Variable pointers












-1














I have a requirement as below:



myConfigFile.py



NAME1='Rahul Singh'
NAME2='R Singh Bajaj'


myMainClass.py



from myConfigFile.py import *

def printName(NAME):
print('Name is : '+NAME)

for i in range(1,3):
printName(Name+i) **##the value passed is 'NAME1'**


Current Output:



Name is :Name1
Name is :Name2


Expected Output:



Name is :Rahul Singh 
Name is :R Singh Bajaj


How can I get the desired output?










share|improve this question
























  • It's taking NAME1 as string rather than to take as variable.
    – Toaster
    Nov 23 '18 at 7:07










  • While the answer of @madforstrength answers your question directly, yet I believe that likely a slightly different design of your programme would make the task for you much easier: use dicts or list and you might stop needing to compose the variable names - which is quite fragile. E.g. you could create a dict like mydict = {'Rahul Sing': {'related property': 1, 'other_property': 2}, 'Singh Bajaj': {'related property': 2, 'anything else': "blödsinn"}}. You then can reference the properties related to the names very easily with the name: mydict.get('Rahul Singh').get('related property')
    – planetmaker
    Nov 23 '18 at 7:17










  • And you would iterate over the single names just by iterating over the dict: for (name,values) in mydict.items(): print("Name: {}".format(name))
    – planetmaker
    Nov 23 '18 at 7:18
















-1














I have a requirement as below:



myConfigFile.py



NAME1='Rahul Singh'
NAME2='R Singh Bajaj'


myMainClass.py



from myConfigFile.py import *

def printName(NAME):
print('Name is : '+NAME)

for i in range(1,3):
printName(Name+i) **##the value passed is 'NAME1'**


Current Output:



Name is :Name1
Name is :Name2


Expected Output:



Name is :Rahul Singh 
Name is :R Singh Bajaj


How can I get the desired output?










share|improve this question
























  • It's taking NAME1 as string rather than to take as variable.
    – Toaster
    Nov 23 '18 at 7:07










  • While the answer of @madforstrength answers your question directly, yet I believe that likely a slightly different design of your programme would make the task for you much easier: use dicts or list and you might stop needing to compose the variable names - which is quite fragile. E.g. you could create a dict like mydict = {'Rahul Sing': {'related property': 1, 'other_property': 2}, 'Singh Bajaj': {'related property': 2, 'anything else': "blödsinn"}}. You then can reference the properties related to the names very easily with the name: mydict.get('Rahul Singh').get('related property')
    – planetmaker
    Nov 23 '18 at 7:17










  • And you would iterate over the single names just by iterating over the dict: for (name,values) in mydict.items(): print("Name: {}".format(name))
    – planetmaker
    Nov 23 '18 at 7:18














-1












-1








-1







I have a requirement as below:



myConfigFile.py



NAME1='Rahul Singh'
NAME2='R Singh Bajaj'


myMainClass.py



from myConfigFile.py import *

def printName(NAME):
print('Name is : '+NAME)

for i in range(1,3):
printName(Name+i) **##the value passed is 'NAME1'**


Current Output:



Name is :Name1
Name is :Name2


Expected Output:



Name is :Rahul Singh 
Name is :R Singh Bajaj


How can I get the desired output?










share|improve this question















I have a requirement as below:



myConfigFile.py



NAME1='Rahul Singh'
NAME2='R Singh Bajaj'


myMainClass.py



from myConfigFile.py import *

def printName(NAME):
print('Name is : '+NAME)

for i in range(1,3):
printName(Name+i) **##the value passed is 'NAME1'**


Current Output:



Name is :Name1
Name is :Name2


Expected Output:



Name is :Rahul Singh 
Name is :R Singh Bajaj


How can I get the desired output?







python variables






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 7:04









petezurich

3,50581734




3,50581734










asked Nov 23 '18 at 6:51









Rahul Singh BajajRahul Singh Bajaj

112




112












  • It's taking NAME1 as string rather than to take as variable.
    – Toaster
    Nov 23 '18 at 7:07










  • While the answer of @madforstrength answers your question directly, yet I believe that likely a slightly different design of your programme would make the task for you much easier: use dicts or list and you might stop needing to compose the variable names - which is quite fragile. E.g. you could create a dict like mydict = {'Rahul Sing': {'related property': 1, 'other_property': 2}, 'Singh Bajaj': {'related property': 2, 'anything else': "blödsinn"}}. You then can reference the properties related to the names very easily with the name: mydict.get('Rahul Singh').get('related property')
    – planetmaker
    Nov 23 '18 at 7:17










  • And you would iterate over the single names just by iterating over the dict: for (name,values) in mydict.items(): print("Name: {}".format(name))
    – planetmaker
    Nov 23 '18 at 7:18


















  • It's taking NAME1 as string rather than to take as variable.
    – Toaster
    Nov 23 '18 at 7:07










