convert SELECT query from mySql to Laravel query builder












1















what would be Laravel Query Builder code of this mysql query;



SELECT * 
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id









share|improve this question























  • I recommend you to use Eloquen Models. Check out the docs

    – Pepe
    Nov 24 '18 at 2:22
















1















what would be Laravel Query Builder code of this mysql query;



SELECT * 
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id









share|improve this question























  • I recommend you to use Eloquen Models. Check out the docs

    – Pepe
    Nov 24 '18 at 2:22














1












1








1








what would be Laravel Query Builder code of this mysql query;



SELECT * 
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id









share|improve this question














what would be Laravel Query Builder code of this mysql query;



SELECT * 
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id






mysql laravel






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 23 '18 at 23:52









iscpreeeiscpreee

133




133













  • I recommend you to use Eloquen Models. Check out the docs

    – Pepe
    Nov 24 '18 at 2:22



















  • I recommend you to use Eloquen Models. Check out the docs

    – Pepe
    Nov 24 '18 at 2:22

















I recommend you to use Eloquen Models. Check out the docs

– Pepe
Nov 24 '18 at 2:22





I recommend you to use Eloquen Models. Check out the docs

– Pepe
Nov 24 '18 at 2:22












2 Answers
2






active

oldest

votes


















1














$query = DB::select("SELECT * 
FROM Student
WHERE family_id IN (SELECT family_id
FROM students
GROUP BY family_id
HAVING COUNT(1)>1)
ORDER BY family_id")


Based on Laravel Documentation






share|improve this answer































    0














    Use function in whereIn clause:



    Student::whereIn('family_id', function($query) {
    $query->select('family_id')
    ->from(with(new Students)->getTable())
    ->groupBy('family_id')
    ->havingRaw('COUNT(1) > 1')
    })->get();





    share|improve this answer























      Your Answer






      StackExchange.ifUsing("editor", function () {
      StackExchange.using("externalEditor", function () {
      StackExchange.using("snippets", function () {
      StackExchange.snippets.init();
      });
      });
      }, "code-snippets");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "1"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53453993%2fconvert-select-query-from-mysql-to-laravel-query-builder%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      $query = DB::select("SELECT * 
      FROM Student
      WHERE family_id IN (SELECT family_id
      FROM students
      GROUP BY family_id
      HAVING COUNT(1)>1)
      ORDER BY family_id")


      Based on Laravel Documentation






      share|improve this answer




























        1














        $query = DB::select("SELECT * 
        FROM Student
        WHERE family_id IN (SELECT family_id
        FROM students
        GROUP BY family_id
        HAVING COUNT(1)>1)
        ORDER BY family_id")


        Based on Laravel Documentation






        share|improve this answer


























          1












          1








          1







          $query = DB::select("SELECT * 
          FROM Student
          WHERE family_id IN (SELECT family_id
          FROM students
          GROUP BY family_id
          HAVING COUNT(1)>1)
          ORDER BY family_id")


          Based on Laravel Documentation






          share|improve this answer













          $query = DB::select("SELECT * 
          FROM Student
          WHERE family_id IN (SELECT family_id
          FROM students
          GROUP BY family_id
          HAVING COUNT(1)>1)
          ORDER BY family_id")


          Based on Laravel Documentation







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 24 '18 at 1:41









          KelvinKelvin

          364224




          364224

























              0














              Use function in whereIn clause:



              Student::whereIn('family_id', function($query) {
              $query->select('family_id')
              ->from(with(new Students)->getTable())
              ->groupBy('family_id')
              ->havingRaw('COUNT(1) > 1')
              })->get();





              share|improve this answer




























                0














                Use function in whereIn clause:



                Student::whereIn('family_id', function($query) {
                $query->select('family_id')
                ->from(with(new Students)->getTable())
                ->groupBy('family_id')
                ->havingRaw('COUNT(1) > 1')
                })->get();





                share|improve this answer


























                  0












                  0








                  0







                  Use function in whereIn clause:



                  Student::whereIn('family_id', function($query) {
                  $query->select('family_id')
                  ->from(with(new Students)->getTable())
                  ->groupBy('family_id')
                  ->havingRaw('COUNT(1) > 1')
                  })->get();





                  share|improve this answer













                  Use function in whereIn clause:



                  Student::whereIn('family_id', function($query) {
                  $query->select('family_id')
                  ->from(with(new Students)->getTable())
                  ->groupBy('family_id')
                  ->havingRaw('COUNT(1) > 1')
                  })->get();






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 24 '18 at 4:10









                  Dhruv RavalDhruv Raval

                  1,053312




                  1,053312






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Stack Overflow!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53453993%2fconvert-select-query-from-mysql-to-laravel-query-builder%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Berounka

                      Fiat S.p.A.

                      Type 'String' is not a subtype of type 'int' of 'index'