Word for the dimension of the vector space in which a vector lives?
$begingroup$
The following issue comes up whenever I teach linear algebra: I want to have a quick way to say that a vector $(x,y,z)$ is in $mathbb{R}^3$. I am tempted to say that it has "length $3$". But then some student interprets this as saying that $sqrt{x^2+y^2+z^2} = 3$. Is there some word other than "length" I could introduce and use to consistently refer to the number of coordinates in a vector? (To point out that I am not nuts here, the commands to get this number in Mathematica and MATLAB are Length
and length()
.)
linear-algebra vocabulary
$endgroup$
|
show 1 more comment
$begingroup$
The following issue comes up whenever I teach linear algebra: I want to have a quick way to say that a vector $(x,y,z)$ is in $mathbb{R}^3$. I am tempted to say that it has "length $3$". But then some student interprets this as saying that $sqrt{x^2+y^2+z^2} = 3$. Is there some word other than "length" I could introduce and use to consistently refer to the number of coordinates in a vector? (To point out that I am not nuts here, the commands to get this number in Mathematica and MATLAB are Length
and length()
.)
linear-algebra vocabulary
$endgroup$
3
$begingroup$
Would "dimension" do?
$endgroup$
– Jasper
Dec 9 '18 at 16:22
2
$begingroup$
This notion is extrinsic; there is no way to look at an object and tell 'the' vector space it belongs to (and one has stuff like $mathbb{R}^{2n} simeq mathbb{C}^n$). But seconded, maybe 'of real dimension 3' or 'real 3-tuple' might do.
$endgroup$
– Vandermonde
Dec 9 '18 at 16:29
$begingroup$
I would also use dimension, but if the vector is known to sit inside some proper subspace I might also use "ambient dimension" to indicate how many components it has.
$endgroup$
– Adam
Dec 9 '18 at 16:44
1
$begingroup$
@user683: $n$-vector has the unfortunate collision with certain physics terminology.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:02
1
$begingroup$
More to the point of the question itself: which kind of linear algebra course are you teaching? Is this an abstract linear algebra course, or an engineering one? What is your main perspective in terms of identifying an $n$-dimensional vector space over the field $mathbb{F}$ with the space of $n$-tuples $mathbb{F}^n$? I ask because the programming conventions are implicitly fixing a basis and always identifying vectors with tuples, hence thelength()
.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:05
|
show 1 more comment
$begingroup$
The following issue comes up whenever I teach linear algebra: I want to have a quick way to say that a vector $(x,y,z)$ is in $mathbb{R}^3$. I am tempted to say that it has "length $3$". But then some student interprets this as saying that $sqrt{x^2+y^2+z^2} = 3$. Is there some word other than "length" I could introduce and use to consistently refer to the number of coordinates in a vector? (To point out that I am not nuts here, the commands to get this number in Mathematica and MATLAB are Length
and length()
.)
linear-algebra vocabulary
$endgroup$
The following issue comes up whenever I teach linear algebra: I want to have a quick way to say that a vector $(x,y,z)$ is in $mathbb{R}^3$. I am tempted to say that it has "length $3$". But then some student interprets this as saying that $sqrt{x^2+y^2+z^2} = 3$. Is there some word other than "length" I could introduce and use to consistently refer to the number of coordinates in a vector? (To point out that I am not nuts here, the commands to get this number in Mathematica and MATLAB are Length
and length()
.)
linear-algebra vocabulary
linear-algebra vocabulary
edited Dec 9 '18 at 16:38
David E Speyer
asked Dec 9 '18 at 15:42
David E SpeyerDavid E Speyer
2,305920
2,305920
3
$begingroup$
Would "dimension" do?
$endgroup$
– Jasper
Dec 9 '18 at 16:22
2
$begingroup$
This notion is extrinsic; there is no way to look at an object and tell 'the' vector space it belongs to (and one has stuff like $mathbb{R}^{2n} simeq mathbb{C}^n$). But seconded, maybe 'of real dimension 3' or 'real 3-tuple' might do.
$endgroup$
– Vandermonde
Dec 9 '18 at 16:29
$begingroup$
I would also use dimension, but if the vector is known to sit inside some proper subspace I might also use "ambient dimension" to indicate how many components it has.
$endgroup$
– Adam
Dec 9 '18 at 16:44
1
$begingroup$
@user683: $n$-vector has the unfortunate collision with certain physics terminology.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:02
1
$begingroup$
More to the point of the question itself: which kind of linear algebra course are you teaching? Is this an abstract linear algebra course, or an engineering one? What is your main perspective in terms of identifying an $n$-dimensional vector space over the field $mathbb{F}$ with the space of $n$-tuples $mathbb{F}^n$? I ask because the programming conventions are implicitly fixing a basis and always identifying vectors with tuples, hence thelength()
.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:05
|
show 1 more comment
3
$begingroup$
Would "dimension" do?
$endgroup$
– Jasper
Dec 9 '18 at 16:22
2
$begingroup$
This notion is extrinsic; there is no way to look at an object and tell 'the' vector space it belongs to (and one has stuff like $mathbb{R}^{2n} simeq mathbb{C}^n$). But seconded, maybe 'of real dimension 3' or 'real 3-tuple' might do.
