I don't know what substitution should use in this integral
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I have a problem with solving this integral.
$int e^{(t-1)t}tdt$
Whatever I tried wont work. Please advice.
calculus
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add a comment |
$begingroup$
I have a problem with solving this integral.
$int e^{(t-1)t}tdt$
Whatever I tried wont work. Please advice.
calculus
$endgroup$
$begingroup$
That integral does not have a nice closed form solution. Wolfram Alpha offers one involving the error function: wolframalpha.com/input/?i=INTEGRATE+e%5E((t%E2%88%921)t)+t+dt
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– Ethan Bolker
Dec 9 '18 at 18:06
add a comment |
$begingroup$
I have a problem with solving this integral.
$int e^{(t-1)t}tdt$
Whatever I tried wont work. Please advice.
calculus
$endgroup$
I have a problem with solving this integral.
$int e^{(t-1)t}tdt$
Whatever I tried wont work. Please advice.
calculus
calculus
asked Dec 9 '18 at 18:02
Novak DjokovicNovak Djokovic
44328
44328
$begingroup$
That integral does not have a nice closed form solution. Wolfram Alpha offers one involving the error function: wolframalpha.com/input/?i=INTEGRATE+e%5E((t%E2%88%921)t)+t+dt
$endgroup$
– Ethan Bolker
Dec 9 '18 at 18:06
add a comment |
$begingroup$
That integral does not have a nice closed form solution. Wolfram Alpha offers one involving the error function: wolframalpha.com/input/?i=INTEGRATE+e%5E((t%E2%88%921)t)+t+dt
$endgroup$
– Ethan Bolker
Dec 9 '18 at 18:06
$begingroup$
That integral does not have a nice closed form solution. Wolfram Alpha offers one involving the error function: wolframalpha.com/input/?i=INTEGRATE+e%5E((t%E2%88%921)t)+t+dt
$endgroup$
– Ethan Bolker
Dec 9 '18 at 18:06
$begingroup$
That integral does not have a nice closed form solution. Wolfram Alpha offers one involving the error function: wolframalpha.com/input/?i=INTEGRATE+e%5E((t%E2%88%921)t)+t+dt
$endgroup$
– Ethan Bolker
Dec 9 '18 at 18:06
add a comment |
1 Answer
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Hint: define $$u=t-{1over 2}$$ and split the integral by two. Note that this integral has no closed form and you have to use the definition of Q-function.
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1 Answer
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$begingroup$
Hint: define $$u=t-{1over 2}$$ and split the integral by two. Note that this integral has no closed form and you have to use the definition of Q-function.
$endgroup$
add a comment |
$begingroup$
Hint: define $$u=t-{1over 2}$$ and split the integral by two. Note that this integral has no closed form and you have to use the definition of Q-function.
$endgroup$
add a comment |
$begingroup$
Hint: define $$u=t-{1over 2}$$ and split the integral by two. Note that this integral has no closed form and you have to use the definition of Q-function.
$endgroup$
Hint: define $$u=t-{1over 2}$$ and split the integral by two. Note that this integral has no closed form and you have to use the definition of Q-function.
answered Dec 9 '18 at 18:06
Mostafa AyazMostafa Ayaz
15.3k3939
15.3k3939
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$begingroup$
That integral does not have a nice closed form solution. Wolfram Alpha offers one involving the error function: wolframalpha.com/input/?i=INTEGRATE+e%5E((t%E2%88%921)t)+t+dt
$endgroup$
– Ethan Bolker
Dec 9 '18 at 18:06