evaluate: given $9<x<10$, if we take precision of $10^{-8}$ , will $x^2$ have precision of $10^{-7}$?...
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i want to solve this problem: find if a given number $9 < x < 10$ with some precision of $8$ numbers after the floating point.
the problem is: if we take the square of $x$, will the result have precision of $10^{-7}$?
I tried solving this using $epsilon> 0$ and got a false result.
thank you.
calculus
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closed as off-topic by amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF Dec 8 '18 at 11:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
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$begingroup$
i want to solve this problem: find if a given number $9 < x < 10$ with some precision of $8$ numbers after the floating point.
the problem is: if we take the square of $x$, will the result have precision of $10^{-7}$?
I tried solving this using $epsilon> 0$ and got a false result.
thank you.
calculus
$endgroup$
closed as off-topic by amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF Dec 8 '18 at 11:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF
If this question can be reworded to fit the rules in the help center, please edit the question.
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Could you please add some detail more on your derivation? Thanks
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– gimusi
Dec 7 '18 at 15:49
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$begingroup$
i want to solve this problem: find if a given number $9 < x < 10$ with some precision of $8$ numbers after the floating point.
the problem is: if we take the square of $x$, will the result have precision of $10^{-7}$?
I tried solving this using $epsilon> 0$ and got a false result.
thank you.
calculus
$endgroup$
i want to solve this problem: find if a given number $9 < x < 10$ with some precision of $8$ numbers after the floating point.
the problem is: if we take the square of $x$, will the result have precision of $10^{-7}$?
I tried solving this using $epsilon> 0$ and got a false result.
thank you.
calculus
calculus
edited Dec 7 '18 at 15:47
gimusi
1
1
asked Dec 7 '18 at 15:40
YaelYael
12
12
closed as off-topic by amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF Dec 8 '18 at 11:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF Dec 8 '18 at 11:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Jyrki Lahtonen, Nosrati, Saad, DRF
If this question can be reworded to fit the rules in the help center, please edit the question.
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Could you please add some detail more on your derivation? Thanks
$endgroup$
– gimusi
Dec 7 '18 at 15:49
add a comment |
$begingroup$
Could you please add some detail more on your derivation? Thanks
$endgroup$
– gimusi
Dec 7 '18 at 15:49
$begingroup$
Could you please add some detail more on your derivation? Thanks
$endgroup$
– gimusi
Dec 7 '18 at 15:49
$begingroup$
Could you please add some detail more on your derivation? Thanks
$endgroup$
– gimusi
Dec 7 '18 at 15:49
add a comment |
1 Answer
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HINT
Let consider
$$x=x_0+Delta x implies x^2=x_0^2+2x_0Delta x +Delta x^2$$
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
HINT
Let consider
$$x=x_0+Delta x implies x^2=x_0^2+2x_0Delta x +Delta x^2$$
$endgroup$
add a comment |
$begingroup$
HINT
Let consider
$$x=x_0+Delta x implies x^2=x_0^2+2x_0Delta x +Delta x^2$$
$endgroup$
add a comment |
$begingroup$
HINT
Let consider
$$x=x_0+Delta x implies x^2=x_0^2+2x_0Delta x +Delta x^2$$
$endgroup$
HINT
Let consider
$$x=x_0+Delta x implies x^2=x_0^2+2x_0Delta x +Delta x^2$$
answered Dec 7 '18 at 15:43
gimusigimusi
1
1
add a comment |
add a comment |
$begingroup$
Could you please add some detail more on your derivation? Thanks
$endgroup$
– gimusi
Dec 7 '18 at 15:49