$endgroup$
– Vandermonde
Dec 9 '18 at 16:29
$begingroup$
I would also use dimension, but if the vector is known to sit inside some proper subspace I might also use "ambient dimension" to indicate how many components it has.
$endgroup$
– Adam
Dec 9 '18 at 16:44
1
$begingroup$
@user683: $n$-vector has the unfortunate collision with certain physics terminology.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:02
1
$begingroup$
More to the point of the question itself: which kind of linear algebra course are you teaching? Is this an abstract linear algebra course, or an engineering one? What is your main perspective in terms of identifying an $n$-dimensional vector space over the field $mathbb{F}$ with the space of $n$-tuples $mathbb{F}^n$? I ask because the programming conventions are implicitly fixing a basis and always identifying vectors with tuples, hence thelength()
.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:05
3
3
$begingroup$
Would "dimension" do?
$endgroup$
– Jasper
Dec 9 '18 at 16:22
$begingroup$
Would "dimension" do?
$endgroup$
– Jasper
Dec 9 '18 at 16:22
2
2
$begingroup$
This notion is extrinsic; there is no way to look at an object and tell 'the' vector space it belongs to (and one has stuff like $mathbb{R}^{2n} simeq mathbb{C}^n$). But seconded, maybe 'of real dimension 3' or 'real 3-tuple' might do.
$endgroup$
– Vandermonde
Dec 9 '18 at 16:29
$begingroup$
This notion is extrinsic; there is no way to look at an object and tell 'the' vector space it belongs to (and one has stuff like $mathbb{R}^{2n} simeq mathbb{C}^n$). But seconded, maybe 'of real dimension 3' or 'real 3-tuple' might do.
$endgroup$
– Vandermonde
Dec 9 '18 at 16:29
$begingroup$
I would also use dimension, but if the vector is known to sit inside some proper subspace I might also use "ambient dimension" to indicate how many components it has.
$endgroup$
– Adam
Dec 9 '18 at 16:44
$begingroup$
I would also use dimension, but if the vector is known to sit inside some proper subspace I might also use "ambient dimension" to indicate how many components it has.
$endgroup$
– Adam
Dec 9 '18 at 16:44
1
1
$begingroup$
@user683: $n$-vector has the unfortunate collision with certain physics terminology.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:02
$begingroup$
@user683: $n$-vector has the unfortunate collision with certain physics terminology.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:02
1
1
$begingroup$
More to the point of the question itself: which kind of linear algebra course are you teaching? Is this an abstract linear algebra course, or an engineering one? What is your main perspective in terms of identifying an $n$-dimensional vector space over the field $mathbb{F}$ with the space of $n$-tuples $mathbb{F}^n$? I ask because the programming conventions are implicitly fixing a basis and always identifying vectors with tuples, hence the
length()
.$endgroup$
– Willie Wong
Dec 10 '18 at 15:05
$begingroup$
More to the point of the question itself: which kind of linear algebra course are you teaching? Is this an abstract linear algebra course, or an engineering one? What is your main perspective in terms of identifying an $n$-dimensional vector space over the field $mathbb{F}$ with the space of $n$-tuples $mathbb{F}^n$? I ask because the programming conventions are implicitly fixing a basis and always identifying vectors with tuples, hence the
length()
.$endgroup$
– Willie Wong
Dec 10 '18 at 15:05
|
show 1 more comment
3 Answers
3
active
oldest
votes
$begingroup$
If all your spaces are $mathbb{R}^n$ then you can say n-dimensional (three-dimensional for $mathbb{R}^3$). However the space of matrices $displaystyle left(begin{array}{cc}a&b\c&dend{array}right)$ ($a,b,c,dinmathbb{C}$) is four-dimensional over $mathbb{C}$, eight-dimensional over $mathbb{R}$ and infinite-dimensional over $mathbb{Q}$. So be clear what the base field is. Alternatively you could just write $(a,b,c)inleft(mathbb{R}^3,+,cdotright)$ or more briefly $(a,b,c)inmathbb{R}^3$.
$endgroup$
add a comment |
$begingroup$
Along with "dimension", you could also use "component".
A vector in three dimensions has three components.
$endgroup$
add a comment |
$begingroup$
I say "This is a 3D vector" or "This is a 7D vector".
$endgroup$
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "548"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmatheducators.stackexchange.com%2fquestions%2f14882%2fword-for-the-dimension-of-the-vector-space-in-which-a-vector-lives%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If all your spaces are $mathbb{R}^n$ then you can say n-dimensional (three-dimensional for $mathbb{R}^3$). However the space of matrices $displaystyle left(begin{array}{cc}a&b\c&dend{array}right)$ ($a,b,c,dinmathbb{C}$) is four-dimensional over $mathbb{C}$, eight-dimensional over $mathbb{R}$ and infinite-dimensional over $mathbb{Q}$. So be clear what the base field is. Alternatively you could just write $(a,b,c)inleft(mathbb{R}^3,+,cdotright)$ or more briefly $(a,b,c)inmathbb{R}^3$.
