Pythagoras theorem and ratio question
-1
$begingroup$
https://gyazo.com/66f47546602b91315cceecd66927c129
In triangle PQR, X is a point on PQ. RX is perpendicular to PQ.
Work out the ratio PX : XQ. Give your answer in its simplest form.
Answer ________ : ________
ratio
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
$endgroup$
|
show 3 more comments
-1
$begingroup$
https://gyazo.com/66f47546602b91315cceecd66927c129
In triangle PQR, X is a point on PQ. RX is perpendicular to PQ.
Work out the ratio PX : XQ. Give your answer in its simplest form.
Answer ________ : ________
ratio
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
$endgroup$
3
$begingroup$
What is the problem you are facing in the problem? Any thoughts?
$endgroup$
– Matti P.
Dec 7 '18 at 7:54
$begingroup$
It would be better if you showed your work too, including where and why you’re stuck.
$endgroup$
– KM101
Dec 7 '18 at 7:58
$begingroup$
Thank you for replying and sorry for not providing enough information. I simply don't get the question, when it says to work out the ratio of PX : XQ, I just don't get what I am supposed to do. I know what a ratio is but I am confused over what to do. Thank you for understanding
$endgroup$
– THELichCA
Dec 7 '18 at 8:08
$begingroup$
You need to use the Pythagorean Theorem to calculate the length of the sides $overline{PX}$ and $overline{XQ}$. Then, you can find the ratio of their sides by $frac{overline{PX}}{overline{XQ}}$.
$endgroup$
– KM101
Dec 7 '18 at 8:11
$begingroup$
So the ratio will simply be: "The length of PX : The length of XQ"?
$endgroup$
– THELichCA
Dec 7 '18 at 8:13
|
show 3 more comments
-1
-1
-1
$begingroup$
https://gyazo.com/66f47546602b91315cceecd66927c129
In triangle PQR, X is a point on PQ. RX is perpendicular to PQ.
Work out the ratio PX : XQ. Give your answer in its simplest form.
Answer ________ : ________
ratio
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
$endgroup$
https://gyazo.com/66f47546602b91315cceecd66927c129
In triangle PQR, X is a point on PQ. RX is perpendicular to PQ.
Work out the ratio PX : XQ. Give your answer in its simplest form.
Answer ________ : ________
ratio
ratio
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
asked Dec 7 '18 at 7:53
THELichCATHELichCA
1
1
3
$begingroup$
What is the problem you are facing in the problem? Any thoughts?
$endgroup$
– Matti P.
Dec 7 '18 at 7:54
$begingroup$
It would be better if you showed your work too, including where and why you’re stuck.
$endgroup$
– KM101
Dec 7 '18 at 7:58
$begingroup$
Thank you for replying and sorry for not providing enough information. I simply don't get the question, when it says to work out the ratio of PX : XQ, I just don't get what I am supposed to do. I know what a ratio is but I am confused over what to do. Thank you for understanding
$endgroup$
– THELichCA
Dec 7 '18 at 8:08
$begingroup$
You need to use the Pythagorean Theorem to calculate the length of the sides $overline{PX}$ and $overline{XQ}$. Then, you can find the ratio of their sides by $frac{overline{PX}}{overline{XQ}}$.
$endgroup$
– KM101
Dec 7 '18 at 8:11
$begingroup$
So the ratio will simply be: "The length of PX : The length of XQ"?
$endgroup$
– THELichCA
Dec 7 '18 at 8:13
|
show 3 more comments
3
$begingroup$
What is the problem you are facing in the problem? Any thoughts?
$endgroup$
– Matti P.
Dec 7 '18 at 7:54
$begingroup$
It would be better if you showed your work too, including where and why you’re stuck.
$endgroup$
– KM101
Dec 7 '18 at 7:58
$begingroup$
Thank you for replying and sorry for not providing enough information. I simply don't get the question, when it says to work out the ratio of PX : XQ, I just don't get what I am supposed to do. I know what a ratio is but I am confused over what to do. Thank you for understanding
$endgroup$
– THELichCA
Dec 7 '18 at 8:08
$begingroup$
You need to use the Pythagorean Theorem to calculate the length of the sides $overline{PX}$ and $overline{XQ}$. Then, you can find the ratio of their sides by $frac{overline{PX}}{overline{XQ}}$.
$endgroup$
– KM101
Dec 7 '18 at 8:11
$begingroup$
So the ratio will simply be: "The length of PX : The length of XQ"?
$endgroup$
– THELichCA
Dec 7 '18 at 8:13
3
3
$begingroup$
What is the problem you are facing in the problem? Any thoughts?
$endgroup$
– Matti P.
Dec 7 '18 at 7:54
$begingroup$
What is the problem you are facing in the problem? Any thoughts?
$endgroup$
– Matti P.
Dec 7 '18 at 7:54
$begingroup$
It would be better if you showed your work too, including where and why you’re stuck.
$endgroup$
– KM101
Dec 7 '18 at 7:58
$begingroup$
It would be better if you showed your work too, including where and why you’re stuck.
