
{
if (key == null) continue;
var value = collection.GetValues(key);
// value = CrossSiteAttackUtil.CleanHtml(value);
if (value != null)
{
formParameters.Add(key, value);
}
}
answered Jul 18 '15 at 10:11
user1606925user1606925
1
add a comment |
0
public static IDictionary<string, string> GetFormParameters(FormCollection collection)
{
IDictionary<string, string> formParameters = new Dictionary<string, string>();
foreach (var key in collection.AllKeys)
{
if (key == null) continue;
var value = collection.GetValues(key);
// value = CrossSiteAttackUtil.CleanHtml(value);
if (value != null)
{
formParameters.Add(key, value);
}
}
answered Jul 18 '15 at 10:11
user1606925user1606925
1
add a comment |
0
0
0
public static IDictionary<string, string> GetFormParameters(FormCollection collection)
{
IDictionary<string, string> formParameters = new Dictionary<string, string>();
foreach (var key in collection.AllKeys)
{
if (key == null) continue;
var value = collection.GetValues(key);
// value = CrossSiteAttackUtil.CleanHtml(value);
if (value != null)
{
formParameters.Add(key, value);
}
}
answered Jul 18 '15 at 10:11
user1606925user1606925
1
public static IDictionary<string, string> GetFormParameters(FormCollection collection)
{
IDictionary<string, string> formParameters = new Dictionary<string, string>();
foreach (var key in collection.AllKeys)
{
if (key == null) continue;
var value = collection.GetValues(key);
// value = CrossSiteAttackUtil.CleanHtml(value);
if (value != null)
{
formParameters.Add(key, value);
}
}
answered Jul 18 '15 at 10:11
user1606925user1606925
1
answered Jul 18 '15 at 10:11
user1606925user1606925
1
answered Jul 18 '15 at 10:11
user1606925user1606925
1
answered Jul 18 '15 at 10:11
user1606925user1606925
1
1
add a comment |
add a comment |
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