$endgroup$
add a comment |
$begingroup$
If all your spaces are $mathbb{R}^n$ then you can say n-dimensional (three-dimensional for $mathbb{R}^3$). However the space of matrices $displaystyle left(begin{array}{cc}a&b\c&dend{array}right)$ ($a,b,c,dinmathbb{C}$) is four-dimensional over $mathbb{C}$, eight-dimensional over $mathbb{R}$ and infinite-dimensional over $mathbb{Q}$. So be clear what the base field is. Alternatively you could just write $(a,b,c)inleft(mathbb{R}^3,+,cdotright)$ or more briefly $(a,b,c)inmathbb{R}^3$.
$endgroup$
add a comment |
$begingroup$
If all your spaces are $mathbb{R}^n$ then you can say n-dimensional (three-dimensional for $mathbb{R}^3$). However the space of matrices $displaystyle left(begin{array}{cc}a&b\c&dend{array}right)$ ($a,b,c,dinmathbb{C}$) is four-dimensional over $mathbb{C}$, eight-dimensional over $mathbb{R}$ and infinite-dimensional over $mathbb{Q}$. So be clear what the base field is. Alternatively you could just write $(a,b,c)inleft(mathbb{R}^3,+,cdotright)$ or more briefly $(a,b,c)inmathbb{R}^3$.
$endgroup$
If all your spaces are $mathbb{R}^n$ then you can say n-dimensional (three-dimensional for $mathbb{R}^3$). However the space of matrices $displaystyle left(begin{array}{cc}a&b\c&dend{array}right)$ ($a,b,c,dinmathbb{C}$) is four-dimensional over $mathbb{C}$, eight-dimensional over $mathbb{R}$ and infinite-dimensional over $mathbb{Q}$. So be clear what the base field is. Alternatively you could just write $(a,b,c)inleft(mathbb{R}^3,+,cdotright)$ or more briefly $(a,b,c)inmathbb{R}^3$.
answered Dec 9 '18 at 17:45
BPPBPP
576316
576316
add a comment |
add a comment |
$begingroup$
Along with "dimension", you could also use "component".
A vector in three dimensions has three components.
$endgroup$
add a comment |
$begingroup$
Along with "dimension", you could also use "component".
A vector in three dimensions has three components.
$endgroup$
add a comment |
$begingroup$
Along with "dimension", you could also use "component".
A vector in three dimensions has three components.
$endgroup$
Along with "dimension", you could also use "component".
A vector in three dimensions has three components.
answered Dec 9 '18 at 21:59
robphyrobphy
3713
3713
add a comment |
add a comment |
$begingroup$
I say "This is a 3D vector" or "This is a 7D vector".
$endgroup$
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
add a comment |
$begingroup$
I say "This is a 3D vector" or "This is a 7D vector".
$endgroup$
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
add a comment |
$begingroup$
I say "This is a 3D vector" or "This is a 7D vector".
$endgroup$
I say "This is a 3D vector" or "This is a 7D vector".
answered Dec 9 '18 at 16:34
Steven GubkinSteven Gubkin
8,42812348
8,42812348
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
add a comment |
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
$begingroup$
I feel compelled to comment that this is used in a social context in which we are working on some problem involving some vectors in $mathbb{R}^n$, where these vectors are being thought of as lists of numbers. I certainly wouldn't use this terminology if I was talking about a vector living in an arbitrary vector space.
$endgroup$
– Steven Gubkin
Dec 11 '18 at 1:41
add a comment |
Thanks for contributing an answer to Mathematics Educators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmatheducators.stackexchange.com%2fquestions%2f14882%2fword-for-the-dimension-of-the-vector-space-in-which-a-vector-lives%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
3
$begingroup$
Would "dimension" do?
$endgroup$
– Jasper
Dec 9 '18 at 16:22
2
$begingroup$
This notion is extrinsic; there is no way to look at an object and tell 'the' vector space it belongs to (and one has stuff like $mathbb{R}^{2n} simeq mathbb{C}^n$). But seconded, maybe 'of real dimension 3' or 'real 3-tuple' might do.
$endgroup$
– Vandermonde
Dec 9 '18 at 16:29
$begingroup$
I would also use dimension, but if the vector is known to sit inside some proper subspace I might also use "ambient dimension" to indicate how many components it has.
$endgroup$
– Adam
Dec 9 '18 at 16:44
1
$begingroup$
@user683: $n$-vector has the unfortunate collision with certain physics terminology.
$endgroup$
– Willie Wong
Dec 10 '18 at 15:02
1
$begingroup$
More to the point of the question itself: which kind of linear algebra course are you teaching? Is this an abstract linear algebra course, or an engineering one? What is your main perspective in terms of identifying an $n$-dimensional vector space over the field $mathbb{F}$ with the space of $n$-tuples $mathbb{F}^n$? I ask because the programming conventions are implicitly fixing a basis and always identifying vectors with tuples, hence the
length()
.$endgroup$
– Willie Wong
Dec 10 '18 at 15:05