Verification of a sequence with exactly two limit points.











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I was not allowed to edit the previous question because people spent their time and energy constructing an answer, therefore I have asked it again, with my initial error in formulating my answers corrected.





Is it true that this example I came up with, namely the sequence $$a_n=cosleft(frac{pi}{3} + frac{pi n}{2}right)$$
Has exactly $4$ limit points/accumulation points? What I tried to do was symmetrically pick an infinite amount of points that lie on the unit circle and all hop between four exact points $pm frac{1}{2}$ and $pm frac{1}{2} sqrt{3}$.



Is equality fine for accumulation points is basically what I am asking.



I also was thinking of an example with infinitely many accumulation points and wondered if the same example would cut it:



$$b_n = n cos(n) $$
Since it oscillates back and forth it comes back to every single point eventually.





As an alternative way of getting four accumulation points I could define unions of the sets $s_a= { a+ frac{1}{n}| n in mathbb{N} }$ for values $a=0, 1,2,3$ but this example feels very contrived and I do not know how to formulate this in terms of a sequence other than just listing the elements one by one in set notation: ${ frac{1}{1}, 1+frac{1}{1}, 2+frac{1}{1} dots, 1+ frac{1}{n}, 2+ frac{1}{n} dots }$










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    You have asked a question with the same title less than one hour ago, moreover without mentionning it. This is not a good practice. You should have modified the text of the initial question instead of asking a new one.
    – Jean Marie
    Nov 23 at 23:00

















up vote
-2
down vote

favorite












I was not allowed to edit the previous question because people spent their time and energy constructing an answer, therefore I have asked it again, with my initial error in formulating my answers corrected.





Is it true that this example I came up with, namely the sequence $$a_n=cosleft(frac{pi}{3} + frac{pi n}{2}right)$$
Has exactly $4$ limit points/accumulation points? What I tried to do was symmetrically pick an infinite amount of points that lie on the unit circle and all hop between four exact points $pm frac{1}{2}$ and $pm frac{1}{2} sqrt{3}$.



Is equality fine for accumulation points is basically what I am asking.



I also was thinking of an example with infinitely many accumulation points and wondered if the same example would cut it:



$$b_n = n cos(n) $$
Since it oscillates back and forth it comes back to every single point eventually.





As an alternative way of getting four accumulation points I could define unions of the sets $s_a= { a+ frac{1}{n}| n in mathbb{N} }$ for values $a=0, 1,2,3$ but this example feels very contrived and I do not know how to formulate this in terms of a sequence other than just listing the elements one by one in set notation: ${ frac{1}{1}, 1+frac{1}{1}, 2+frac{1}{1} dots, 1+ frac{1}{n}, 2+ frac{1}{n} dots }$










share|cite|improve this question




















  • 1




    You have asked a question with the same title less than one hour ago, moreover without mentionning it. This is not a good practice. You should have modified the text of the initial question instead of asking a new one.
    – Jean Marie
    Nov 23 at 23:00















up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











I was not allowed to edit the previous question because people spent their time and energy constructing an answer, therefore I have asked it again, with my initial error in formulating my answers corrected.





Is it true that this example I came up with, namely the sequence $$a_n=cosleft(frac{pi}{3} + frac{pi n}{2}right)$$
Has exactly $4$ limit points/accumulation points? What I tried to do was symmetrically pick an infinite amount of points that lie on the unit circle and all hop between four exact points $pm frac{1}{2}$ and $pm frac{1}{2} sqrt{3}$.



Is equality fine for accumulation points is basically what I am asking.



I also was thinking of an example with infinitely many accumulation points and wondered if the same example would cut it:



$$b_n = n cos(n) $$
Since it oscillates back and forth it comes back to every single point eventually.





As an alternative way of getting four accumulation points I could define unions of the sets $s_a= { a+ frac{1}{n}| n in mathbb{N} }$ for values $a=0, 1,2,3$ but this example feels very contrived and I do not know how to formulate this in terms of a sequence other than just listing the elements one by one in set notation: ${ frac{1}{1}, 1+frac{1}{1}, 2+frac{1}{1} dots, 1+ frac{1}{n}, 2+ frac{1}{n} dots }$










share|cite|improve this question















I was not allowed to edit the previous question because people spent their time and energy constructing an answer, therefore I have asked it again, with my initial error in formulating my answers corrected.





Is it true that this example I came up with, namely the sequence $$a_n=cosleft(frac{pi}{3} + frac{pi n}{2}right)$$
Has exactly $4$ limit points/accumulation points? What I tried to do was symmetrically pick an infinite amount of points that lie on the unit circle and all hop between four exact points $pm frac{1}{2}$ and $pm frac{1}{2} sqrt{3}$.



Is equality fine for accumulation points is basically what I am asking.



