Line Integral of Clockwise Circle











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Considering the circle $x^2+y^2=9$ going in the clockwise direction, I am evaluating the line integral $int_{C}$ $Fdr$ from $(3,0)$ to $(0,3$). I have parametrization $x=3cost$ and $y=3sint$ and I had a question on the limits of integration, as it is 3/4 of a circle and traveling clockwise. I don't think it is from 0 to $pi$$/2$ considering the orientation. Any help is appreciated.










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    Considering the circle $x^2+y^2=9$ going in the clockwise direction, I am evaluating the line integral $int_{C}$ $Fdr$ from $(3,0)$ to $(0,3$). I have parametrization $x=3cost$ and $y=3sint$ and I had a question on the limits of integration, as it is 3/4 of a circle and traveling clockwise. I don't think it is from 0 to $pi$$/2$ considering the orientation. Any help is appreciated.










    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Considering the circle $x^2+y^2=9$ going in the clockwise direction, I am evaluating the line integral $int_{C}$ $Fdr$ from $(3,0)$ to $(0,3$). I have parametrization $x=3cost$ and $y=3sint$ and I had a question on the limits of integration, as it is 3/4 of a circle and traveling clockwise. I don't think it is from 0 to $pi$$/2$ considering the orientation. Any help is appreciated.










      share|cite|improve this question













      Considering the circle $x^2+y^2=9$ going in the clockwise direction, I am evaluating the line integral $int_{C}$ $Fdr$ from $(3,0)$ to $(0,3$). I have parametrization $x=3cost$ and $y=3sint$ and I had a question on the limits of integration, as it is 3/4 of a circle and traveling clockwise. I don't think it is from 0 to $pi$$/2$ considering the orientation. Any help is appreciated.







      calculus integration line-integrals






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      asked Nov 23 at 21:44









      darklord0530

      613




      613






















          3 Answers
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          Then your limits are $0$ and $-{3pi over 2}$ as following$$int_CFcdot rdthetahat a_theta=int_{0}^{-{3pi over 2}}3F_theta(r,theta) dtheta$$






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            up vote
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            Alternatively,
            $$ int_C F ,mathrm dr = -int_{-C} F , mathrm dr, $$
            where $-C$ is traversed in the anti-clockwise direction.






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              For clockwise, you want $y = -3sin(t)$






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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes








                up vote
                2
                down vote



                accepted










                Then your limits are $0$ and $-{3pi over 2}$ as following$$int_CFcdot rdthetahat a_theta=int_{0}^{-{3pi over 2}}3F_theta(r,theta) dtheta$$






                share|cite|improve this answer

























                  up vote
                  2
                  down vote



                  accepted










                  Then your limits are $0$ and $-{3pi over 2}$ as following$$int_CFcdot rdthetahat a_theta=int_{0}^{-{3pi over 2}}3F_theta(r,theta) dtheta$$






                  share|cite|improve this answer























                    up vote
                    2
                    down vote



                    accepted







                    up vote
                    2
                    down vote



                    accepted






                    Then your limits are $0$ and $-{3pi over 2}$ as following$$int_CFcdot rdthetahat a_theta=int_{0}^{-{3pi over 2}}3F_theta(r,theta) dtheta$$






                    share|cite|improve this answer












                    Then your limits are $0$ and $-{3pi over 2}$ as following$$int_CFcdot rdthetahat a_theta=int_{0}^{-{3pi over 2}}3F_theta(r,theta) dtheta$$







                    share|cite|improve this answer












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                    share|cite|improve this answer










                    answered Nov 23 at 21:50









                    Mostafa Ayaz

                    13.1k3735




                    13.1k3735






















                        up vote
                        3
                        down vote













                        Alternatively,
                        $$ int_C F ,mathrm dr = -int_{-C} F , mathrm dr, $$
                        where $-C$ is traversed in the anti-clockwise direction.






                        share|cite|improve this answer

























                          up vote
                          3
                          down vote













                          Alternatively,
                          $$ int_C F ,mathrm dr = -int_{-C} F , mathrm dr, $$
                          where $-C$ is traversed in the anti-clockwise direction.






                          share|cite|improve this answer























                            up vote
                            3
                            down vote










                            up vote
                            3
                            down vote









                            Alternatively,
                            $$ int_C F ,mathrm dr = -int_{-C} F , mathrm dr, $$
                            where $-C$ is traversed in the anti-clockwise direction.






                            share|cite|improve this answer












                            Alternatively,
                            $$ int_C F ,mathrm dr = -int_{-C} F , mathrm dr, $$
                            where $-C$ is traversed in the anti-clockwise direction.







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Nov 23 at 21:51









                            MisterRiemann

                            5,1981623




                            5,1981623






















                                up vote
                                2
                                down vote













                                For clockwise, you want $y = -3sin(t)$






                                share|cite|improve this answer

























                                  up vote
                                  2
                                  down vote













                                  For clockwise, you want $y = -3sin(t)$






                                  share|cite|improve this answer























                                    up vote
                                    2
                                    down vote










                                    up vote
                                    2
                                    down vote









                                    For clockwise, you want $y = -3sin(t)$






                                    share|cite|improve this answer












                                    For clockwise, you want $y = -3sin(t)$







                                    share|cite|improve this answer












                                    share|cite|improve this answer



                                    share|cite|improve this answer










                                    answered Nov 23 at 21:47









                                    ncmathsadist

                                    41.9k259101




                                    41.9k259101






























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