How to create outputs in columns using Printf with varied output lengths - Java












2















I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf



I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.



import java.util.Scanner;
public class Convert {

public static void main(String args) {
Scanner input = new Scanner(System.in);

System.out.println("Please enter your decimal number");

int decimal = input.nextInt();
System.out.printf("Decimal: %dn", decimal);

String binary=decimalToBinary(decimal);
System.out.printf("Binary: %sn", binary);

String octa=decimalToOctal(decimal);
System.out.printf("Octal: %sn", octa);


String hexa=decimalToOctal(decimal);
System.out.printf("Hexa:%sn", hexa);


}

public static String decimalToBinary(int decimal) {

int remainder;
String answer="";

while (decimal>0) {
remainder=decimal%2;
decimal=decimal/2;
answer=remainder+answer;

}
return answer;


}



public static String decimalToOctal(int decimal) {

int remainder;
String answer="";

while (decimal>0) {
remainder=decimal%8;
decimal=decimal/8;
answer=remainder+answer;
}
return answer;
}

public static String decimalToHexadecimal(int decimal) {

int remainder;
String answer="";


while (decimal>0) {
remainder=decimal%16;
decimal=decimal/16;

if (remainder==10)
answer= "A" + answer;
else if (remainder==11)
answer= "B" + answer;
else if (remainder==12)
answer= "C" + answer;
else if (remainder==13)
answer= "D" + answer;
else if (remainder==14)
answer= "E" + answer;
else if (remainder==15)
answer= "F" + answer;
else answer=remainder+answer;
}
return answer;

}


}










share|improve this question



























    2















    I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf



    I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.



    import java.util.Scanner;
    public class Convert {

    public static void main(String args) {
    Scanner input = new Scanner(System.in);

    System.out.println("Please enter your decimal number");

    int decimal = input.nextInt();
    System.out.printf("Decimal: %dn", decimal);

    String binary=decimalToBinary(decimal);
    System.out.printf("Binary: %sn", binary);

    String octa=decimalToOctal(decimal);
    System.out.printf("Octal: %sn", octa);


    String hexa=decimalToOctal(decimal);
    System.out.printf("Hexa:%sn", hexa);


    }

    public static String decimalToBinary(int decimal) {

    int remainder;
    String answer="";

    while (decimal>0) {
    remainder=decimal%2;
    decimal=decimal/2;
    answer=remainder+answer;

    }
    return answer;


    }



    public static String decimalToOctal(int decimal) {

    int remainder;
    String answer="";

    while (decimal>0) {
    remainder=decimal%8;
    decimal=decimal/8;
    answer=remainder+answer;
    }
    return answer;
    }

    public static String decimalToHexadecimal(int decimal) {

    int remainder;
    String answer="";


    while (decimal>0) {
    remainder=decimal%16;
    decimal=decimal/16;

    if (remainder==10)
    answer= "A" + answer;
    else if (remainder==11)
    answer= "B" + answer;
    else if (remainder==12)
    answer= "C" + answer;
    else if (remainder==13)
    answer= "D" + answer;
    else if (remainder==14)
    answer= "E" + answer;
    else if (remainder==15)
    answer= "F" + answer;
    else answer=remainder+answer;
    }
    return answer;

    }


    }










    share|improve this question

























      2












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      2








      I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf



      I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.



      import java.util.Scanner;
      public class Convert {

      public static void main(String args) {
      Scanner input = new Scanner(System.in);

      System.out.println("Please enter your decimal number");

      int decimal = input.nextInt();
      System.out.printf("Decimal: %dn", decimal);

      String binary=decimalToBinary(decimal);
      System.out.printf("Binary: %sn", binary);

      String octa=decimalToOctal(decimal);
      System.out.printf("Octal: %sn", octa);


      String hexa=decimalToOctal(decimal);
      System.out.printf("Hexa:%sn", hexa);


      }

      public static String decimalToBinary(int decimal) {

      int remainder;
      String answer="";

      while (decimal>0) {
      remainder=decimal%2;
      decimal=decimal/2;
      answer=remainder+answer;

      }
      return answer;


      }



      public static String decimalToOctal(int decimal) {

      int remainder;
      String answer="";

      while (decimal>0) {
      remainder=decimal%8;
      decimal=decimal/8;
      answer=remainder+answer;
      }
      return answer;
      }

      public static String decimalToHexadecimal(int decimal) {

      int remainder;
      String answer="";


      while (decimal>0) {
      remainder=decimal%16;
      decimal=decimal/16;

      if (remainder==10)
      answer= "A" + answer;
      else if (remainder==11)
      answer= "B" + answer;
      else if (remainder==12)
      answer= "C" + answer;
      else if (remainder==13)
      answer= "D" + answer;
      else if (remainder==14)
      answer= "E" + answer;
      else if (remainder==15)
      answer= "F" + answer;
      else answer=remainder+answer;
      }
      return answer;

