Typescript wrapping types
I have some factory method which is making some computations and manipulations. Also I have a generic method doSomething. I don't wanna to specify type for doSomething each time. I would like to do it once for factory method and then get it each time with already assigned type
function factory<T>(t: T){
// some computations
return {method: doSomething<T>} <- this is what I wanna do
}
// Generic
function<T extends object>doSomething(): T{
//complex stuff, a lot of lambdas
}
How from factory method I can return doSomething with allready assigned type?
javascript angular reactjs typescript
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
add a comment |
I have some factory method which is making some computations and manipulations. Also I have a generic method doSomething. I don't wanna to specify type for doSomething each time. I would like to do it once for factory method and then get it each time with already assigned type
function factory<T>(t: T){
// some computations
return {method: doSomething<T>} <- this is what I wanna do
}
// Generic
function<T extends object>doSomething(): T{
//complex stuff, a lot of lambdas
}
How from factory method I can return doSomething with allready assigned type?
javascript angular reactjs typescript
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
add a comment |
I have some factory method which is making some computations and manipulations. Also I have a generic method doSomething. I don't wanna to specify type for doSomething each time. I would like to do it once for factory method and then get it each time with already assigned type
function factory<T>(t: T){
// some computations
return {method: doSomething<T>} <- this is what I wanna do
}
// Generic
function<T extends object>doSomething(): T{
//complex stuff, a lot of lambdas
}
How from factory method I can return doSomething with allready assigned type?
javascript angular reactjs typescript
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
I have some factory method which is making some computations and manipulations. Also I have a generic method doSomething. I don't wanna to specify type for doSomething each time. I would like to do it once for factory method and then get it each time with already assigned type
function factory<T>(t: T){
// some computations
return {method: doSomething<T>} <- this is what I wanna do
}
// Generic
function<T extends object>doSomething(): T{
//complex stuff, a lot of lambdas
}
How from factory method I can return doSomething with allready assigned type?
javascript angular reactjs typescript
javascript angular reactjs typescript
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
asked Nov 22 '18 at 22:11
Oskar Woźniak
114113
114113
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can't specify the type parameter of a generic function without calling it. So doSomething<T> is not acceptable; only doSomething<T>() is allowed. Luckily, you can just return a concrete function that calls the generic function with the proper type parameter specified. Like this:
function factory<T extends object>(t: T) {
// some computations
return { method: ()=>doSomething<T>() }
}
// Generic, note generic parameter comes after the function name
declare function doSomething<T extends object>(): T;
Let's see if it works:
const ret = factory({a: "hey"}).method();
// const ret: { a: string }
Looks good to me. Hope that helps; good luck!
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't specify the type parameter of a generic function without calling it. So doSomething<T> is not acceptable; only doSomething<T>() is allowed. Luckily, you can just return a concrete function that calls the generic function with the proper type parameter specified. Like this:
function factory<T extends object>(t: T) {
// some computations
return { method: ()=>doSomething<T>() }
}
// Generic, note generic parameter comes after the function name
declare function doSomething<T extends object>(): T;
Let's see if it works:
const ret = factory({a: "hey"}).method();
// const ret: { a: string }
Looks good to me. Hope that helps; good luck!
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
add a comment |
You can't specify the type parameter of a generic function without calling it. So doSomething<T> is not acceptable; only doSomething<T>() is allowed. Luckily, you can just return a concrete function that calls the generic function with the proper type parameter specified. Like this:
function factory<T extends object>(t: T) {
// some computations
return { method: ()=>doSomething<T>() }
}
// Generic, note generic parameter comes after the function name
declare function doSomething<T extends object>(): T;
Let's see if it works:
const ret = factory({a: "hey"}).method();
// const ret: { a: string }
Looks good to me. Hope that helps; good luck!
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
add a comment |
You can't specify the type parameter of a generic function without calling it. So doSomething<T> is not acceptable; only doSomething<T>() is allowed. Luckily, you can just return a concrete function that calls the generic function with the proper type parameter specified. Like this:
function factory<T extends object>(t: T) {
// some computations
return { method: ()=>doSomething<T>() }
}
// Generic, note generic parameter comes after the function name
declare function doSomething<T extends object>(): T;
Let's see if it works:
const ret = factory({a: "hey"}).method();
// const ret: { a: string }
Looks good to me. Hope that helps; good luck!
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
You can't specify the type parameter of a generic function without calling it. So doSomething<T> is not acceptable; only doSomething<T>() is allowed. Luckily, you can just return a concrete function that calls the generic function with the proper type parameter specified. Like this:
function factory<T extends object>(t: T) {
// some computations
return { method: ()=>doSomething<T>() }
}
// Generic, note generic parameter comes after the function name
declare function doSomething<T extends object>(): T;
Let's see if it works:
const ret = factory({a: "hey"}).method();
// const ret: { a: string }
Looks good to me. Hope that helps; good luck!
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
answered Nov 23 '18 at 1:50
jcalz
22.3k21738
22.3k21738
add a comment |
add a comment |
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