I also was thinking of an example with infinitely many accumulation points and wondered if the same example would cut it:



$$b_n = n cos(n) $$
Since it oscillates back and forth it comes back to every single point eventually.





As an alternative way of getting four accumulation points I could define unions of the sets $s_a= { a+ frac{1}{n}| n in mathbb{N} }$ for values $a=0, 1,2,3$ but this example feels very contrived and I do not know how to formulate this in terms of a sequence other than just listing the elements one by one in set notation: ${ frac{1}{1}, 1+frac{1}{1}, 2+frac{1}{1} dots, 1+ frac{1}{n}, 2+ frac{1}{n} dots }$







real-analysis






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edited Nov 26 at 18:12

























asked Nov 23 at 21:59









WesleyGroupshaveFeelingsToo

1,115321




1,115321








  • 1




    You have asked a question with the same title less than one hour ago, moreover without mentionning it. This is not a good practice. You should have modified the text of the initial question instead of asking a new one.
    – Jean Marie
    Nov 23 at 23:00
















  • 1




    You have asked a question with the same title less than one hour ago, moreover without mentionning it. This is not a good practice. You should have modified the text of the initial question instead of asking a new one.
    – Jean Marie
    Nov 23 at 23:00










1




1




You have asked a question with the same title less than one hour ago, moreover without mentionning it. This is not a good practice. You should have modified the text of the initial question instead of asking a new one.
– Jean Marie
Nov 23 at 23:00






You have asked a question with the same title less than one hour ago, moreover without mentionning it. This is not a good practice. You should have modified the text of the initial question instead of asking a new one.
– Jean Marie
Nov 23 at 23:00












1 Answer
1






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up vote
2
down vote



accepted










We have that




  • $n=1 implies a_1=cosleft(frac{pi}{3} + frac{pi }{2}right)=-frac{sqrt 3}2$

  • $n=2 implies a_2=cosleft(frac{pi}{3} + piright)=-frac12$

  • $n=3 implies a_3=cosleft(frac{pi}{3} + frac{3pi }{2}right)=frac{sqrt 3}2$

  • $n=4 implies a_4=cosleft(frac{pi}{3} + 2piright)=frac12$

  • $n=5 implies a_5=a_1$


For the second question, yes of curse $b_n$ oscillates diverging assuming values $in mathbb{R}$ and $cos n$ is dense in $[-1,1]$. From that to conlcude that $ncos n$ is dense on the real line is not so trivial, see the related




  • Is $n sin n$ dense on the real line?

  • Does this sequence $a(n) = frac{1}{n^3sin(n)}$ converge

  • Is it true that $varliminf_{n rightarrow +infty} |n sin n| = 0$

  • Convergence of $sum(n^3sin^2n)^{-1}$






share|cite|improve this answer























  • Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:14












  • @WesleyGroupshaveFeelingsToo Yes, refer to the following OP
    – gimusi
    Nov 23 at 22:17










  • I mean one sort of needs to prove that you will never start repeating a finite set of points.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:18










  • ah, very nice, thank you.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:19











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










We have that




  • $n=1 implies a_1=cosleft(frac{pi}{3} + frac{pi }{2}right)=-frac{sqrt 3}2$

  • $n=2 implies a_2=cosleft(frac{pi}{3} + piright)=-frac12$

  • $n=3 implies a_3=cosleft(frac{pi}{3} + frac{3pi }{2}right)=frac{sqrt 3}2$

  • $n=4 implies a_4=cosleft(frac{pi}{3} + 2piright)=frac12$

  • $n=5 implies a_5=a_1$


For the second question, yes of curse $b_n$ oscillates diverging assuming values $in mathbb{R}$ and $cos n$ is dense in $[-1,1]$. From that to conlcude that $ncos n$ is dense on the real line is not so trivial, see the related




  • Is $n sin n$ dense on the real line?

  • Does this sequence $a(n) = frac{1}{n^3sin(n)}$ converge

  • Is it true that $varliminf_{n rightarrow +infty} |n sin n| = 0$

  • Convergence of $sum(n^3sin^2n)^{-1}$






share|cite|improve this answer























  • Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:14












  • @WesleyGroupshaveFeelingsToo Yes, refer to the following OP
    – gimusi
    Nov 23 at 22:17










  • I mean one sort of needs to prove that you will never start repeating a finite set of points.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:18










  • ah, very nice, thank you.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:19















up vote
2
down vote



accepted










We have that




  • $n=1 implies a_1=cosleft(frac{pi}{3} + frac{pi }{2}right)=-frac{sqrt 3}2$

  • $n=2 implies a_2=cosleft(frac{pi}{3} + piright)=-frac12$

  • $n=3 implies a_3=cosleft(frac{pi}{3} + frac{3pi }{2}right)=frac{sqrt 3}2$

  • $n=4 implies a_4=cosleft(frac{pi}{3} + 2piright)=frac12$

  • $n=5 implies a_5=a_1$


For the second question, yes of curse $b_n$ oscillates diverging assuming values $in mathbb{R}$ and $cos n$ is dense in $[-1,1]$. From that to conlcude that $ncos n$ is dense on the real line is not so trivial, see the related




  • Is $n sin n$ dense on the real line?