      }


      }










      share|improve this question














      I was asked to create a code with three methods. This program should be have a method for each of the conversions decimalToBinary, decimalToOctal and decimalToHexadecimal and then display the results in a table with four columns: Decimal, Binary, Octal and Hexadecimal using printf



      I was able to create the code to do the conversions however I am having a very hard time figuring out how to print the code into a column. I did research and I know how to use printf however I am confused since the lengths of the outputs will be different every time. How can I get them to display equally? Here is my code.



      import java.util.Scanner;
      public class Convert {

      public static void main(String args) {
      Scanner input = new Scanner(System.in);

      System.out.println("Please enter your decimal number");

      int decimal = input.nextInt();
      System.out.printf("Decimal: %dn", decimal);

      String binary=decimalToBinary(decimal);
      System.out.printf("Binary: %sn", binary);

      String octa=decimalToOctal(decimal);
      System.out.printf("Octal: %sn", octa);


      String hexa=decimalToOctal(decimal);
      System.out.printf("Hexa:%sn", hexa);


      }

      public static String decimalToBinary(int decimal) {

      int remainder;
      String answer="";

      while (decimal>0) {
      remainder=decimal%2;
      decimal=decimal/2;
      answer=remainder+answer;

      }
      return answer;


      }



      public static String decimalToOctal(int decimal) {

      int remainder;
      String answer="";

      while (decimal>0) {
      remainder=decimal%8;
      decimal=decimal/8;
      answer=remainder+answer;
      }
      return answer;
      }

      public static String decimalToHexadecimal(int decimal) {

      int remainder;
      String answer="";


      while (decimal>0) {
      remainder=decimal%16;
      decimal=decimal/16;

      if (remainder==10)
      answer= "A" + answer;
      else if (remainder==11)
      answer= "B" + answer;
      else if (remainder==12)
      answer= "C" + answer;
      else if (remainder==13)
      answer= "D" + answer;
      else if (remainder==14)
      answer= "E" + answer;
      else if (remainder==15)
      answer= "F" + answer;
      else answer=remainder+answer;
      }
      return answer;

      }


      }







      java string eclipse printf






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      asked Nov 24 '18 at 0:09









      Rebecca Allyson MorrisRebecca Allyson Morris

      132




      132
























          1 Answer
          1






          active

          oldest

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          0














          Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,



          printf("%20s", s);


          will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.






          share|improve this answer
























          • I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:20











          • For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:26











          Your Answer






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          1 Answer
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          active

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,



          printf("%20s", s);


          will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.






          share|improve this answer
























          • I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:20











          • For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:26
















          0














          Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,



          printf("%20s", s);


          will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.






          share|improve this answer
























          • I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:20











          • For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:26














          0












          0








          0







          Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,



          printf("%20s", s);


          will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.






          share|improve this answer













          Take a look at the printf() documentation, in particular the format string syntax. You are after the width specifiers. For example,



          printf("%20s", s);


          will ensure your output will have a width of 20 characters. You can play around with the variations to achieve what you want.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 24 '18 at 0:18









          davedave

          8,48752850




          8,48752850













          • I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:20











          • For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:26



















          • I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:20











          • For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

            – Rebecca Allyson Morris
            Nov 24 '18 at 0:26

















          I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

          – Rebecca Allyson Morris
          Nov 24 '18 at 0:20





          I had tried different lengths, I just left the lengths out when I pasted my code because I realized the problem is even if I put 20 characters, or 15, or any it goes out of line with different inputs as some inputs will create longer outputs.

          – Rebecca Allyson Morris
          Nov 24 '18 at 0:20













          For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

          – Rebecca Allyson Morris
          Nov 24 '18 at 0:26





          For example, this code works if the user input is "30" System.out.println("Please enter your decimal number"); int decimal = input.nextInt(); System.out.printf("Decimal: %20dn", decimal); String binary=decimalToBinary(decimal); System.out.printf("Binary: %21sn", binary); String octa=decimalToOctal(decimal); System.out.printf("Octal: %22sn", octa); String hexa=decimalToOctal(decimal); System.out.printf("Hexa:%24sn", hexa); Any other input its not inline

          – Rebecca Allyson Morris
          Nov 24 '18 at 0:26


















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