  • While the answer of @madforstrength answers your question directly, yet I believe that likely a slightly different design of your programme would make the task for you much easier: use dicts or list and you might stop needing to compose the variable names - which is quite fragile. E.g. you could create a dict like mydict = {'Rahul Sing': {'related property': 1, 'other_property': 2}, 'Singh Bajaj': {'related property': 2, 'anything else': "blödsinn"}}. You then can reference the properties related to the names very easily with the name: mydict.get('Rahul Singh').get('related property')
    – planetmaker
    Nov 23 '18 at 7:17










  • And you would iterate over the single names just by iterating over the dict: for (name,values) in mydict.items(): print("Name: {}".format(name))
    – planetmaker
    Nov 23 '18 at 7:18
















It's taking NAME1 as string rather than to take as variable.
– Toaster
Nov 23 '18 at 7:07




It's taking NAME1 as string rather than to take as variable.
– Toaster
Nov 23 '18 at 7:07












While the answer of @madforstrength answers your question directly, yet I believe that likely a slightly different design of your programme would make the task for you much easier: use dicts or list and you might stop needing to compose the variable names - which is quite fragile. E.g. you could create a dict like mydict = {'Rahul Sing': {'related property': 1, 'other_property': 2}, 'Singh Bajaj': {'related property': 2, 'anything else': "blödsinn"}}. You then can reference the properties related to the names very easily with the name: mydict.get('Rahul Singh').get('related property')
– planetmaker
Nov 23 '18 at 7:17




While the answer of @madforstrength answers your question directly, yet I believe that likely a slightly different design of your programme would make the task for you much easier: use dicts or list and you might stop needing to compose the variable names - which is quite fragile. E.g. you could create a dict like mydict = {'Rahul Sing': {'related property': 1, 'other_property': 2}, 'Singh Bajaj': {'related property': 2, 'anything else': "blödsinn"}}. You then can reference the properties related to the names very easily with the name: mydict.get('Rahul Singh').get('related property')
– planetmaker
Nov 23 '18 at 7:17












And you would iterate over the single names just by iterating over the dict: for (name,values) in mydict.items(): print("Name: {}".format(name))
– planetmaker
Nov 23 '18 at 7:18




And you would iterate over the single names just by iterating over the dict: for (name,values) in mydict.items(): print("Name: {}".format(name))
– planetmaker
Nov 23 '18 at 7:18












2 Answers
2






active

oldest

votes


















0














You need to replace



printName(Name+i)


with



printName(eval("NAME" + str(i)))





share|improve this answer































    0














    Since, "NAME" is a string so you need to typecast int i into str(i).
    Please find the full code below
    **



    myMainClass.py



    #!/usr/bin/python

    from myConfigFile import *

    def printName(NAME):
    print('Name is : '+NAME)
    for i in range(1,3):
    printName(eval("NAME"+str(i))) ##the value passed is 'NAME1'





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      You need to replace



      printName(Name+i)


      with



      printName(eval("NAME" + str(i)))





      share|improve this answer




























        0














        You need to replace



        printName(Name+i)


        with



        printName(eval("NAME" + str(i)))





        share|improve this answer


























          0












          0








          0






          You need to replace



          printName(Name+i)


          with



          printName(eval("NAME" + str(i)))





          share|improve this answer














          You need to replace



          printName(Name+i)


          with



          printName(eval("NAME" + str(i)))






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 23 '18 at 7:04









          petezurich

          3,50581734




          3,50581734










          answered Nov 23 '18 at 7:01









          Muhammad BilalMuhammad Bilal

          1,71111021




          1,71111021

























              0














              Since, "NAME" is a string so you need to typecast int i into str(i).
              Please find the full code below
              **



              myMainClass.py



              #!/usr/bin/python

              from myConfigFile import *

              def printName(NAME):
              print('Name is : '+NAME)
              for i in range(1,3):
              printName(eval("NAME"+str(i))) ##the value passed is 'NAME1'





              share|improve this answer




























                0














                Since, "NAME" is a string so you need to typecast int i into str(i).
                Please find the full code below
                **



                myMainClass.py



                #!/usr/bin/python

                from myConfigFile import *

                def printName(NAME):
                print('Name is : '+NAME)
                for i in range(1,3):
                printName(eval("NAME"+str(i))) ##the value passed is 'NAME1'





                share|improve this answer


























                  0












                  0








                  0






                  Since, "NAME" is a string so you need to typecast int i into str(i).
                  Please find the full code below
                  **



                  myMainClass.py



                  #!/usr/bin/python

                  from myConfigFile import *

                  def printName(NAME):
                  print('Name is : '+NAME)
                  for i in range(1,3):
                  printName(eval("NAME"+str(i))) ##the value passed is 'NAME1'





                  share|improve this answer














                  Since, "NAME" is a string so you need to typecast int i into str(i).
                  Please find the full code below
                  **



                  myMainClass.py



                  #!/usr/bin/python

                  from myConfigFile import *

                  def printName(NAME):
                  print('Name is : '+NAME)
                  for i in range(1,3):
                  printName(eval("NAME"+str(i))) ##the value passed is 'NAME1'






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 23 '18 at 7:28

























                  answered Nov 23 '18 at 7:05









                  Rishi BansalRishi Bansal

                  588217




                  588217






























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