ggplot2 facet labeller with bquote












1














Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3



library(ggplot2)

var.lab1 = as_labeller(c(
"setosa" = "se",
"versicolor" = "ve",
"virginica" = "vi"
))

var.lab2 = as_labeller(c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
))


This works as expected



ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab1) +
geom_point()


This doesn't work (the labeller has no effect)



ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = var.lab2) +
geom_point()


And this works



var.lab3 = c(
"setosa" = bquote("Spp"[set]),
"versicolor" = bquote("Spp"[ver]),
"virginica" = bquote("Spp"[vir])
)

vlabeller <- function (variable, value) {
return(var.lab3[value])
}

ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
facet_wrap(~ Species, labeller = vlabeller) +
geom_point()


But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."










share|improve this question





























    1














    Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3



    library(ggplot2)

    var.lab1 = as_labeller(c(
    "setosa" = "se",
    "versicolor" = "ve",
    "virginica" = "vi"
    ))

    var.lab2 = as_labeller(c(
    "setosa" = bquote("Spp"[set]),
    "versicolor" = bquote("Spp"[ver]),
    "virginica" = bquote("Spp"[vir])
    ))


    This works as expected



    ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
    facet_wrap(~ Species, labeller = var.lab1) +
    geom_point()


    This doesn't work (the labeller has no effect)



    ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
    facet_wrap(~ Species, labeller = var.lab2) +
    geom_point()


    And this works



    var.lab3 = c(
    "setosa" = bquote("Spp"[set]),
    "versicolor" = bquote("Spp"[ver]),
    "virginica" = bquote("Spp"[vir])
    )

    vlabeller <- function (variable, value) {
    return(var.lab3[value])
    }

    ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
    facet_wrap(~ Species, labeller = vlabeller) +
    geom_point()


    But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."










    share|improve this question



























      1












      1








      1







      Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3



      library(ggplot2)

      var.lab1 = as_labeller(c(
      "setosa" = "se",
      "versicolor" = "ve",
      "virginica" = "vi"
      ))

      var.lab2 = as_labeller(c(
      "setosa" = bquote("Spp"[set]),
      "versicolor" = bquote("Spp"[ver]),
      "virginica" = bquote("Spp"[vir])
      ))


      This works as expected



      ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
      facet_wrap(~ Species, labeller = var.lab1) +
      geom_point()


      This doesn't work (the labeller has no effect)



      ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
      facet_wrap(~ Species, labeller = var.lab2) +
      geom_point()


      And this works



      var.lab3 = c(
      "setosa" = bquote("Spp"[set]),
      "versicolor" = bquote("Spp"[ver]),
      "virginica" = bquote("Spp"[vir])
      )

      vlabeller <- function (variable, value) {
      return(var.lab3[value])
      }

      ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
      facet_wrap(~ Species, labeller = vlabeller) +
      geom_point()


      But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."










      share|improve this question















      Yet another labeller question... I am struggling using math expressions in labellers with ggplot2 > 3



      library(ggplot2)

      var.lab1 = as_labeller(c(
      "setosa" = "se",
      "versicolor" = "ve",
      "virginica" = "vi"
      ))

      var.lab2 = as_labeller(c(
      "setosa" = bquote("Spp"[set]),
      "versicolor" = bquote("Spp"[ver]),
      "virginica" = bquote("Spp"[vir])
      ))


      This works as expected



      ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
      facet_wrap(~ Species, labeller = var.lab1) +
      geom_point()


      This doesn't work (the labeller has no effect)



      ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
      facet_wrap(~ Species, labeller = var.lab2) +
      geom_point()


      And this works



      var.lab3 = c(
      "setosa" = bquote("Spp"[set]),
      "versicolor" = bquote("Spp"[ver]),
      "virginica" = bquote("Spp"[vir])
      )

      vlabeller <- function (variable, value) {
      return(var.lab3[value])
      }

      ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
      facet_wrap(~ Species, labeller = vlabeller) +
      geom_point()


      But ggplot2 is unhappy "Warning message: The labeller API has been updated. Labellers taking variable and value arguments are now deprecated. See labellers documentation."







      r ggplot2






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 22 at 18:00

























      asked Nov 22 at 17:14









      user2165907

      6493719




      6493719
























          1 Answer
          1






          active

          oldest

          votes


















          2














          You could just use label_bquote and substr to get what you want. No need for a custom labeller.





          library(ggplot2)

          ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
          facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
          geom_point()




          Created on 2018-11-22 by the reprex package (v0.2.1)






          share|improve this answer





















          • Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
            – user2165907
            Nov 22 at 17:54













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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          You could just use label_bquote and substr to get what you want. No need for a custom labeller.





          library(ggplot2)

          ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
          facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
          geom_point()




          Created on 2018-11-22 by the reprex package (v0.2.1)






          share|improve this answer





















          • Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
            – user2165907
            Nov 22 at 17:54


















          2














          You could just use label_bquote and substr to get what you want. No need for a custom labeller.





          library(ggplot2)

          ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
          facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
          geom_point()




          Created on 2018-11-22 by the reprex package (v0.2.1)






          share|improve this answer





















          • Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
            – user2165907
            Nov 22 at 17:54
















          2












          2








          2






          You could just use label_bquote and substr to get what you want. No need for a custom labeller.





          library(ggplot2)

          ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
          facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
          geom_point()




          Created on 2018-11-22 by the reprex package (v0.2.1)






          share|improve this answer












          You could just use label_bquote and substr to get what you want. No need for a custom labeller.





          library(ggplot2)

          ggplot(iris, aes(x = Sepal.Length, y = Petal.Length)) +
          facet_wrap(~ Species, labeller = label_bquote(cols = "Spp"[.(substr(Species, 1, 3))])) +
          geom_point()




          Created on 2018-11-22 by the reprex package (v0.2.1)







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 17:36









          Jake Kaupp

          5,28221428




          5,28221428












          • Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
            – user2165907
            Nov 22 at 17:54




















          • Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
            – user2165907
            Nov 22 at 17:54


















          Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
          – user2165907
          Nov 22 at 17:54






          Yes, your answer is correct for my particular (and simple) example, that's why I have to validate it. Unfortunately, I am working on a bigger (many more facets) "true life" dataset and each facet has a different kind of labeller, some with bquote and others without... So, if there are other propositions I'll be happy.
          – user2165907
          Nov 22 at 17:54




















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