Mathematical calculation of work exercise?
So I have the following exercise:
Find the work that is necessary to pump empty the cylindrical motor oil tank, it the tank is placed up on the base. The height of the tank is 202cm, radius of the bottom is 88cm and the specific weight of the tank oil is 0.92
Take 9.8m/s^2 as the acceleration of gravity and 1000kg/m^3 as the density of the water.
I have to find
1) the weight of the motor oil (N/m^3) K=
2) indifferent integral to find the work F(x)=... +C
3) the work in joulses W=
What I have found out:
$$ V=1564288 pi cm^3 $$
calculus physics indefinite-integrals mathematical-physics
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So I have the following exercise:
Find the work that is necessary to pump empty the cylindrical motor oil tank, it the tank is placed up on the base. The height of the tank is 202cm, radius of the bottom is 88cm and the specific weight of the tank oil is 0.92
Take 9.8m/s^2 as the acceleration of gravity and 1000kg/m^3 as the density of the water.
I have to find
1) the weight of the motor oil (N/m^3) K=
2) indifferent integral to find the work F(x)=... +C
3) the work in joulses W=
What I have found out:
$$ V=1564288 pi cm^3 $$
calculus physics indefinite-integrals mathematical-physics
add a comment |
So I have the following exercise:
Find the work that is necessary to pump empty the cylindrical motor oil tank, it the tank is placed up on the base. The height of the tank is 202cm, radius of the bottom is 88cm and the specific weight of the tank oil is 0.92
Take 9.8m/s^2 as the acceleration of gravity and 1000kg/m^3 as the density of the water.
I have to find
1) the weight of the motor oil (N/m^3) K=
2) indifferent integral to find the work F(x)=... +C
3) the work in joulses W=
What I have found out:
$$ V=1564288 pi cm^3 $$
calculus physics indefinite-integrals mathematical-physics
So I have the following exercise:
Find the work that is necessary to pump empty the cylindrical motor oil tank, it the tank is placed up on the base. The height of the tank is 202cm, radius of the bottom is 88cm and the specific weight of the tank oil is 0.92
Take 9.8m/s^2 as the acceleration of gravity and 1000kg/m^3 as the density of the water.
I have to find
1) the weight of the motor oil (N/m^3) K=
2) indifferent integral to find the work F(x)=... +C
3) the work in joulses W=
What I have found out:
$$ V=1564288 pi cm^3 $$
calculus physics indefinite-integrals mathematical-physics
calculus physics indefinite-integrals mathematical-physics
edited Dec 5 '18 at 9:02
asked Dec 3 '18 at 20:28
Student123
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486
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add a comment |
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