  • Does this sequence $a(n) = frac{1}{n^3sin(n)}$ converge

  • Is it true that $varliminf_{n rightarrow +infty} |n sin n| = 0$

  • Convergence of $sum(n^3sin^2n)^{-1}$






share|cite|improve this answer























  • Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:14












  • @WesleyGroupshaveFeelingsToo Yes, refer to the following OP
    – gimusi
    Nov 23 at 22:17










  • I mean one sort of needs to prove that you will never start repeating a finite set of points.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:18










  • ah, very nice, thank you.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:19













up vote
2
down vote



accepted







up vote
2
down vote



accepted






We have that




  • $n=1 implies a_1=cosleft(frac{pi}{3} + frac{pi }{2}right)=-frac{sqrt 3}2$

  • $n=2 implies a_2=cosleft(frac{pi}{3} + piright)=-frac12$

  • $n=3 implies a_3=cosleft(frac{pi}{3} + frac{3pi }{2}right)=frac{sqrt 3}2$

  • $n=4 implies a_4=cosleft(frac{pi}{3} + 2piright)=frac12$

  • $n=5 implies a_5=a_1$


For the second question, yes of curse $b_n$ oscillates diverging assuming values $in mathbb{R}$ and $cos n$ is dense in $[-1,1]$. From that to conlcude that $ncos n$ is dense on the real line is not so trivial, see the related




  • Is $n sin n$ dense on the real line?

  • Does this sequence $a(n) = frac{1}{n^3sin(n)}$ converge

  • Is it true that $varliminf_{n rightarrow +infty} |n sin n| = 0$

  • Convergence of $sum(n^3sin^2n)^{-1}$






share|cite|improve this answer














We have that




  • $n=1 implies a_1=cosleft(frac{pi}{3} + frac{pi }{2}right)=-frac{sqrt 3}2$

  • $n=2 implies a_2=cosleft(frac{pi}{3} + piright)=-frac12$

  • $n=3 implies a_3=cosleft(frac{pi}{3} + frac{3pi }{2}right)=frac{sqrt 3}2$

  • $n=4 implies a_4=cosleft(frac{pi}{3} + 2piright)=frac12$

  • $n=5 implies a_5=a_1$


For the second question, yes of curse $b_n$ oscillates diverging assuming values $in mathbb{R}$ and $cos n$ is dense in $[-1,1]$. From that to conlcude that $ncos n$ is dense on the real line is not so trivial, see the related




  • Is $n sin n$ dense on the real line?

  • Does this sequence $a(n) = frac{1}{n^3sin(n)}$ converge

  • Is it true that $varliminf_{n rightarrow +infty} |n sin n| = 0$

  • Convergence of $sum(n^3sin^2n)^{-1}$







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Nov 23 at 22:36

























answered Nov 23 at 22:04









gimusi

88.8k74394




88.8k74394












  • Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:14












  • @WesleyGroupshaveFeelingsToo Yes, refer to the following OP
    – gimusi
    Nov 23 at 22:17










  • I mean one sort of needs to prove that you will never start repeating a finite set of points.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:18










  • ah, very nice, thank you.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:19


















  • Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:14












  • @WesleyGroupshaveFeelingsToo Yes, refer to the following OP
    – gimusi
    Nov 23 at 22:17










  • I mean one sort of needs to prove that you will never start repeating a finite set of points.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:18










  • ah, very nice, thank you.
    – WesleyGroupshaveFeelingsToo
    Nov 23 at 22:19
















Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
– WesleyGroupshaveFeelingsToo
Nov 23 at 22:14






Could I simply take $cos(n)$ and that would give me an infinite amount of points because of density?
– WesleyGroupshaveFeelingsToo
Nov 23 at 22:14














@WesleyGroupshaveFeelingsToo Yes, refer to the following OP
– gimusi
Nov 23 at 22:17




@WesleyGroupshaveFeelingsToo Yes, refer to the following OP
– gimusi
Nov 23 at 22:17












I mean one sort of needs to prove that you will never start repeating a finite set of points.
– WesleyGroupshaveFeelingsToo
Nov 23 at 22:18




I mean one sort of needs to prove that you will never start repeating a finite set of points.
– WesleyGroupshaveFeelingsToo
Nov 23 at 22:18












ah, very nice, thank you.
– WesleyGroupshaveFeelingsToo
Nov 23 at 22:19




ah, very nice, thank you.
– WesleyGroupshaveFeelingsToo
Nov 23 at 22:19


















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