$endgroup$
– KM101
Dec 7 '18 at 7:58
$begingroup$
Thank you for replying and sorry for not providing enough information. I simply don't get the question, when it says to work out the ratio of PX : XQ, I just don't get what I am supposed to do. I know what a ratio is but I am confused over what to do. Thank you for understanding
$endgroup$
– THELichCA
Dec 7 '18 at 8:08
$begingroup$
Thank you for replying and sorry for not providing enough information. I simply don't get the question, when it says to work out the ratio of PX : XQ, I just don't get what I am supposed to do. I know what a ratio is but I am confused over what to do. Thank you for understanding
$endgroup$
– THELichCA
Dec 7 '18 at 8:08
$begingroup$
You need to use the Pythagorean Theorem to calculate the length of the sides $overline{PX}$ and $overline{XQ}$. Then, you can find the ratio of their sides by $frac{overline{PX}}{overline{XQ}}$.
$endgroup$
– KM101
Dec 7 '18 at 8:11
$begingroup$
You need to use the Pythagorean Theorem to calculate the length of the sides $overline{PX}$ and $overline{XQ}$. Then, you can find the ratio of their sides by $frac{overline{PX}}{overline{XQ}}$.
$endgroup$
– KM101
Dec 7 '18 at 8:11
$begingroup$
So the ratio will simply be: "The length of PX : The length of XQ"?
$endgroup$
– THELichCA
Dec 7 '18 at 8:13
$begingroup$
So the ratio will simply be: "The length of PX : The length of XQ"?
$endgroup$
– THELichCA
Dec 7 '18 at 8:13
|
show 3 more comments
1 Answer
1
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0
$begingroup$
Note that $triangle PXR, triangle QXR$ are right angled at $X$. Use the pythagorean theorem in both triangles:
$PX^2+RX^2=PX^2+16^2=PR^2=20^2implies PX=sqrt{20^2-16^2}$
$QX^2+RX^2=QX^2+16^2=QR^2=34^2implies QX=sqrt{34^2-16^2}$
Can you now work out the ratio $PX:QX=frac{PX}{QX}$ in simplest terms?
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
$endgroup$
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
add a comment |
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$begingroup$
Note that $triangle PXR, triangle QXR$ are right angled at $X$. Use the pythagorean theorem in both triangles:
$PX^2+RX^2=PX^2+16^2=PR^2=20^2implies PX=sqrt{20^2-16^2}$
$QX^2+RX^2=QX^2+16^2=QR^2=34^2implies QX=sqrt{34^2-16^2}$
Can you now work out the ratio $PX:QX=frac{PX}{QX}$ in simplest terms?
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
$endgroup$
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
add a comment |
0
$begingroup$
Note that $triangle PXR, triangle QXR$ are right angled at $X$. Use the pythagorean theorem in both triangles:
$PX^2+RX^2=PX^2+16^2=PR^2=20^2implies PX=sqrt{20^2-16^2}$
$QX^2+RX^2=QX^2+16^2=QR^2=34^2implies QX=sqrt{34^2-16^2}$
Can you now work out the ratio $PX:QX=frac{PX}{QX}$ in simplest terms?
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
$endgroup$
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
add a comment |
0
0
0
$begingroup$
Note that $triangle PXR, triangle QXR$ are right angled at $X$. Use the pythagorean theorem in both triangles:
$PX^2+RX^2=PX^2+16^2=PR^2=20^2implies PX=sqrt{20^2-16^2}$
$QX^2+RX^2=QX^2+16^2=QR^2=34^2implies QX=sqrt{34^2-16^2}$
Can you now work out the ratio $PX:QX=frac{PX}{QX}$ in simplest terms?
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
$endgroup$
Note that $triangle PXR, triangle QXR$ are right angled at $X$. Use the pythagorean theorem in both triangles:
$PX^2+RX^2=PX^2+16^2=PR^2=20^2implies PX=sqrt{20^2-16^2}$
$QX^2+RX^2=QX^2+16^2=QR^2=34^2implies QX=sqrt{34^2-16^2}$
Can you now work out the ratio $PX:QX=frac{PX}{QX}$ in simplest terms?
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
answered Dec 7 '18 at 8:17
Shubham JohriShubham Johri
4,689717
4,689717
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
add a comment |
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
The ratio would be 12:30 = 6:15 = 2:3
$endgroup$
– THELichCA
Dec 7 '18 at 8:19
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
Yes, that's correct. $12:30::2:5$
$endgroup$
– Shubham Johri
Dec 7 '18 at 8:20
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
$begingroup$
You simplified the ratio incorrectly. $6:15 implies 2:5$. Other than that, it’s correct.
$endgroup$
– KM101
Dec 7 '18 at 8:22
add a comment |
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3
$begingroup$
What is the problem you are facing in the problem? Any thoughts?
$endgroup$
– Matti P.
Dec 7 '18 at 7:54
$begingroup$
It would be better if you showed your work too, including where and why you’re stuck.
$endgroup$
– KM101
Dec 7 '18 at 7:58
$begingroup$
Thank you for replying and sorry for not providing enough information. I simply don't get the question, when it says to work out the ratio of PX : XQ, I just don't get what I am supposed to do. I know what a ratio is but I am confused over what to do. Thank you for understanding
$endgroup$
– THELichCA
Dec 7 '18 at 8:08
$begingroup$
You need to use the Pythagorean Theorem to calculate the length of the sides $overline{PX}$ and $overline{XQ}$. Then, you can find the ratio of their sides by $frac{overline{PX}}{overline{XQ}}$.
$endgroup$
– KM101
Dec 7 '18 at 8:11
$begingroup$
So the ratio will simply be: "The length of PX : The length of XQ"?
$endgroup$
– THELichCA
Dec 7 '18 at 8:13